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#1 |
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Mar 2018
2×5×53 Posts |
Concatenate 2^k-1 and 2^(k-2)-1. Example 71, 153,...can you find a prime congruent to 4 or 3 mod 7?
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#2 |
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Feb 2017
Nowhere
464310 Posts |
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#3 |
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"Daniel Jackson"
May 2011
14285714285714285714
3·13·17 Posts |
Here's the remainders of the first few numbers of that form:
Code:
71 mod 7 = 1 153 mod 7 = 6 317 mod 7 = 2 6315 mod 7 = 1 12731 mod 7 = 5 25563 mod 7 = 6 511127 mod 7 = 1 1023255 mod 7 = 2 2047511 mod 7 = 4 40951023 mod 7 = 1 81912047 mod 7 = 0 163834095 mod 7 = 5 327678191 mod 7 = 1 6553516383 mod 7 = 1 13107132767 mod 7 = 1 26214365535 mod 7 = 1 524287131071 mod 7 = 4 |
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#4 |
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Mar 2018
2×5×53 Posts |
the possible remainders are 0,1,2,3,4,5,6 (3 with frequency 1/18)
Can you find a prime with residue 3 or 4? |
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#5 |
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Just call me Henry
"David"
Sep 2007
Cambridge (GMT/BST)
23·3·5·72 Posts |
PRPs:
Code:
M(3)M(1) 1 M(5)M(3) 2 M(25)M(23) 6 M(33)M(31) 1 M(143)M(141) 2 M(165)M(163) 1 M(285)M(283) 1 M(321)M(319) 1 M(323)M(321) 2 M(1003)M(1001) 5 M(1683)M(1681) 1 M(1921)M(1919) 5 M(4223)M(4221) 1 M(5451)M(5449) 1 M(6783)M(6781) 1 |
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