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#12 | |
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Mar 2003
New Zealand
13·89 Posts |
Quote:
The expected number of factors doesn't take into account the modifications, as Citirx noted above. When large values of Y are used with the `sr2sieve -y Y' switch the time it takes for the program to respond to an interrupt signal may become excessive. |
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#13 |
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Jun 2003
158210 Posts |
I also noted that if y is large and speed > 2^31p/sec, then the program does not output anything.
But for y values less than 10, this is not important. |
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#14 |
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Mar 2004
Belgium
292 Posts |
Any need for further sieving?
If so, with which y? Thank you. |
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#15 |
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Jun 2003
2×7×113 Posts |
Just looking for time per factor at different y values.
Note that if you sieved a range at y1 then there is no point on sieving the same range at y2, where y2>y1. So using above need average time per factor for y=1 to y=12 and what machine was used for each. edit: No need to reserve the whole trillion range for low y's. You can find the time over the first few factors.
Last fiddled with by Citrix on 2007-05-25 at 07:40 |
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#16 |
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Mar 2004
Belgium
292 Posts |
Reserving 801T => 802T, y= 12
P4 - 2800 - 1Gb |
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#17 |
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Mar 2004
Belgium
292 Posts |
Range done in under 15 minutes
05/25/07 15:09:42 WARNING: Only testing for factors p of the form p=1 (mod 4096). 05/25/07 15:09:42 sr2sieve started: 2 <= n <= 49999947, 801000000000000 <= p <= 802000000000000 05/25/07 15:22:43 sr2sieve stopped: at p=802000000000000 because range is complete. 05/25/07 15:22:43 Found factors for 0 terms in 748.295 cpu sec. (expected about 49.68) Is it advisable to use the "Y" settings for "production" use? Last fiddled with by ValerieVonck on 2007-05-25 at 13:23 |
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#18 |
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Jun 2003
2×7×113 Posts |
y=12 so you expect to find 1 factor, for every 2048 actual factors. So 2048/50=41T.
So you should do a range of 41T with y=12 to get a factor. Now to get average time over 1-2 factors, do a range of 100-150T. edit: Don't know for sure, but I think y=5 might be the best for a .dat of range n=2M. Last fiddled with by Citrix on 2007-05-26 at 04:27 |
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#19 |
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Mar 2004
Belgium
292 Posts |
Reserving 802T => 844T
P4 - 2400 - 512 mb |
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#20 |
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Jun 2005
373 Posts |
If you want to find factors needed soon on the SoB side, you could create a .dat from 14M to 15M. Below is beeing P-1ed currently.
Yours, H. |
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#21 |
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Mar 2004
Belgium
11010010012 Posts |
finished my range
Code:
05/25/07 23:05:04 WARNING: Only testing for factors p of the form p=1 (mod 4096). 05/25/07 23:05:05 sr2sieve started: 2 <= n <= 49999947, 802000000000000 <= p <= 844000000000000 05/25/07 23:05:29 sr2sieve stopped: at p=802005932351489 because SIGINT was received. 05/25/07 23:05:29 Found factors for 0 terms in 25.968 cpu sec. (expected about 0.29) 05/25/07 23:06:19 WARNING: Only testing for factors p of the form p=1 (mod 4096). 05/25/07 23:06:19 sr2sieve started: 2 <= n <= 49999947, 802005932351489 <= p <= 844000000000000 05/25/07 23:33:36 sr2sieve stopped: at p=804090763714561 because SIGINT was received. 05/25/07 23:33:36 Found factors for 0 terms in 1659.984 cpu sec. (expected about 103.67) 05/26/07 10:53:41 WARNING: Only testing for factors p of the form p=1 (mod 4096). 05/26/07 10:53:41 sr2sieve started: 2 <= n <= 49999947, 804090763714561 <= p <= 844000000000000 05/26/07 19:21:57 sr2sieve stopped: at p=842603790606337 because SIGINT was received. 05/26/07 19:21:57 Found factors for 0 terms in 31699.796 cpu sec. (expected about 1963.85) 05/26/07 20:00:01 WARNING: Only testing for factors p of the form p=1 (mod 4096). 05/26/07 20:00:02 sr2sieve started: 2 <= n <= 49999947, 842603790606337 <= p <= 844000000000000 05/26/07 20:18:39 sr2sieve stopped: at p=844000000000000 because range is complete. 05/26/07 20:18:39 Found factors for 0 terms in 32811.092 cpu sec. (expected about 2029.59) |
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#22 |
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Jun 2003
2×7×113 Posts |
Attached is PSP dat from 4M to 6M to test.
I tried making a dat file for PSP+SOB with n=4M to 6M for PSP and n=14M to 16M for SOB. Geoff's Srsieve became very slow when I did this, so I am just posting the PSP 2M dat. Reserve ranges as you wish.Thanks!
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