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#12 |
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Aug 2002
Buenos Aires, Argentina
1,523 Posts |
I think the following message that I posted to USENET on November 1997 would be interesting for this thread. It was about computing i^i without computing e or pi.
======================================================= I don't know of a series for i^i, but below there is a continued fraction expansion: From the Handbook of Mathematical Functions (Milton Abramowitz and Irene Stegun), formula 4.2.42: Code:
2 2 2 2 2 2
2a*atn(1/z) 2a a +1 a +2 a +3
e = 1 + ---- ----- ----- ----- ...
z-a+ 3z+ 5z+ 7z+
Code:
2 2 2
-pi/2 i 2 1+1 1+2 1+3
e = i = 1 - ----- ----- ----- ----- ...
2+ 3+ 5+ 7+
fraction, the precision is incremented in 75 decimal digits approximately. Code:
10 word 400 20 point 200 30 input "Terms";T 40 S#=0 50 for K=T to 1 step -1 60 S#=(K*K+1)/(K+K+1+S#) 70 next K 80 F#=1-2/(2+S#) 90 G#=#i 100 H#=G#^G# 110 print H#-F# |
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#13 | |
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Bronze Medalist
Jan 2004
Mumbai,India
22×33×19 Posts |
Quote:
QUOTE=S80780]1) What is the value of i^i? i^i = e^[(2k+0.5)*pi*i*i] = e^[-(2k+0.5)*pi], k in Z, so it is real. 2) What is the value of i^-i? i^-i = (i^i)^-1 = e^[(2k+0.5)*pi], k in Z, so it is real. I expect the main value is k=0. A more interesting question here would be, if e^pi is in Q. Benjamin[/QUOTE] Dear Bob, Compared to your qualifications and career (see Jinydu's post in this thread) I am just an amateur mathem'cian with a Mechanical engg. background groping into the darker recesses of maths with the advantage of having traversed the globe for 35 yrs and then retired. I give below the numerical values of the foll: i^i =0.207 879 576 350 761 908 546 955 ------ i^-i = reciprocal of i^i =4.810 477 389 --------- e^pi =23.140 692 632 779 269 005 729 086 ----- This is a transcendental no. Hence in the set R pi^e =22.459 157 718 361 045 473 427 152 -------- Q.E.I. It is not known whether this no. is rational or irrational so it could be in Q . Hence this no. is open for enquiry and proof Source: "The Penguin dictionary of curious and intresting numbers" by David Wells" Mally
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