M51 arithmetic - Page 8

henryzz · 2019-01-18, 09:41

276 = (8-2)*5*8+9*(9+3)/3

278 = (8-2)*5+8+9*9*3-3
279 = -(8+2-5*8)*9 + L3D[9]
280 = 8+2*(5+8)+9*9*3+3

282 = (8+2)*5-8+9*9*3-3
283 = (8*2)*(5+8)+9*9-3-3

21 = -9+9*3+3
24 = 9*9/3-3
30 = 9*9/3+3
33 = 9+9*3-3
36 = 9*(9+3)/3
39 = 9+9*3+3

retina · 2019-01-18, 10:35

Quote:

Originally Posted by henryzz

280 = 8+2*(5+8)+9*9*3+3

Also this:

280 = 8*(2*(5+8)+9) {+/- extension}

And this:

288 = (8-(2-5)*8)*9 {+/- extension}

ETA:

294 = (8-2)*(5*8+9) {+/- extension}

henryzz · 2019-01-18, 12:14

300 = (-8+2+5*8)*9 + L3D[-6]
306: 302 to 310 = (-8+2+5*8)*9 + L3D[-4 to 4]

henryzz · 2019-01-18, 12:22

Even better:

304: 299 to 317 = 8*(-2+5*8) + L4D[-13 to 13]

retina · 2019-01-18, 13:38

336 = 8*(2+5*8) + L4D[-13 to 13]

henryzz · 2019-01-21, 11:52

This one solves a lot of multiples of 80:
320 = 8*2*5*(8-L4D[4])

And multiples of 50:
350 = (8+2)*5*(8-L4D[1])

352: 350 to 356 = 8*2*(5+8+9) + L3D[-3 to 4]

retina · 2019-01-21, 12:19

Using only division:

160 = 8/(2/5/(8/(9/(9/(3/3)))))

It doesn't solve anything extra.

retina · 2019-01-21, 12:43

Some more divisions

1440 = 8/(2/5/8/(9/(9/3/3)))
12960 = 8/(2/5/8/9/(9/(3/3)))
116640 = 8/(2/5/8/9/9/3/3)

henryzz · 2019-01-22, 15:20

I am struggling to find results around this sort of size.
358 = -8+2+5*8+9*(9+3)*3

retina · 2019-01-22, 15:40

357 = 8-2+5*8*9-(9-(3-3))
357 = 8-2+5*8*9-(9+3)+3
357 = 8-2+5*8*9-(9+3-3)
357 = 8-2+5*8*9-(9-3)-3
357 = 8-2+5*8*9-(9-3+3)
357 = 8-2+5*8*9-9*3/3
357 = 8-2+5*8*9-9/(3/3)
357 = 8-2+5*8*9-9/3*3

So many ways to generate 9 with those last three digits.

henryzz · 2019-01-22, 16:07

How didn't I spot that trivial 5*8*9=360?

2019-01-18, 09:41	#78
henryzz Just call me Henry "David" Sep 2007 Cambridge (GMT/BST) 2³·3·5·7² Posts	276 = (8-2)58+9(9+3)/3 278 = (8-2)5+8+993-3 279 = -(8+2-58)9 + L3D[9] 280 = 8+2(5+8)+993+3 282 = (8+2)5-8+993-3 283 = (82)(5+8)+99-3-3 21 = -9+93+3 24 = 99/3-3 30 = 99/3+3 33 = 9+93-3 36 = 9(9+3)/3 39 = 9+93+3 Last fiddled with by henryzz on 2019-01-18 at 09:47*

2019-01-18, 12:14	#80
henryzz Just call me Henry "David" Sep 2007 Cambridge (GMT/BST) 2³·3·5·7² Posts	300 = (-8+2+58)9 + L3D[-6] 306: 302 to 310 = (-8+2+58)9 + L3D[-4 to 4] Last fiddled with by henryzz on 2019-01-18 at 12:15

2019-01-21, 11:52	#83
henryzz Just call me Henry "David" Sep 2007 Cambridge (GMT/BST) 2³·3·5·7² Posts	This one solves a lot of multiples of 80: 320 = 825(8-L4D[4]) And multiples of 50: 350 = (8+2)5(8-L4D[1]) 352: 350 to 356 = 82(5+8+9) + L3D[-3 to 4] Last fiddled with by henryzz on 2019-01-21 at 12:26*

2019-01-22, 15:40	#87
retina Undefined "The unspeakable one" Jun 2006 My evil lair 2²×1,549 Posts	A whole bunch of 357s 357 = 8-2+589-(9-(3-3)) 357 = 8-2+589-(9+3)+3 357 = 8-2+589-(9+3-3) 357 = 8-2+589-(9-3)-3 357 = 8-2+589-(9-3+3) 357 = 8-2+589-93/3 357 = 8-2+589-9/(3/3) 357 = 8-2+589-9/33 So many ways to generate 9 with those last three digits.

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2019-01-18, 12:22	#81
henryzz Just call me Henry "David" Sep 2007 Cambridge (GMT/BST) 16F8₁₆ Posts	Even better: 304: 299 to 317 = 8(-2+58) + L4D[-13 to 13]

2019-01-18, 13:38	#82
retina Undefined "The unspeakable one" Jun 2006 My evil lair 1834₁₆ Posts	336 = 8(2+58) + L4D[-13 to 13]

2019-01-21, 12:19	#84
retina Undefined "The unspeakable one" Jun 2006 My evil lair 2²×1,549 Posts	Using only division: 160 = 8/(2/5/(8/(9/(9/(3/3))))) It doesn't solve anything extra.

2019-01-21, 12:43	#85
retina Undefined "The unspeakable one" Jun 2006 My evil lair 2²·1,549 Posts	Some more divisions 1440 = 8/(2/5/8/(9/(9/3/3))) 12960 = 8/(2/5/8/9/(9/(3/3))) 116640 = 8/(2/5/8/9/9/3/3)

2019-01-22, 15:20	#86
henryzz Just call me Henry "David" Sep 2007 Cambridge (GMT/BST) 2³·3·5·7² Posts	I am struggling to find results around this sort of size. 358 = -8+2+58+9(9+3)*3

2019-01-22, 16:07	#88
henryzz Just call me Henry "David" Sep 2007 Cambridge (GMT/BST) 13370₈ Posts	How didn't I spot that trivial 589=360?