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#23 |
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Undefined
"The unspeakable one"
Jun 2006
My evil lair
140648 Posts |
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#24 |
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"Rashid Naimi"
Oct 2015
Remote to Here/There
3·5·137 Posts |
From a mathematical point of view a denomination structure based on binary values ($1, $2, $4, ...coinage) would be the optimally inefficient model.
What would be the most efficient? On the second thought the most inefficient would be denomination of $1 only. ETA Depending on how we define efficiency, it could be a coinage with denominations for every integer upto some anticipated maximum. That way there would be a single coin that world be equal to any value. So you could always (if you wanted to) carry around all your wealth as a single coin, regardless of how wealthy or poor you are. Last fiddled with by a1call on 2019-05-24 at 22:30 |
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#25 |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
36×13 Posts |
Back in the USSR, we had 1, 2, 3, 5, 10, 15 (!!). 20, 50 cent coins and 1, 3 (!!), 5, 10. 25 (!!). 50, 100 roubles.
15 cent piece comes all the way back from Czarist Russia; there was even a word for it, a "pyatialtynnyj", where "altyn" is 3 cents (nobody has likely ever heard these words in modern Russia) |
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#26 | |
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∂2ω=0
Sep 2002
República de California
103×113 Posts |
Quote:
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#27 | ||
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Sep 2003
A1916 Posts |
Quote:
Quote:
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#28 |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
36×13 Posts |
Fiji has a 7 dollar bill.
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#29 |
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Romulan Interpreter
Jun 2011
Thailand
258B16 Posts |
The most efficient would be coins in golden ratio
![]() This can be mathematically proven, hehe, but it would depend of how you define "efficient". During our youth, under "commi" government, we had denominations similar to what Serge said, at the time you could still buy something (like a candy, a small copybook, a pretzel, a ballpoint pen refill tube, etc) with the "15 bani" - a value of 2-3 US cents in the '70s. Last fiddled with by LaurV on 2019-05-26 at 09:02 |
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#30 |
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Apr 2010
Over the rainbow
23·52·13 Posts |
should you use odd value only, it should be 1-3-7, the objective being using 3 denomination of the same order at max for all the value inside the range it. say, for example, you want a half of a baguette ( yes, i'm french) with exact change.It cost 48 cent(all taxes included) .
1-3-7 10+30+7+1 : 4 coins 1-2-5 5+2+1+20*2 : 5 coins 1-5-10-25-50 25+10+10+5+1*3 : 7 coins 1,2,3,5,10,15,20,50 3+10+15+20: 4 coins now I know in N America, the price would be 50 cent, without taxes... but that is not the point ;p |
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#31 | |
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Undefined
"The unspeakable one"
Jun 2006
My evil lair
140648 Posts |
Quote:
So to keep the profits rolling in we can add two cents and say we are helping the buyer to make life easier for them. It is totally for the buyers benefit, we promise. It isn't so we can make more profit. But if we have to suffer with more profit then okay we will do it if it helps the buyer. |
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#32 |
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"Rashid Naimi"
Oct 2015
Remote to Here/There
3×5×137 Posts |
You will not find any bakeries in my neck of the woods in N. America that will sell you half of a baguette. Judging by how much we weigh on average, that is no surprise.
![]() It is difficult for me to formulate the constraints that would define an efficient denomination structure. It should be something along the lines of: * Minimum number of sub-dollar denominations that would allow you to have optimally minium number of coins, if you were to have the exact change for any value from 1¢ to 99¢. ETA With the current North American structure you would need: 3x25¢+2x10¢+1x5¢+4x1¢ Total of 10 coins. With a binary structure you would need: 1¢+2¢+4¢+8¢+16¢+32¢+64¢ Total of 7 coins. With a 3 based structure you would need: 2x1¢+2x3¢+2x9¢+27¢+81¢ Total of 8 coins. Last fiddled with by a1call on 2019-05-26 at 19:05 |
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#33 | ||
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Feb 2017
Nowhere
4,643 Posts |
Quote:
Thus, a "foolish consistency" indicates an unwillingness or inability to learn, or to disregard new information for the sake of ideological purity. Quote:
I refer to it occasionally, as when someone invited me to have a "puncheon" of ale (probably meaning a "flagon"). Among the entries: 1 (U.S.) fluid ounce (fl oz) = 1.8046875 cubic inches (in^3) 1 (U.S.) fluid (liquid) pint (fl pt)= 16 fl oz = 28.875 in^3 1 (U.S.) fluid (liquid) quart (fl qt) = 2 fl pt = 57.75 in^3 1 (U.S.) gallon (gal) = 4 fl qt = 8 fl pt = 128 fl oz = 231 in^3 [Note: the gallon of 231 in^3 is the U.S. standard liquid measure.] 1 British or Imperial quart = 69.354 in^3 = 1.201 U.S. fl qt 1 British or Imperial gallon = 277.42 in^3 = 1.201 U.S. gal [Note: A British or Imperial pint would be half an Imperial quart, so 1.201 U.S. fl pt, or about 19.2 fl oz. However, the British or Imperial fluid ounce is defined so that a British or Imperial gallon is 160 British or Imperial fluid ounces, as opposed to 128 U.S. fluid ounces in a U.S. gallon. Thus a British or Imperial pint would be 20 British or Imperial fluid ounces.] -------------------------------------------------------------------------- APOTHECARIES' FLUID MEASURE: The Apothecaries' fluid ounce, pint, quart and gallon are the same as for U.S. liquid measure. However, the fluid ounce is subdivided as follows: 1 fluid dram = 60 minims = 1/8 fl oz 1 fl oz = 8 fl drs = 480 minims Thus 1 fl pt = 128 fl drs and 1 gal = 1024 fl drs. -------------------------------------------------------------------------- WINE OR LIQUID MEASURE -- used for all liquids except beer, ale and (formerly) milk. The ounce, pint, quart and gallon are the same as for U.S. liquid measure. 1 gill = 4 oz; 1 pt = 4 gills (gi) 1 barrel (bl) = 31 & 1/2 gal 1 tierce (tr) = 42 gal 1 hogshead (hhd) = 2 bl = 63 gal 1 puncheon (pn) = 2 tr = 84 gal 1 pipe (p) = 2 hhd = 3 tr = 4 bl = 126 gal 1 tun (T) = 4 hhd = 8 bl = 252 gal [sometimes a tun is larger.] -------------------------------------------------------------------------- ALE OR BEER MEASURE -- for beer and ale (and formerly milk also). The BEER GALLON is 282 in^3, not the U.S. standard 231 in^3 gallon! It is divided into 4 quarts, and the quart into 2 pints. 1 beer pint = 35.25 in^3 1 beer quart = 2 beer pints = 70.5 in^3 1 barrel = 36 beer gallons 1 hogshead = 54 beer gallons -------------------------------------------------------------------------- MISCELLANEOUS CUBIC MEASURES 1 teaspoon (tsp) = 1/6 fl oz, 5 ml approx 1 fifth = 1/5 gal = 46.2 in^3 [usually for distilled liquor] 1 Magnum = a 2-quart bottle of wine or champagne 1 acre-foot = 43560 cu ft (a volume of water 1 ft deep, covering 1 acre.) Last fiddled with by Dr Sardonicus on 2019-05-29 at 14:47 Reason: Relocating a sentence |
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