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Old 2012-06-08, 16:52   #45
R. Gerbicz
 
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86=((1/.\overbar{1})!!!!-1-1)!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
92=11!!!!!!!+((1/sqrt(.\overrbar{1}))!)!!
97=(((1/sqrt(.\overrbar{1}))!)!!)!!!!+1*1 (idea of 97=(6*4*2)*2+1)

Last fiddled with by R. Gerbicz on 2012-06-08 at 16:58
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Old 2012-06-08, 17:01   #46
alpertron
 
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We will need to write in a post the complete table from 0 to 100 along with their score so we can start making better solutions.
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Old 2012-06-08, 18:57   #47
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Quote:
Originally Posted by alpertron View Post
We will need to write in a post the complete table from 0 to 100 along with their score so we can start making better solutions.
I can't find a few ( figured one of the two out) but:

Quote:
0 = 11 - 11
1 = 11 / 11
2 = 1/1 + 1/1
3 = 1 * 1 + 1 + 1
4 = 1 + 1 + 1 + 1
5 = 1*1/(.1+.1)
6 = (1 + 1 + 1 * 1)!
7 = (1 + 1 + 1)! + 1
8 = 1/.1 - 1 - 1
9 = 1/.1-1*1
10 = 11/1.1
11 = 11+1-1
12 = 11+1*1
13 = 11+1+1
14 = (1/(.1 + .1))!! -1
15 = (1/(.1 + .1))!! * 1
16 = (1/(.1 + .1))!! + 1
17 = ((1 + 1 + 1)!)!!! - 1
18 = ((1 + 1 + 1)!)!!! * 1
19 = ((1 + 1 + 1)!)!!! + 1
20 = 1/.1+1/.1
21 = (1+1+.1)/.1
22 = 11+11
23 = (1+sqrt(1/.overbar{1}))-1
24 = (1+1+1+1)!
25 = (1+sqrt(1/.overbar{1}))+1
26 = 1/(.\overbar{1}*sqrt(.\overbar{1}))-1
27 = 1/(.\overbar{1}*sqrt(.\overbar{1})) *1
28 = 1/(.\overbar{1}*sqrt(.\overbar{1}))+1
29 = 1/(.1*sqrt(.\overbar{1}))-1
30 = (1+1+1)/.1
31 = 1/(.1*sqrt(.\overbar{1}))+1
32 = 11/sqrt(.\overbar{1})-1
33 = 11/sqrt(.\overbar{1})*1
34 = 11/sqrt(.\overbar{1})+1
35 = (1/.\overbar{1})!!*.\overbar{1}*sqrt(.\overbar{1})
36 = (11+1)/sqrt(.\overbar{1})
37 = 111*sqrt(.\overbar{1})
38 = (((1/sqrt(.\overrbar{1}))!)!)!-1/.1
39 = (((1/sqrt(.\overrbar{1}))!)!)!-1/.\overbar{1}
40 = (1/(.1+.1))! * sqrt(.\overbar{1})
41 = 11!!!!!!!-1/.\sqrt(overbar{1})
42 = 11!!!!!!!-1-1
43 = 11!!!!!!!*1-1
44 = (1/.\overbar{1})!!!!-1/1
45 = 1/(.1+.1)/.\overbar{1}
46 = (((1/sqrt(.\overrbar{1}))!)!)!-1-1
47 = (((1/sqrt(.\overrbar{1}))!)!)!-1*1
48 = (((1/sqrt(.\overrbar{1}))!)!)!*1*1
49 = (((1/sqrt(.\overrbar{1}))!)!)!+1*1
50 = (((1/sqrt(.\overrbar{1}))!)!)!+1+1
51 = (((1/sqrt(.\overrbar{1}))!)!)!+1/sqrt{.\overbar{1}}
52 = 11!!!!!!-1/.\sqrt(overbar{1})
53 = (1/sqrt(.\overbar{1}))!/.\overbar{1}-1
54 = (1+1)/.\overbar{1}/sqrt(.\overbar{1})
55 = 11/(.1+.1)
56 = 11!!!!!!*1+1
57 = (((1/sqrt(.\overrbar{1}))!)!)!+(1/.\overbar{1})
58 = 11!!!!!!+1/.\sqrt(overbar{1})
59 = (1/sqrt(.\overrbar{1}))!/.1-1
60 = (1+1+1)!/.1
61 = (1/sqrt(.\overrbar{1}))!/.1+1
62 = 11!!!!!!!+(1/.\overrbar{1})!!!!!!!
63 = 11!!!!!-1/.\sqrt(overbar{1})
64 = (1+1)^((1/sqrt(.\overrbar{1}))!)
65 = 11!!!!!*1-1
66 = 11 * (1/sqrt(.\overrbar{1}))!
67 = 11!!!!!*1+1
67 = 11!!!!!+1+1
69 = 11!!!!!+1/.\sqrt(overbar{1})
70=((1/(.1 + .1))!! -1)!!!!!!!!!
71 = ((1/sqrt(.\overrbar{1}))!)! * .1 - 1
72 = ((1/sqrt(.\overrbar{1}))!)! * .1 * 1
73 = ((1/sqrt(.\overrbar{1}))!)! * .1 + 1
74 = 11!!!!!!!+(1/.1)!!!!!!!
75 = 11!!!!!+1/.\overbar{1}
76 = 11!!!!*sqrt(.\overbar{1})-1
77 = 11!!!!*sqrt(.\overbar{1})*1
78 = 11!!!!*sqrt(.\overbar{1})+1
79 = ((1/sqrt(.\overrbar{1}))!)! * .\overrbar{1} -1
80 = 1/(.\overbar{1}*.\overbar{1})-1
81 = 1/(.\overbar{1}*.\overbar{1})*1
82 = 1/(.\overbar{1}*.\overbar{1})+1
83 = 11!!!!!!!!+(1/.1)!!!!! = 11*3+10*5
84 = 11!!!!!!!+(1/.1)!!!!!! = 11*4+10*4
85 = (1/.1)!!!!!!+(1/.\overrbar{1})!!!! = 10*4+9*5
86 = (1/.1)!!!!!+(1/.\overrbar{1})!!!!! = 10*5+9*4
87 = 11!!!*.1-1
88 = 11!!!*.1*1
89 = 1/.1/.\overbar{1}-1
90 = 1/.1/.\overbar{1}*1
91 = 1/.1/.\overbar{1}+1
92=11!!!!!!!+((1/sqrt(.\overrbar{1}))!)!!
93 = 11!!!!!+(1/.\overrbar{1})!!!!!! = 11*6+9*3
94 = 11!!!!!!!+(1/.1)!!!!! = 11*4+10*5
95 = 11!!!!!!+(1/.1)!!!!!! = 11*5+10*4
96 = (((1/sqrt(.\overrbar{1}))!)!)! *(1+1)
97=(((1/sqrt(.\overrbar{1}))!)!!)!!!!+1*1 (idea of 97=(6*4*2)*2+1)
98 = 11/.\overbar{1}-1
99 = 1/.1/.1-1
100 = 11/.11
is what I get. oops forgot the points

