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#1 |
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Mar 2018
72·11 Posts |
A mathexchange user found that 111010111 divides ((2^3343663-1)*10^1006543+2^3343662-1), the concatenation of two consecutive Mersenne numbers!
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#2 |
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Mar 2018
53910 Posts |
Somebody can find other factors of this number? Besides 691 and naturally 111010111
Last fiddled with by enzocreti on 2018-12-10 at 12:51 |
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#3 |
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Banned
"Luigi"
Aug 2002
Team Italia
486510 Posts |
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#4 |
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Mar 2018
72·11 Posts |
just for fun and because i guess that the next factor is a 666666666...7 prime!
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#5 |
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Banned
"Luigi"
Aug 2002
Team Italia
5·7·139 Posts |
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#6 |
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Aug 2006
22·3·499 Posts |
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