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Old 2018-12-08, 08:31   #23
axn
 
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Quote:
Originally Posted by a1call View Post
IINM That only works on the Linux versions.
Possibly, if you installed using Windows installer, the feature is not enabled by default. But I (almost) always use the standalone executable, and they come with this enabled.

Code:
GP/PARI CALCULATOR Version 2.12.0 (development 22943-2eb50d55b)
  amd64 running mingw (x86-64/GMP-6.1.2 kernel) 64-bit version
  compiled: Aug 22 2018, gcc version 7.3-win32 20180506 (GCC)
                    threading engine: single
         (readline v6.2 enabled, extended help enabled)
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Old 2018-12-09, 20:40   #24
enzocreti
 
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Default HOW TO REACH EXPONENT 1 MILLION

I conjectured that there is no probable prime 6 mod 7 of the form (2^k-1)*10^d+2^(k-1)-1. How can I test this conjecture up to at least k=1.000.000?

Last fiddled with by enzocreti on 2018-12-09 at 20:40
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Old 2018-12-09, 20:43   #25
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Quote:
Originally Posted by enzocreti View Post
I conjectured that there is no probable prime 6 mod 7 of the form (2^k-1)*10^d+2^(k-1)-1. How can I test this conjecture up to at least k=1.000.000?
find the pattern of when it can be 6 mod 7 and test through sets of conditions. show them failing the testing to be probable primes etc.
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Old 2018-12-10, 07:31   #26
enzocreti
 
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Default 6 mod 7 probable prime

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Originally Posted by science_man_88 View Post
find the pattern of when it can be 6 mod 7 and test through sets of conditions. show them failing the testing to be probable primes etc.
According to a mathexchange user, there shouldn't be any probable prime 6 mod 7 up to k=800.000
I wonder how much far we should arrive for finding one!
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Old 2018-12-10, 07:47   #27
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According to a bearded guy who was pushing a shopping cart full of tin cans, the number you are looking for is around 937,500.
But why should one be gullible enough to listen to that guy?
...Or that other guy that you mentioned?
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Old 2018-12-10, 07:50   #28
enzocreti
 
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Default 6 mod 7

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Originally Posted by Batalov View Post
According to a bearded guy who was pushing a shopping cart full of tin cans, the number you are looking for is around 937,500.
But why should one be gullible enough to listen to that guy?
...Or that other guy that you mentioned?

I don't understand...i trust him...he found also a probable prime of this form for k=541456.
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Old 2018-12-10, 11:18   #29
enzocreti
 
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Default palindromic prime

palindromic prime 111010111 divides (2^3343663-1)*10^1006543+2^3343662-1!!!
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Old 2018-12-10, 12:28   #30
enzocreti
 
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Default factors

besides 111010111 and 691, what are the other factors of this huge number?
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Old 2018-12-17, 10:40   #31
MisterBitcoin
 
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Quote:
Originally Posted by enzocreti View Post
besides 111010111 and 691, what are the other factors of this huge number?
Quote:
Originally Posted by axn View Post
No factors till 32*10^9. Quitting my attempt.
According to axn´s post, the status of the number is unknown.
As expected, it is not an PRP.

Code:
(2^7891456-1)*10^2375565+2^7891455-1 is composite: RES64: [8DA21E99C6B92C74] (790809.4526s+0.6214s)
Do me a favor, and double check this result. Check this forum, you will find all what you need. No tips.

Last fiddled with by MisterBitcoin on 2018-12-17 at 10:40 Reason: Spacing....
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