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View Poll Results: Estimate number of spam emails, in thousands.
Less than 60 0 0%
60 to 69 1 6.67%
70 to 79 2 13.33%
80 to 99 5 33.33%
More than 100 7 46.67%
Voters: 15. You may not vote on this poll

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Old 2007-06-22, 12:10   #1
lazy
 

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Predict number of digits in smaller factor of 2^1^0^6^1-1

My prediction: 70 to 79

Last fiddled with by lazy on 2007-06-22 at 12:47
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Old 2007-06-22, 12:37   #2
Xyzzy
 
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"Mike"
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Quote:
Predict number of digits in 2^1^0^6^1-1
$ echo '2^1061-1' | bc | tr -d '\\\n' | wc -c
320


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Old 2007-06-22, 13:26   #3
VolMike
 
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Quote:
Posts: ∞
Join Date: Aug 2002

http://mersenneforum.org/images/icons/icon1.gif
Quote:
Predict number of digits in http://mersenneforum.org/cgi-bin/mim...%5E0%5E6%5E1-1
$ echo '2^1061-1' | bc | tr -d '\\\n' | wc -c
320
This number is composite
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Old 2007-06-25, 00:21   #4
Xyzzy
 
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Quote:
This number is composite
Of course it is. But, 21061-1 is always going to be:

Code:
24707306311927565716857342128774085333197833223161879682238935306082\
80512304630699364750777605433648622889134085898582902707626188791424\
27816178466724534313869039824556355421587484018239859883229052450779\
38567513252198179128990807936780194781391547404884040101606295111368\
825026273254703636026307207764436438929167613951


Disclaimer: The OP revised their question after we posted our first response.
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Old 2007-06-26, 13:27   #5
VolMike
 
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Thus , the result should be 1, becouse it is the smallest factor of 2^1061-1 :)

Last fiddled with by VolMike on 2007-06-26 at 14:02
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Old 2007-06-26, 15:19   #6
lazy
 

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Smaller prime factor.
Should I be very accurate?
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Old 2007-06-26, 22:24   #7
garo
 
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The word you are looking for starts with a p and has 11 digits.
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Old 2007-06-29, 18:50   #8
lazy
 

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Don't understand.

Quote:
Originally Posted by garo
The word you are looking for starts with a p and has 11 digits (not letters).
What do you mean?

I don't get it.
Can you say what it is.
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Old 2007-07-03, 03:45   #9
jasonp
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Quote:
Originally Posted by lazy View Post
I don't get it.
Can you say what it is.
A penultimate (a fancy word for 'second to last') factor refers to the second-largest factor of a number. The size of this factor is what people use to classify how difficult the number was to factorize. E.g. if the largest factor was 1000 digits and the penultimate factor was 30 digits, your factorization is not very noteworthy.
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Old 2007-07-03, 12:24   #10
lazy
 

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Yes, it is

So, But the chance that it has upto 3 prime factors is rare. Like M751 or M811.
If so, I didn't mean the penultimate prime factor,
but the smaller prime factor.

Even if it has 2 prime factors, the penultimate factor means the larger prime factor, and not the penultimate prime factor.

If it has 3 prime factors, I mean the smaller prime factor always.
The penultimate factor means here the product of larger two prime factors.
It is again, not also the penultimate prime factor.
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Old 2007-07-03, 18:08   #11
ewmayer
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Quote:
Originally Posted by lazy View Post
So, But the chance that it has upto 3 prime factors is rare.
No, it's not.

Quote:
Like M751 or M811.
We won't know whether it's like these 2 until we factor it.

Quote:
If so, I didn't mean the penultimate prime factor, but the smaller prime factor.
Better known as "the penultimate prime factor".

Quote:
Even if it has 2 prime factors, the penultimate factor means the larger prime factor, and not the penultimate prime factor.
Wrong.

Quote:
If it has 3 prime factors, I mean the smaller prime factor always.
"Smaller of the three" is nonsensical. Do you mean the smallest?

Quote:
The penultimate factor means here the product of larger two prime factors.
No, that's the "remaining composite cofactor."

Quote:
It is again, not also the penultimate prime factor.
This is again, wrong. Care to try for 0 for 8?

Well-chosen user name, BTW.
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