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#1 |
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Jun 2003
The Texas Hill Country
32·112 Posts |
Find unequal rational numbers, a, b, ( other than 2 and 4 ) such that
There are an infinite number of such pairs. Give the general solution. |
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#2 | ||
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Bronze Medalist
Jan 2004
Mumbai,India
80416 Posts |
Quote:
Quote:
Mally
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#3 |
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Undefined
"The unspeakable one"
Jun 2006
My evil lair
2×11×283 Posts |
There is one more set of integers satisfying the equation: {-2, -4}
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#4 | |
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Bronze Medalist
Jan 2004
Mumbai,India
22·33·19 Posts |
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I got this info from the book 'Numbers' by David Wells who seldom makes a mistake in the data he presents. It clearly says ' Euler showed that the only integer solution to a^b = b^a is 4^2 =2^4 =16.' Unless Wells takes the answer 1/16 with the negative no.s to be a non integer solution. Possibly thats the correct interpretation. However when it comes to rational numbers the -ve sign cancels out I would say, as is the case with (-2,-4) but I' not sure. Mally
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#5 |
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Aug 2002
Buenos Aires, Argentina
2·683 Posts |
a = (1 + 1/n)[sup]n[/sup] b = (1 + 1/n)[sup]n+1[/sup] n can be any integer different from zero. Last fiddled with by alpertron on 2006-06-15 at 13:53 |
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#6 | |
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Undefined
"The unspeakable one"
Jun 2006
My evil lair
2×11×283 Posts |
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