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#12 |
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"Forget I exist"
Jul 2009
Dumbassville
26×131 Posts |
Closest thing I see is that 2,3,5,17,23,31 don't divide it. Assuming it sums to the same number ( they do but 0 mod 511 is irrelevant).
Last fiddled with by science_man_88 on 2018-04-17 at 00:18 |
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#13 | |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
36×13 Posts |
Quote:
(r+s)^2 = 2s^2 mod f ((u+v)/v)^2 = ((r+s)/s)^2 = 2 mod f ((u+v)/v)^2 - ((r+s)/s)^2 = 0 mod f ((u+v)/v - (r+s)/s) * ((u+v)/v + (r+s)/s) = 0 mod f (u/v - r/s) * (u/v + r/s + 2) = 0 mod f So, do gcd( u/v - r/s , f ) and gcd( u/v + r/s +2 , f ) (unless they are trivial) and see. In your example: Code:
? uv=Mod(16,511)/15 Mod(478, 511) ? rs=Mod(20,511)/3 Mod(177, 511) ? gcd(478-177, 511) 7 ? gcd(478+177+2, 511) 73 |
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#14 |
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Mar 2016
15916 Posts |
A pleasant night for you, Batalov
and thanks a lot for this clear explication. ![]() ![]()
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