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#34 | |
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Jan 2020
22·32 Posts |
Quote:
Given a RPS(n) game, we can always extend it to a RPS(n+2) game: aaavw aaavw aaa10 ww001 vv100 where A is the adjacency matrix of the RPS(n) game, V is a column vector of even length n-1 with (n-1)/2 zeros and (n-1)/2 ones, W is the negation of V. The "cartesian product" block construction provides a RPS(15) game which embeds five independent RPS(3) games. I chose V so that the elements of four RPS(3) games still win/lose together against everything else, obtaining a RPS(17) game with 81 automorphisms: 0 1 0 1 1 1 1 1 1 0 0 0 0 0 0 1 0 0 0 1 1 1 1 1 1 1 0 0 0 0 0 0 1 0 1 0 0 1 1 1 1 1 1 0 0 0 0 0 0 1 0 0 0 0 0 1 0 1 1 1 1 1 1 0 0 0 1 0 0 0 0 0 0 1 1 1 1 1 1 1 0 0 0 1 0 0 0 0 1 0 0 1 1 1 1 1 1 0 0 0 1 0 0 0 0 0 0 0 0 1 0 1 1 1 1 1 1 0 1 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 0 1 0 0 0 0 0 0 1 0 0 1 1 1 1 1 1 0 1 1 1 1 0 0 0 0 0 0 0 1 0 1 1 1 0 1 1 1 1 0 0 0 0 0 0 0 0 1 1 1 1 0 1 1 1 1 0 0 0 0 0 0 1 0 0 1 1 1 0 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 0 1 0 1 1 1 1 1 1 0 0 0 0 0 0 0 0 1 0 1 1 1 1 1 1 1 0 0 0 0 0 0 1 0 0 1 0 0 0 0 0 0 0 1 1 1 1 1 1 0 1 0 0 1 1 1 1 1 1 1 0 0 0 0 0 0 1 0 1 0 0 This approach can be easily generalized: given a prime p, choose the largest odd composite n=3*q not exceeding p; build a RPS(n) with q independent RPS(3) blocks; extend it once or twice, so that the elements of the first q-1 RPS(3) blocks can still be shifted independently. Asymptotically, the number of automorphisms grows from O(p^2) to O(3^(p/3)). As an example, for p=23 we get 23*11 = 253 and 3^6 = 729 respectively. A more refined solution has 1323 automorphisms: 0 1 1 0 1 0 0 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 0 0 0 1 1 0 1 0 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 0 0 0 0 1 1 0 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 0 1 0 0 0 1 1 0 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 0 0 1 0 0 0 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 0 1 0 1 0 0 0 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 0 1 1 0 1 0 0 0 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 1 1 0 1 0 0 1 1 1 1 1 1 1 0 1 0 0 0 0 0 0 0 0 0 1 1 0 1 0 1 1 1 1 1 1 1 0 1 0 0 0 0 0 0 0 0 0 0 1 1 0 1 1 1 1 1 1 1 1 0 1 0 0 0 0 0 0 0 1 0 0 0 1 1 0 1 1 1 1 1 1 1 0 1 0 0 0 0 0 0 0 0 1 0 0 0 1 1 1 1 1 1 1 1 1 0 1 0 0 0 0 0 0 0 1 0 1 0 0 0 1 1 1 1 1 1 1 1 0 1 0 0 0 0 0 0 0 1 1 0 1 0 0 0 1 1 1 1 1 1 1 0 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 1 1 0 1 0 0 1 0 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 1 1 0 1 0 1 0 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 0 1 0 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 0 0 0 1 1 0 1 0 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 1 0 0 0 1 1 0 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 0 1 0 0 0 1 0 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 1 0 1 0 0 0 1 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 0 0 1 0 1 1 0 0 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 1 1 0 1 0 0 1 0 0 Here the starting RPS(21) game embeds three independent RPS(7) games. The extended RPS(23) game admits: for the first two blocks, any of the 21 possible automorphisms; for last block, the 3 automorphisms which keep last element unchanged. Last fiddled with by 0scar on 2020-10-12 at 03:40 |
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