Formula for complex Mersenne numbers found!!!

[CRGreathouse]

Originally Posted by samuel

ok ok i get it i get it i should not blame it on the hardware i am so sorry tservo dcheuk prime95 thank you guys all of you for using ur titan graphics and i7s and other monsters to check the first two numbers. i should not have do that blame it on the hardware

You could blame hardware, but if you study the probabilities you'd see that it's unlikely to be the problem.

Originally Posted by samuel

and for crgreathouse, if the second number comes out to be not prime my algorithm is bad and should be tossed, total defeat, white flag. i learned, let me live, have mercy

That's actually probably the right response. I wouldn't blame you at all if you wanted to continue the search and check a few exponents yourself -- hope springs eternal -- but there are good reasons for the skepticism of the other forum members. (Of course, if the number turns out to be prime, I'll swallow my pride and admit that there very probably is something special going on.)

Originally Posted by samuel

i learned a lot about math here surprisely on an internet forum

Good! I included a number of links in my last post in hopes that, if a topic stood out to you, you would be able to read more about it. I tried to keep them at an accessible level.

[xilman]

Originally Posted by samuel

x^a-y^b=1 ----> x^a=1+y^b ------->x=(1+y^b)^(1/a)
didn't you already answered your question? that is the ONLY solution.

I did not answer my own question. I demonstrated that (3,2,2,3) is one solution. I did not prove that it is the ONLY solution.

You re-arranged the terms of the equation correctly. You did not prove that there are no more solutions. Please prove that (1+y^b) can never be a-th power of an integer unless y=2,b=3 and a=2.

Keep going.

[lukerichards]

I'd like to recommend again that Samuel contribute a guess to:

https://mersenneforum.org/showthread...hlight=predict

Samuel - this is a thread where we try to predict the next Mersenne prime. It is a bit of fun, not expected to be correct, but it might be worth you entering.

any updates to the second number? i am very anxious to see it is prime!

Originally Posted by xilman

I did not answer my own question. I demonstrated that (3,2,2,3) is one solution. I did not prove that it is the ONLY solution.

You re-arranged the terms of the equation correctly. You did not prove that there are no more solutions. Please prove that (1+y^b) can never be a-th power of an integer unless y=2,b=3 and a=2.

Keep going.

uh because the difference between any integer combinations raise to any power greater than 1 is always greater than 1.

Originally Posted by CRGreathouse

You could blame hardware, but if you study the probabilities you'd see that it's unlikely to be the problem.



That's actually probably the right response. I wouldn't blame you at all if you wanted to continue the search and check a few exponents yourself -- hope springs eternal -- but there are good reasons for the skepticism of the other forum members. (Of course, if the number turns out to be prime, I'll swallow my pride and admit that there very probably is something special going on.)



Good! I included a number of links in my last post in hopes that, if a topic stood out to you, you would be able to read more about it. I tried to keep them at an accessible level.

i think my pride hangs on the balance on this second prime number, i still get to call myself a genius if it turns out to be prime though hahaha

[Uncwilly]

Originally Posted by samuel

i think my pride hangs on the balance on this second prime number, i still get to call myself a genius if it turns out to be prime though hahaha

If not you have to buy us all a round of drinks.

[jnml]

Originally Posted by samuel

i think my pride hangs on the balance on this second prime number, i still get to call myself a genius if it turns out to be prime though hahaha

Whatever makes you happy.

Nonetheless, I think most geniuses are smart enough to figure out that bragging about
themselves being genius is not much of a smart idea.

[VBCurtis]

Originally Posted by samuel

uh because the difference between any integer combinations raise to any power greater than 1 is always greater than 1.

All you did was restate the claim. That's not a reason. Why is this true? Or, how do you *know* it is true, rather than just saying it is?

[chalsall]

Originally Posted by VBCurtis

All you did was restate the claim. That's not a reason. Why is this true? Or, how do you *know* it is true, rather than just saying it is?

Sorry for speaking into the vacuum, but he doesn't know.

I will probably be sanctioned for daring to speak out of turn, but this is intentional distractionary misdirection.

[tServo]

Originally Posted by samuel

any updates to the second number? i am very anxious to see it is prime!

In about 80 minutes or so @ 9 eastern time.