How long should carry?

[chrow]

Before I let my PC just some hours linked. now that I decided to let 24 hours, after 23 hours working, MATHER BOARD MONITOR locked. He continued measuring the temperature and the speed of cooler correctly, when the room heated, MBM accused, and when the room also cooled him accused. Perhaps he was not doing that accurately, but it was doing. what it locked was MBM's Icon who stays next to the watch.
If MBM had problems is very possible that the prime95 also can have. up to now it did not accuse anything.
When prime95 does it have problems how Will I know? When is he going to tell me occurred mistakes?


Moises Deangelo
lewris@ig.com.br
ICQ:89529510

[S80780]

If prime95 detects a failure, it gives an output on the program window saying something like 'this or that failure was detected. Resuming work from last savefile.'. The same message is written with a timestamp in the results.txt file. So if you think that a failure has accured, take a look at the results.txt entries. This is no 100% guarantee, but the propability of undetected failures is quite low.

Benjamin

[Mr. P-1]

Originally Posted by cheesehead

So the sequence will be:

Trial factoring ("Factoring") up to 2^68
P-1 stage 1
P-1 stage 1 GCD
P-1 stage 2 (lots of memory use here)
P-1 stage 2 GCD
L-L test

If insufficient memory has been allowed, then stage 2 will be omitted entirely. I doubt that the 30MB Moises has allowed will be enough.

Regards

Daran

[cheesehead]

Originally Posted by Mr. P-1

If insufficient memory has been allowed, then stage 2 will be omitted entirely. I doubt that the 30MB Moises has allowed will be enough.

True, it's not enough for P-1 stage 2 on M33518297.

Moises could increase his allocation to 68M or more, which would provide 4 temporary areas (the minimum requirement) for P-1 stage 2 on assignments between M30190000 and M35200000.

30MB would provide at least 4 temporaries for P-1 stage 2 up to M15340000.

[Mr. P-1]

Originally Posted by cheesehead

True, it's not enough for P-1 stage 2 on M33518297.

Moises could increase his allocation to 68M or more, which would provide 4 temporary areas (the minimum requirement) for P-1 stage 2 on assignments between M30190000 and M35200000.

30MB would provide at least 4 temporaries for P-1 stage 2 up to M15340000.

Moises, it really does help a lot if you can give the program as much memory as you can for stage 2 - hundreds of megabytes if you have them. You can set up the client so that it only runs stage 2 at certain times of the day when you're not otherwise using the machine.

If you don't then the risk is that you could spend many months LL testing an exponent where a factor could easily have been found.

Regards

Daran