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#1 |
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Jun 2003
5,051 Posts |
I was trying on Prime95's Pfactor option to do some P-1 on numbers of the form k*2^n+1. The following are some of the bounds that the program used. All numbers used 34,1.5 parameters (factored to 34 bits, one factor saves 1.5 tests).
980535*2^438222+1 completed P-1, B1=15000, B2=105000, Wc1: 0B7EC43F 980535*2^450435+1 completed P-1, B1=15000, B2=108750, Wc1: 0BC8F208 980535*2^460337+1 completed P-1, B1=10000, B2=97500, Wc1: 0BFAB234 980535*2^498747+1 completed P-1, B1=10000, B2=105000, Wc1: 0D05D273 P95 was given 200M of memory (day & night). I am really confused! AFAIK, all else being the same, bigger numbers should get higher B1/B2 bounds. But here, P95 goes down from a higher B1 to a lower one! Anybody has got any ideas? Geroge?! ![]() PS:- There were many more P-1 tests I ran. The four shown above are just representative. All of them used 48k zero-padded FFT. Each P-1 took < 1 min on P4 2.8GHz. |
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#2 |
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P90 years forever!
Aug 2002
Yeehaw, FL
752610 Posts |
It sure looks like a minor bug. I can't tell without stepping through the bounds-generating code.
Your logic that the PRP test takes longer for bigger numbers, thus a factor is worth more, thus deeper P-1 is required is correct. If it isn't a bug, then all I can think of is these B1/B2 combinations are real close and it is a rounding error introducing seemingly illogical choices. It would be great if akruppa, the P-1 bounds expert bar none, would review the Mersenne bounds generating code - hint, hint. |
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#3 |
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10110011010002 Posts |
Hi,
How can i calculate such "thing" 2^4637852? What software shal i use? |
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