Four Fours - Page 6

grandpascorpion · 2007-02-08, 16:57

111 = 444/4
112 = 44/.4 + √4

Andi47 · 2007-02-08, 18:10

113 seems to be quite difficult.

113 = gamma(gamma(4)) - 4 - (√4 / √.4~) ;)
113 = (√4 + (√4 + 4!)%)) / (√4)% (found in a table)

Anyone for a solution without gamma and % ?

Andi47 · 2007-02-09, 09:38

Two more "gamma" solutions:

113 = gamma(gamma(4)) - √4 / .4 - √4
113 = (√4 / .4)! - gamma(4) - gamma(√4)

S485122 · 2007-02-09, 15:51

Quote:

Originally Posted by Andi47

Two more "gamma" solutions

Ok, now we now know gamma(gamma(4))=120 and that gamma(4)+gamma(√4)=7
But what is the gamma functiun ?

I did not find an explanation on internet, but I suppose I did not look hard enough.

Andi47 · 2007-02-09, 17:02

Quote:

Originally Posted by S485122

Ok, now we now know gamma(gamma(4))=120 and that gamma(4)+gamma(√4)=7
But what is the gamma functiun ?

I did not find an explanation on internet, but I suppose I did not look hard enough.

Wikipedia:Gamma Function

for integers: gamma(n) = (n-1)!

Edit: I did not find any solution for 113 with only +, -, *, /, ^, √, .4 and .4~ in the internt, some pages even belive that this is impossible, although there is now prove for possibility or impossibility. Maybe one of you finds one?

petrw1 · 2007-02-09, 17:51

For the record I do NOT have a solution to 113 either.....within my constraints.

grandpascorpion · 2007-02-09, 17:53

114 = (√4 / .4)! - 4 - √4
115 = (√4 / .4)! - (√4 /.4)
116 = (√4 / .4)! - √4 - √4
117 = (√4 / .4)! - √(4/.4~)

Andi47 · 2007-02-09, 18:57

118 = (√4 / .4)! - 4 + √4
119 = (√4 / .4)! - 4 / 4
120 = (√4 / .4)! + 4 - 4
121 = (√4 / .4)! + 4 / 4

grandpascorpion · 2007-02-09, 19:05

122 = (√4 / .4)! + 4/ √4
123 = (√4 / .4)! + √(4 /.4~)
124 = (√4 / .4)! + √4 +√4
125 = (√4 / .4)! + √4 / .4

Andi47 · 2007-02-09, 20:25

126 = √(√(√(4^4!))) * √4 - √4
127 = √(√(√((√4 / .4)^4!))) + √4
128 = √(√(√(4^4!))) * (4 - √4)
129 = √(√(√((√4 / .4)^4!))) + 4

grandpascorpion · 2007-02-09, 20:49

130 = (√4 / .4)! + 4/.4
131 = ( 4^4 + gamma(4) )/ √4 (Am I throwing in the towel too early?)
132 = (√4 / .4)! + 4!/√4

2007-02-09, 18:57	#63
Andi47 Oct 2004 Austria 100110110010₂ Posts	118 = (√4 / .4)! - 4 + √4 119 = (√4 / .4)! - 4 / 4 120 = (√4 / .4)! + 4 - 4 121 = (√4 / .4)! + 4 / 4 Last fiddled with by Andi47 on 2007-02-09 at 18:57 Reason: Typo

2007-02-09, 19:05	#64
grandpascorpion Jan 2005 Transdniestr 503 Posts	122 = (√4 / .4)! + 4/ √4 123 = (√4 / .4)! + √(4 /.4~) 124 = (√4 / .4)! + √4 +√4 125 = (√4 / .4)! + √4 / .4 Last fiddled with by grandpascorpion on 2007-02-09 at 19:07

2007-02-09, 20:49	#66
grandpascorpion Jan 2005 Transdniestr 503 Posts	130 = (√4 / .4)! + 4/.4 131 = ( 4^4 + gamma(4) )/ √4 (Am I throwing in the towel too early?) 132 = (√4 / .4)! + 4!/√4 Last fiddled with by grandpascorpion on 2007-02-09 at 21:01

2007-02-08, 16:57	#56
grandpascorpion Jan 2005 Transdniestr 503₁₀ Posts	111 = 444/4 112 = 44/.4 + √4

2007-02-08, 18:10	#57
Andi47 Oct 2004 Austria 2×17×73 Posts	113 seems to be quite difficult. 113 = gamma(gamma(4)) - 4 - (√4 / √.4~) ;) 113 = (√4 + (√4 + 4!)%)) / (√4)% (found in a table) Anyone for a solution without gamma and % ?

2007-02-09, 09:38	#58
Andi47 Oct 2004 Austria 2·17·73 Posts	Two more "gamma" solutions: 113 = gamma(gamma(4)) - √4 / .4 - √4 113 = (√4 / .4)! - gamma(4) - gamma(√4)

2007-02-09, 17:51	#61
petrw1 1976 Toyota Corona years forever! "Wayne" Nov 2006 Saskatchewan, Canada 1001001010111₂ Posts	For the record I do NOT have a solution to 113 either.....within my constraints.

2007-02-09, 17:53	#62
grandpascorpion Jan 2005 Transdniestr 503 Posts	114 = (√4 / .4)! - 4 - √4 115 = (√4 / .4)! - (√4 /.4) 116 = (√4 / .4)! - √4 - √4 117 = (√4 / .4)! - √(4/.4~)

2007-02-09, 20:25	#65
Andi47 Oct 2004 Austria 2·17·73 Posts	126 = √(√(√(4^4!))) * √4 - √4 127 = √(√(√((√4 / .4)^4!))) + √4 128 = √(√(√(4^4!))) * (4 - √4) 129 = √(√(√((√4 / .4)^4!))) + 4