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#45 | |
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Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
22·5·72·11 Posts |
Quote:
Try a thought experiment: forget about the galaxies for a moment and think only of a couple of observers on a trajectory such that they only just miss each other, together with a third observer right next to the point of closest approach. The third observer first sees the other two approaching at 0.6c and then, after they pass, receding at 0.6c in opposite directions. What do the other two see? They first see their opposite number approaching at less than the speed of light. For a brief instant, light from one travels to the other at right angles to the direction of flight. Then they recede from each other at less than the speed of light. Paul |
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#46 | |
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Aug 2002
Buenos Aires, Argentina
2·683 Posts |
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Without going that far, the people who went to the Moon "gained" about 1/10000th of a second (considering that you need five days to reach the Moon, it is not too much). |
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#47 | |
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May 2003
3·7·11 Posts |
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This is all derivable just using high-school maths (in fact, maths that a bright 10 year old could grasp) as long as you're prepared to accept a few assumptions. Basically, assume the speed of light is constant, and that distance is measured by bouncing light off the object, measuring how long the reflection takes to return, and scaling that by the known constant speed of light. In this particular example, draw the space/time cone for the inertial observer, the two lines with gradients +/-0.6 (OK, I've got the axes oriented unconventially) corresponding to the two 'moving' objects. At an arbitrary point in time, send a light beam (line with gradient +/-1) from one object to the other, and when it arrives, bounce it back (line with gradient -/+1). Notice that the originator does indeed get his response. Conclusion - they are not receding from each other at a superluminal speed. Get some graph paper, and draw it - it's very enlightening. |
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#48 |
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Aug 2002
Termonfeckin, IE
53148 Posts |
I think I misunderstood what the OP was saying. I understand how relativistic mechanics will show that the galaxies recede at 0.88c in each others frames of reference.
I thought it had to with the stretching of space-time. There are galaxies that are receding from us at faster than the speed of light. No light from them will ever reach us. Right? |
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#49 | |
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Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
250348 Posts |
Quote:
Paul |
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#50 |
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Aug 2003
Snicker, AL
7·137 Posts |
Stipulating that FTL galaxies do exist, this would predict that we should be able to detect galaxies receding from us at a broad range of fractions of C. This could only occur as a result of distortion from space time expansion. Why do we not detect such a range especially approaching C? The local group of galaxies is essentially moving in tandem. More distant galaxies should progressively be moving away from us at faster and faster speeds up to and including the point at which they become invisible because they are receding from us at the speed of light.
This should provoke a few comments! We're pretty far off topic though. Fusion |
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#51 | |
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"William"
May 2003
New Haven
2·7·132 Posts |
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#52 | |
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Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
22×5×72×11 Posts |
Quote:
BTW, what do you mean by "now"? Simultaneity of spatially separated events is not well defined in relativity. Paul |
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#53 | |
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Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
22·5·72·11 Posts |
Quote:
Paul |
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#54 | |
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"William"
May 2003
New Haven
2·7·132 Posts |
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I knew "now" was problematical - that's why I quoted it. |
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#55 | |
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"Richard B. Woods"
Aug 2002
Wisconsin USA
170148 Posts |
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See http://hyperphysics.phy-astr.gsu.edu...o/redshf2.html for the calculation formulas. See http://www.journals.uchicago.edu/ApJ...883408314Guest for a May 2002 article about a z=6.28 quasar. Last fiddled with by cheesehead on 2005-12-22 at 06:52 |
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