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#1 |
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Jun 2003
The Texas Hill Country
32·112 Posts |
Without using any symbols, arrange the digits 1, 3, 5,7, 9 to equal the digits 2, 4, 6, 8.
Last fiddled with by Wacky on 2006-07-06 at 11:41 |
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#2 |
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Undefined
"The unspeakable one"
Jun 2006
My evil lair
2·11·283 Posts |
What is considered a "symbol"? "+", "-", "*", "/"?
Is this a trick question? |
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#3 |
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Jun 2003
The Texas Hill Country
32·112 Posts |
This is not a "trick" question. There are certain "operations" implied by the relative location of the digit glyphs. For example, concatenation represents the multiplication of the number represented by the leading "string" by the number's base followed by the addition of the number represented by the last digit. There are additional operations implied by other configurations. However, none of these representations require any additional glyphs.
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#4 |
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Undefined
"The unspeakable one"
Jun 2006
My evil lair
2·11·283 Posts |
The only operations I can think of without using symbols would be superscript for powering and subscript for base change.
Is the answer in four parts where there is a separate result for each digit? Or is it one answer that gives a result containing all the required digits? Or maybe something else? For example: 11 (base) 7 = 8. [Sorry, I don't know how to do proper subscripts] 11 (base) 5 = 6. 11 (base) 3 = 4. |
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#5 |
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Jun 2003
The Texas Hill Country
21018 Posts |
You have discovered the other two "operations". Now, you need to use each of the digits 1, 3, 5, 7 and 9 once in an expression that is equal to the same value as another expression which uses each of the digits 2, 4, 6 and 8 exactly once each.
(Sorry, I left out the "9". -- The original statement of the puzzle is correct.) Last fiddled with by Wacky on 2006-07-09 at 17:13 |
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#6 | ||
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Undefined
"The unspeakable one"
Jun 2006
My evil lair
2×11×283 Posts |
Quote:
Quote:
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#7 |
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Undefined
"The unspeakable one"
Jun 2006
My evil lair
2×11×283 Posts |
The closest I have got is 1735(base)9=2460(base)8 but this doesn't meet the requirements because of the zero.
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#8 |
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"William"
May 2003
New Haven
2×7×132 Posts |
264[sub]8[/sub] = 39[sub]57[/sub][sup]1[/sup] and 426[sub]8[/sub] = 75[sub]39[/sub][sup]1[/sup] |
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