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Old 2007-03-02, 13:33   #45
Patrick123
 
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My p cents worth:

p is prime iff the only two factors of p are p and p/p provided
p <> p - p and
p <> p/p

Regards
Patrick
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Old 2007-03-02, 15:13   #46
Mini-Geek
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Quote:
Originally Posted by Patrick123 View Post
My p cents worth:

p is prime iff the only two factors of p are p and p/p provided
p <> p - p and
p <> p/p

Regards
Patrick
Violation.
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Old 2007-03-02, 22:37   #47
Patrick123
 
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Quote:
Originally Posted by Mini-Geek View Post
Violation.
Whoops let's rephrase that:

p is prime iff its only factors are p and p/p provided
p <> p - p and
p <> p/p and
p is positive.

Regards
Patrick
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Old 2007-03-04, 11:07   #48
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Quote:
Originally Posted by R.D. Silverman View Post
An integer p is prime if and only if for all A,B, such that A^2 = B^2 mod p,
then A=B mod p or A=-B mod p.
So, 1 and 6 are primes then?

Last fiddled with by Jushi on 2007-03-04 at 11:11
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Old 2007-03-04, 13:18   #49
S485122
 
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Quote:
Originally Posted by Jushi View Post
So, 1 and 6 are primes then?
How do you define an equality modulo 1 ?
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Old 2007-03-04, 13:40   #50
Jushi
 
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Quote:
Originally Posted by S485122 View Post
How do you define an equality modulo 1 ?
Usually, "a = b mod c" means "c divides (b-a)". Then any two integers are equal mod 1, because 1 divides any integer.
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Old 2007-03-08, 15:56   #51
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Quote:
Originally Posted by S485122 View Post
How do you define an equality modulo 1 ?
That's not much worse than equality mod 2\pi which everyone knows from study of trigonometric functions... "x = y (mod z)" is defined for any number z (including 0, where it gives equality) as he wrotes, or x-y \in z\,\mathbb Z where Z are the integers, i.e. zZ are all numbers of the form zk with k some integer.
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