Last fiddled with by science_man_88 on 2012-06-08 at 19:55 Reason: thank you R. Gerbicz
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Old 2012-06-08, 19:07   #48
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Here it is the missing:

70=((1/.\overbar{1})!!*.\overbar{1}*sqrt(.\overbar{1}))!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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Old 2012-06-08, 19:10   #49
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Quote:
Originally Posted by R. Gerbicz View Post
Here it is the missing:

70=((1/.\overbar{1})!!*.\overbar{1}*sqrt(.\overbar{1}))!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
thank you for helping fill it in.
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Old 2012-06-08, 19:20   #50
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100 = 11 / .11 is a better solution according to the score table.
37 = 111*sqrt(.\overbar{1}) is also a better solution.
70 = ((1/(.1 + .1))!! -1)!!!!!!!!! = 14*5

Last fiddled with by alpertron on 2012-06-08 at 19:53
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Old 2012-06-08, 19:50   #51
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Quote:
Originally Posted by alpertron View Post
100 = 11 / .11 is a better solution according to the score table.
37 = 111*sqrt(.\overbar{1}) is also a better solution.
18 = ((1 + 1 + 1)!)!!! * 1 -> 10015 points by my math ?
18 = 1/(.\overbar{1}/(1+1)) -> 1005.5 ?

Last fiddled with by science_man_88 on 2012-06-08 at 19:51
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Old 2012-06-08, 20:04   #52
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Quote:
Originally Posted by science_man_88 View Post
18 = ((1 + 1 + 1)!)!!! * 1 -> 10015 points by my math ?
18 = 1/(.\overbar{1}/(1+1)) -> 1005.5 ?
I think we could use factorial = 10 points because it is a standard operation, multiple factorials = 100 points*number of consecutive !, and overbar 100 points. So overbar would be better than multiple factorials but much worse than standard factorial.

Last fiddled with by alpertron on 2012-06-08 at 20:05
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Old 2012-06-08, 20:14   #53
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Quote:
Originally Posted by alpertron View Post
I think we could use factorial = 10 points because it is a standard operation, multiple factorials = 100 points*number of consecutive !, and overbar 100 points. So overbar would be better than multiple factorials but much worse than standard factorial.
okay by that 18 right now is 315 points using 100*3 still a lot of possible moves I think.

Last fiddled with by science_man_88 on 2012-06-08 at 20:15
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Old 2012-06-08, 22:30   #54
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Quote:
Originally Posted by science_man_88 View Post
okay by that 18 right now is 315 points using 100*3 still a lot of possible moves I think.
I get:
18 = ((1 + 1 + 1)!)!!! * 1 -> 315 points
18 = 1/.\overbar{1}*(1+1) -> 103.5 points

Maybe you can use decimal dot -> 1 point, concatenation -> 0 points, other operations in group 1 -> 2 points. In this way all results will have an integral number of points. In this case you would have 320 points vs. 107 points.

Last fiddled with by alpertron on 2012-06-08 at 22:35
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Old 2012-06-09, 00:15   #55
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Quote:
Originally Posted by alpertron View Post
18 = 1/.\overbar{1}*(1+1) -> 103.5 points
104.5 ? 1 decimal point -> .5
4 class one operators -> 4
over-bar -> class 3 or 4 from earlier comments if class 3->100 ( not 1000 like I originally must have done) if class 4->1000
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