Quadrilateral problem

[philmoore]

Originally Posted by davieddy

If we relax the "simple" stipulation that AB,BC,CD,DA do not intersect
we get two "figures of 8". In one, AB crosses CD, in the other BC crosses
the diameter DA.

Perhaps the two negative solutions give the diameter in these cases?

David

One negative solution definitely seems to give such an interpretation, but the other negative solution is less than 3 (in absolute value), so I really do not understand whether or not this solution has a straightforward geometric interpretation.

[davieddy]

Originally Posted by philmoore

One negative solution definitely seems to give such an interpretation, but the other negative solution is less than 3 (in absolute value), so I really do not understand whether or not this solution has a straightforward geometric interpretation.

Pity.
Another erroneous post for Mally to gloat about :(((