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Old 2007-08-13, 12:53   #1
Cruelty
 
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Default RES64: PRP vs. LLR

I'm pretty sure I read about it on this forum some time ago, but can't find it right now: are residues from PRP and LLR compatible? e.g. should I get the same RES64 after testing the same number with both programs?
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Old 2007-08-13, 13:24   #2
axn
 
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For numbers of the form k*2^n+1, LLR performs a Proth test. For k*2^n-1, it performs a LLR test. For others it performs a PRP test (I don't know about the new Gaussian Mersenne norm thingie ).

So you'll see the LLR program produce three types of RES64:- Proth RES64, LLR RES64 and plain RES64. It is the last that would be compatible with RES64 produced by PRP.

I think the short answer is: NO
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Old 2007-08-13, 14:48   #3
Cruelty
 
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OK, so for the k*2^n-1, LLR RES64 <> RES64.
Thanks for the answer
I guess I could just LLR manual
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