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Old 2006-06-12, 16:03   #1
Wacky
 
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Default PR 4 # 12

Find unequal rational numbers, a, b, ( other than 2 and 4 ) such that a^b = b^a

There are an infinite number of such pairs. Give the general solution.
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Old 2006-06-14, 08:44   #2
mfgoode
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Thumbs up general solution

Quote:
Originally Posted by Wacky
Find unequal rational numbers, a, b, ( other than 2 and 4 ) such that a^b = b^a

There are an infinite number of such pairs. Give the general solution.
Quote:
Originally Posted by Mally
Hint: Euler proved that 2 and the 4 are the only integers satisfying the eqn. So now give the general solution for rationals

Mally
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Old 2006-06-14, 10:04   #3
retina
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There is one more set of integers satisfying the equation: {-2, -4}
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Old 2006-06-15, 04:03   #4
mfgoode
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Smile +ve and -ve integers.

Quote:
Originally Posted by retina
There is one more set of integers satisfying the equation: {-2, -4}


I got this info from the book 'Numbers' by David Wells who seldom makes a mistake in the data he presents.

It clearly says ' Euler showed that the only integer solution to a^b = b^a is 4^2 =2^4 =16.'
Unless Wells takes the answer 1/16 with the negative no.s to be a non integer solution. Possibly thats the correct interpretation.

However when it comes to rational numbers the -ve sign cancels out I would say, as is the case with (-2,-4) but I' not sure.

Mally
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Old 2006-06-15, 13:52   #5
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a = (1 + 1/n)[sup]n[/sup]
b = (1 + 1/n)[sup]n+1[/sup]
n can be any integer different from zero.

Last fiddled with by alpertron on 2006-06-15 at 13:53
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Old 2006-06-16, 02:53   #6
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Quote:
n can be any integer different from zero
Actually, n can be any integer except zero or minus one.
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