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#45 |
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"Robert Gerbicz"
Oct 2005
Hungary
2·743 Posts |
86=((1/.\overbar{1})!!!!-1-1)!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
92=11!!!!!!!+((1/sqrt(.\overrbar{1}))!)!! 97=(((1/sqrt(.\overrbar{1}))!)!!)!!!!+1*1 (idea of 97=(6*4*2)*2+1) Last fiddled with by R. Gerbicz on 2012-06-08 at 16:58 |
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#46 |
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Aug 2002
Buenos Aires, Argentina
2·683 Posts |
We will need to write in a post the complete table from 0 to 100 along with their score so we can start making better solutions.
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#47 | ||
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"Forget I exist"
Jul 2009
Dumbassville
26×131 Posts |
Quote:
Quote:
Last fiddled with by science_man_88 on 2012-06-08 at 19:55 Reason: thank you R. Gerbicz |
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#48 |
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"Robert Gerbicz"
Oct 2005
Hungary
2·743 Posts |
Here it is the missing:
70=((1/.\overbar{1})!!*.\overbar{1}*sqrt(.\overbar{1}))!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! |
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#49 |
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"Forget I exist"
Jul 2009
Dumbassville
20C016 Posts |
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#50 |
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Aug 2002
Buenos Aires, Argentina
2·683 Posts |
100 = 11 / .11 is a better solution according to the score table.
37 = 111*sqrt(.\overbar{1}) is also a better solution. 70 = ((1/(.1 + .1))!! -1)!!!!!!!!! = 14*5 Last fiddled with by alpertron on 2012-06-08 at 19:53 |
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#51 | |
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"Forget I exist"
Jul 2009
Dumbassville
26·131 Posts |
Quote:
18 = 1/(.\overbar{1}/(1+1)) -> 1005.5 ? Last fiddled with by science_man_88 on 2012-06-08 at 19:51 |
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#52 |
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Aug 2002
Buenos Aires, Argentina
2×683 Posts |
I think we could use factorial = 10 points because it is a standard operation, multiple factorials = 100 points*number of consecutive !, and overbar 100 points. So overbar would be better than multiple factorials but much worse than standard factorial.
Last fiddled with by alpertron on 2012-06-08 at 20:05 |
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#53 |
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"Forget I exist"
Jul 2009
Dumbassville
26·131 Posts |
okay by that 18 right now is 315 points using 100*3 still a lot of possible moves I think.
Last fiddled with by science_man_88 on 2012-06-08 at 20:15 |
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#54 | |
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Aug 2002
Buenos Aires, Argentina
2·683 Posts |
Quote:
18 = ((1 + 1 + 1)!)!!! * 1 -> 315 points 18 = 1/.\overbar{1}*(1+1) -> 103.5 points Maybe you can use decimal dot -> 1 point, concatenation -> 0 points, other operations in group 1 -> 2 points. In this way all results will have an integral number of points. In this case you would have 320 points vs. 107 points. Last fiddled with by alpertron on 2012-06-08 at 22:35 |
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#55 |
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"Forget I exist"
Jul 2009
Dumbassville
203008 Posts |
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