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#67 |
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Aug 2005
Brazil
2×181 Posts |
How do you calculate the cyclotomic polynomials for the special numbers?
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#68 |
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Dec 2004
1001010112 Posts |
Personally I don't know how to calculate it yet and havn't had the time to investigate how. ... I generally use m instead of Y1 Y0.
So how did I do it... Little black box from ??? Xilman ??? ... the phi.exe program. I used it a couple times to check my calculations for the last few polynomials generally it produces the obvious degree 5 polys and m values. However from time to time it will generate polynomials like the c112 above, I've been using them with great success. Perhaps I'm doing something wrong but it's certainly working well for me, and the odd 4 hour factorization of a c112+ it's like christmas.
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#69 | |
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Jul 2004
Potsdam, Germany
33F16 Posts |
Quote:
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#70 | |
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Aug 2005
Brazil
2×181 Posts |
Quote:
Phi asks for the n and x values for the polynomial. How do you calculate those? |
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#71 | |
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Dec 2004
13·23 Posts |
Quote:
fetofs, Like I said black box for me so far, if you just run phi it give you switches, correct. All of the numbers that I have been trying thus far have been of the x^n-1 type so I'm simply entering the base and exponent. For N you can always use 1 right, it divides everything . I havn't seen a difference using anything other than 1 for N anyways.Maybe I need to ask a few question... 1. You know that inorder to do snfs as opposed to ggnfs you need the equation from which the composite orginated. 2. In addition to this N: doesn't have to be N for the entire expression Maybe I'm still not understanding your question... for the above number a c112 it orginated from the expression. Ahh sorry I noticed the forum butchered the number.. 713406215047 hat 13 - 1 so phi 13 713406215047 1 |
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#72 | |
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"Sander"
Oct 2002
52.345322,5.52471
29×41 Posts |
Quote:
I'm wondering if there's a newer version available. Latest i could find is 0.1.2 |
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#73 |
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Mar 2004
Belgium
34916 Posts |
Here is the phi program
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#74 |
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Dec 2004
13·23 Posts |
If during sieving you get a report of "too many relations" I know this can be avoided by reducing your sieve range.
My question is... What does it matter if you get too many relations 90% through your sieving chunk. Are those "extra" relations thrown out or does it just make the bin file too large --> more difficult to process later ? Just curious. |
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#75 |
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Mar 2004
Belgium
292 Posts |
For me its no problem.... I only wondered it woulnd't interfere with the program.
C. |
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#76 |
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Mar 2004
Belgium
292 Posts |
Hi group,
I am doing my first SNFS factorization. But I have a question about "degree". I run the program phi.exe & I choose a polynomial of the 6th degree. But I can also choose a 4 & 5 degree one! What is better to choose? a 6 or a 4 degree poly? Sorry about the st00pid question .... but I try understand it... Best Regards C.
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#77 |
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"Nancy"
Aug 2002
Alexandria
2,467 Posts |
Depends on how large your number is, that is, on the SNFS difficulty. Grossly simplified, for difficulty ~100, degree 4 is optimal, for ~150, degree 5 and for ~240, degree 6. Sometimes the difficulty can be reduced by dividing out algebraic factors. Run phi without -deg4 or -deg6 first and see what difficulty you get. Without a -degx parameter, phi will try to minimise the difficulty by dividing out the largest algebraic factors that can be used.
Then. if your number is very small (difficulty <120) try -deg4, if it is very large (>190) try -deg6. If the difficulty you now get is no (or only marginally) higher than the default one, use -deg4 or -deg6, resp. Otherwise stick with the default. For composite sizes beginners of SNFS will typically attempt, the default polynomial produced by phi is usually very reasonable. Alex |
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