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#12 |
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Jun 2003
22×3×421 Posts |
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#13 |
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"Rashid Naimi"
Oct 2015
Remote to Here/There
80716 Posts |
Good, my data mining worked.
![]() Thanks. I will still try it the old fashioned way for now. Getting too old for programming. |
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#14 |
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Romulan Interpreter
Jun 2011
Thailand
961110 Posts |
This is not really a puzzle, it is more like a prank.
That huge "size 40" tricked me a little, until I realized that for 14 moves to be a cycle you can move maximum 7 steps in one direction, as you will need 7 steps to come back. Therefore, jumping two squares every time, there is no way to reach the other end of a "size 40" board (the standard chess board is "size 8", not "size 64", grrr). Then it clicked to me they mean area, or the number of squares, and in this case you can't have a board too large. A 6x7 board will be already larger, so you must stay in 5x8, or 6x6, or you still can play with a 10x4. The Nx3 would be too narrow, I mean, the only way you can make a non-intersecting track with length 14 is on a 14x3 board, and that is already "size 42", isn't it??? And then "bang!" it hit me! haha. It took me like 10 minutes. Edit: pencil and paper, no code, no calculator for area. (Long Live Mathologer, one of his videos shows how to calculate area of tilted rhombuses, by wrapping them in imaginary non-tilted square boxes and subtract the surrounding area). Last fiddled with by LaurV on 2019-07-02 at 08:33 |
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#15 |
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Jun 2003
22×3×421 Posts |
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#16 |
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Romulan Interpreter
Jun 2011
Thailand
258B16 Posts |
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#17 |
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Oct 2017
5·23 Posts |
Am I right with the following summing up:
Each vertex is belonging to two edges (and not more!). It is forbidden that 3 consecutive points lie in a straight line, because : „Two edges meeting at a corner are usually required to form an angle that is not straight (180°); otherwise, the collinear line segments will be considered parts of a single side.“ (Wiki, simple polygon) |
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#18 |
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Jan 2017
32·11 Posts |
I don't believe the intent was to forbid two consecutive jumps in the same direction.
You could interpret it as saying that the geometric shape surrounded by the path must be a simple polygon. Said simple polygon might have fewer vertices than there are jumps in the path, if consecutive jumps are in the same direction. |
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#19 | |
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Oct 2017
5×23 Posts |
Quote:
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#20 |
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"Hugo"
Jul 2019
Germany
31 Posts |
Nothing was said about the side lengths of the path polygon, so any number of consecutive moves in the same direction is allowed.
"board of size mXn" was chosen instead of "board of area ...." to avoid interference with the enclosed area of the knight's path. |
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#21 |
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"Kebbaj Reda"
May 2018
Casablanca, Morocco
89 Posts |
for those who have found the solution.
and who is bored like me. try to find instead of a difference in area 7. the product of both areas 195. |
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#22 | |
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Oct 2017
5·23 Posts |
Quote:
It‘s no problem to find shapes with area 13 respectively 15. Or I have misunderstood your problem... |
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