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Old 2018-12-17, 08:52   #67
enzocreti
 
Mar 2018

10228 Posts
Default never mind

never mind it is easy to proof


any explanation instead for this:
when pg(43k) is prime and k is odd as in the case of pg(215), then 43k is congruent to 7 mod 13.
when pg(43k) is prime and k is even as in the case of pg(69660), then 43k is 6 mod 13.

Last fiddled with by enzocreti on 2018-12-17 at 11:16 Reason: typo
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Old 2018-12-17, 10:50   #68
enzocreti
 
Mar 2018

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Default prime

pg(215) is congruent to the prime 21015781248582109976561479237247175760828678449588166559266766851 mod (2^214-1)
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Old 2018-12-17, 13:23   #69
enzocreti
 
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Default 51456 and 541456

are all coincidences?

Last fiddled with by enzocreti on 2018-12-17 at 13:26
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Old 2018-12-17, 14:14   #70
enzocreti
 
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Default 51456 and 541456

pg(51456) and pg(541456) are both primes. If I am right, both the probable primes are of the form 8400s+367.
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Old 2018-12-17, 14:52   #71
enzocreti
 
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Default pg(51456) and pg(541456)

the probable primes pg(51456) and pg(541456) end both with digits 55967! by the way 55967 is prime

Last fiddled with by enzocreti on 2018-12-17 at 15:01
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Old 2018-12-17, 17:49   #72
enzocreti
 
Mar 2018

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Default 51456 and 541456

as I said it is at least curious that pg(51456) and pg(541456) are both primes and 541456=700^2+51456
moreover 541456 and 51456 are both congruent to 111 mod 35
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Old 2018-12-17, 17:56   #73
enzocreti
 
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Default ...moreover...

moreover (541456-13999)/7=75351
(51456-13999)/7=5351
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Old 2018-12-17, 18:14   #74
science_man_88
 
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Default

Quote:
Originally Posted by enzocreti View Post
as I said it is at least curious that pg(51456) and pg(541456) are both primes and 541456=700^2+51456
moreover 541456 and 51456 are both congruent to 111 mod 35
All both numbers being 111 mod 35 means, is that their difference is divisible by 35, 490000 = 350000+2*35000+2*3500 so what. since 35 divides into 700 , there's no real mystery other than what makes both pg numbers prime. which if the two values chosen are highly composite numbers or have neighbors that fill in the gaps, then it increases their likelihood to be prime potentially. As the Mersenne numbers concatenated have a lot of factors if their exponents do. So most of the mystique goes away.

Last fiddled with by science_man_88 on 2018-12-17 at 18:15
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Old 2018-12-17, 18:31   #75
enzocreti
 
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Default pg(51456) and pg(541456)

mod(pg(51456),350000)=5967
mod(pg(541456),350000)=255967
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Old 2018-12-17, 19:33   #76
enzocreti
 
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Default pg(215),pg(69660),pg(92020) and pg(541456)

pg(215),pg(69660),pg(92020) and pg(541456) are the probable primes where k is a multiple of 43. Infact:

pg(43*5) is prime
pg(43*1620) is prime
pg(43*2140) is prime
pg(43*12592) is prime

now note that 5 (odd) is congruent to -8 mod 13
1620 (even) is congruent to 8 mod 13
2140 (even) is congruent to 8 mod 13
12592 (even) is congruent to 8 mod 13
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Old 2018-12-17, 20:04   #77
enzocreti
 
Mar 2018

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Default pg(67) and pg(51456)

pg(67=67*1) and pg(51456=67*768) are probable primes

1 is congruent to 1 mod 13
768 is congruent to 1 mod 13
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