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Old 2005-03-25, 04:24   #12
mfgoode
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Default Kiddie problem

Quote:
Originally Posted by Uncwilly
How about [b].[/b]125
:surprised
Great!!.
I didnt think of that. Come to think of it .0125 and the rest of the zero decimals wont do.
Mally
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Old 2005-03-25, 04:36   #13
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Quote:
Originally Posted by paulunderwood
Thanks

another the imaginary number -12.5i
:surprised
Excellent!! Didnt think of that either.
Just think where a simple problem has lead us?
Mally
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Old 2005-03-25, 14:19   #14
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Quote:
Originally Posted by paulunderwood
Thanks

another the imaginary number -12.5i
Quote:
Originally Posted by Uncwilly
How about [b].[/b]125

Well whats wrong with +12.5, +1.25i or +1.25i ?

0r .125, 12.5 or 1.25 ?, for that matter!

Mally !
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Old 2005-03-28, 16:29   #15
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Question Kiddie problem

Quote:
Originally Posted by mfgoode

Well whats wrong with +12.5i, +1.25i or +1.25i ?

0r .125, 12.5 or 1.25 ?, for that matter!

Mally !

What no more answers?
I still have one more different answer up my sleeve.
This is apart from the negative values which are equally valid of the above
Come on guys use your imaginations
Mally
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Old 2005-03-29, 06:17   #16
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Quote:
Originally Posted by mfgoode
Well whats wrong with +12.5, +1.25i or +1.25i ?
+12.5 is okay. But taking away the 1st and next digits of [b]+1.25i[/b] leaves [b]+.5i[/b], which is not 1/5 of [b]+.25i[/b].
Were you thinking of [b]+.05i[/b] as the third value? That would [i]substitute[/i] "0" for "2", instead of simply [i]taking away[/i]
the "2" as required by the original posting.
[u]You already pointed out that ".0125 and the rest of the zero decimals wont do."[/u] :-D


Quote:
0r .125, 12.5 or 1.25 ?, for that matter!
Similarly, [b].125[/b] is wrong because the second term is [b].25[/b], not [b].025[/b], and so forth ...

Last fiddled with by cheesehead on 2005-03-29 at 06:25
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Old 2005-03-29, 16:16   #17
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Lightbulb Kiddie problem

QUOTE:[cheesehead]
Were you thinking of +.05i as the third value? That would substitute
"0" for "2", instead of taking away
the "2" as required by the original posting :UnQUOTE]

:surprised
Im glad you brought up this thought provoking point.

Its not surprising that you find it baffling as to many others in the past.

The same argument was put forward by the mid-eastern traders when they encountered the Sanskrit 'sunya'. The Arabs called it the mysterious 'sifr' and spread it to the Western world where it was called Ziffer and chiffre by the Germans and French resp. tho' they included numbers in general.

THe'SUNYA' means a void which has no magnitude but possesses place value.
Before I comment fully, I throw this problem open to the forum to get their views to detrmine what is right and what is wrong.
Mally
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Old 2005-03-30, 12:51   #18
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Quote:
Originally Posted by mfgoode
Its not surprising that you find it baffling as to many others in the past.
I'm not baffled.

The digit "0" is used as a placeholder after the decimal point. So?
Your puzzle rules mention taking away digits, but not adding/inserting them.
If we had a placeholder that was not a digit, we could use that ... but we don't.
Inserting the [b]digit[/b] "0" as a placeholder is outside the rule requiring "take away".


Quote:
THe'SUNYA' means a void which has no magnitude but possesses place value.
Fine ... but "0" is not a sunya.
If you intend that taking away the digit "2" from .25 produces .05 instead of .5,

then you need to revise the puzzle's wording.

Remember, you said .0125 wouldn't do. If that "0" isn't allowed, then neither is the one in .05

Last fiddled with by cheesehead on 2005-03-30 at 13:04
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Old 2005-03-30, 18:39   #19
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I was going to post solutions using a numbering system with a base other than 10. It was an interesting discovery that there are no such solutions. (i.e. no solutions in hexadecimal nor binary nor base-7 nor any other base.)

William
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Old 2005-03-31, 16:00   #20
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wblipp: Thank you for extending the problem to other bases. It has saved me needless trouble as I thought about this also and its possibility but did not put pen to paper.
Now that you have ruled out the application to other bases it makes the problem unique. I am intrigued to read about 'all bases' and will be interested to know your line of reasoning.
I am now of the opinion that I should lift the restriction of 3 digits to any finite number thus generalising the problem and making it more interesting.
Mally
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Old 2005-03-31, 16:12   #21
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Quote:
Originally Posted by mfgoode
I am intrigued to read about 'all bases' and will be interested to know your line of reasoning.
Letting the 3 digit number be ABC and the base be "b", we have

Ab^2+Bb+C=5(Bb+C)
Bb+C=5C

From which we can get
C=Ab^2/20

We know C<b. From this we get
Ab<20.

The gets a small number of possible values for A and b. The only cases with
A<b and C<b and C an integer is the base 10 solution.
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Old 2005-03-31, 16:23   #22
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Default Kiddie problem

[QUOTE=wblipp]Letting the 3 digit number be ABC and the base be "b", we have......Unquote]
Thanks wblipp. Thats great but I still have to digest it :surprised
Mally
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