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#1 |
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"Nancy"
Aug 2002
Alexandria
2,467 Posts |
Adam has a sister, Barbara. She is as old as he was when she was half as old as he is. Adam is 24, how old is Barbara?
Alex |
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#2 | |
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Jun 2003
The Texas Hill Country
32×112 Posts |
Quote:
To make it more interesting, also try the similar problem that states "was half as old as he was" (then). She is "of age" (18 in this jurisdiction). In my proposed alternate, She is a sweet 16. |
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#3 |
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Aug 2003
Upstate NY, USA
5068 Posts |
16
darn Wacky beating me by under a minute Last fiddled with by tom11784 on 2005-12-29 at 23:39 |
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#4 |
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Jun 2003
The Texas Hill Country
108910 Posts |
Barbara's brother, Adam, was present when she fell in the well. Why didn't he help her out?
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#5 |
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Aug 2003
Upstate NY, USA
2·163 Posts |
He fell in as well
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#6 |
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Jun 2003
The Texas Hill Country
32×112 Posts |
Tom,
I'm adverse to verse, but it will get worse. As for the age, we're on a different page. In the case of the well, your answer is swell. A different solution I seek, (when found, others may reek). But an English pun, is really the fun. So bring in the New Year, with merriment and Cheer^h^h^h^h^h Oxydol ? Happy New Year, Y'all. Last fiddled with by Wacky on 2005-12-30 at 00:33 |
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#7 |
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Jun 2005
Near Beetlegeuse
22·97 Posts |
Let Barbara's age now be x.
Then 24-x = x - 12. and so x = 18. As for why he didn't help her out of the well; she fell in the stair well and picked herself up without his help. |
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#8 |
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"Nancy"
Aug 2002
Alexandria
1001101000112 Posts |
18 is, of course, correct and quite easily verified. I thought the problem was interesting because I found it very hard to wrap my mind around that second sentence! It's not really a complicated sentence and the math is trivial, but for some reason this problem is surprisingly hard to get a grip on (to me anyway).
Alex |
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#9 |
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Jun 2005
Near Beetlegeuse
22·97 Posts |
I know exactly what you mean. I find word problems difficult, period. I always seem to end up with about five variables and to lose track of the essential point of the question.
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#10 | |
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Jun 2003
The Texas Hill Country
44116 Posts |
Quote:
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#11 |
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Nov 2005
B616 Posts |
"Adam has a sister, Barbara. She is as old as he was when she was half as old as he is. Adam is 24, how old is Barbara?"
At first I read that as saying that they're the same age, but since this is a word problem, I have to reinterpet it. Her's old age was A/2. A=24 now. Her age now is what A was when B=A/2. B1=A1/2 A2=24 B2=A1 Assume that B1, B2, A1, and A2 are all integers from 1 to 24. If A1 is even then there exists possible values for B1. Eliminate odds. Try values of B1: B1=1, A1=2, A2=3 <-- not a solution B1=2, A1=4, A2=6 <-- not a solution B1=3, A1=6, A2=9 <-- not a solution B1=4, A1=8, A2=12 <-- not a solution B1=5, A1=10, A2=15 <-- not a solution B1=6, A1=12, A2=18 <-- not a solution B1=7, A1=14, A2=21 <-- not a solution B1=8, A1=16, A2=24 <-- solution Since 24 is even, then B1 has to be even too since 3(any odd)=another odd. If I was really lazy in going through test values then I'd also observed that A2=3 * B1. That is what everyone else did. |
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