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#1 |
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Mar 2016
3×5×23 Posts |
A peaceful evening for all,
Is it possible to find a prime generating sieving algorithm for the following described function: http://devalco.de/poly_xy.php Have a lot of fun ![]() ![]() ![]() Bernhard |
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#2 | ||
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"Forget I exist"
Jul 2009
Dumbassville
26·131 Posts |
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Quote:
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#3 | |
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Mar 2016
3×5×23 Posts |
A peaceful day for all,
Quote:
Hint 1: Fix either u or v for the function f(u,v) and examine the prime distribution. There is a pattern, you could find. ![]() http://devalco.de/poly_xy.php Have a lot of fun by examing the prime distribution Bernhard ![]() ![]()
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#4 | |
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Mar 2016
3×5×23 Posts |
Quote:
You can use this primesieve for a better primesieve concerning http://devalco.de/poly_xy.php There will be a third hint in some few days, and concerning the participation a suggestion for a first solution. There might be several solution, you have the first choice ![]() ![]() ![]() Greeting from the primes Bernhard |
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#5 | |
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"Forget I exist"
Jul 2009
Dumbassville
838410 Posts |
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#6 |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
36×13 Posts |
This looks like Misc.Math.
(it is obviously not a puzzle, just a bunch of fluff plus shameless self-promotion to boot.) |
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#7 |
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Mar 2016
34510 Posts |
"Anyone who has "discovered" a pattern or found order in disorder,ie. feigenbaum constants, are justified in feeling
a sense of pride and accomplishment for this personal insight. " from jwaltos (http://www.mersenneforum.org/showpos...9&postcount=25) I am very thankful for these words. An explication for the proposed pattern for the function f(u,v)=u^2 + 2uv - v2 : You can simplify by fixing either u or v and you get a quadratic function with one variable. You could use this "slices" horizontal and vertikal. for every p with p | f(n)=an^2+bn+c (a<5; a,b,c element N) follows that p | f(n+p) and p | f(-n-b/a) The primes p with p | f(u,v) appears double periodically horizantal and vertikal. In order to understand this i have tried to give an "amazing" applet http://devalco.de/poly_xy.php you can click on the primes 7, 17, 23, 31 and so on The primes p of the function f(u,v)=u^2 + 2uv - v2 build corally a pattern. The remaining question is: in which order you can make a sieving (dividing by the primes) As the pattern is clear, the solution for the algorithm will come in 3 days. Bernhard @Batalov I support Gimps, LL-D test place 164 |
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#10 |
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Mar 2016
3×5×23 Posts |
A peaceful evening for all,
a proposition for a primesieve concerning f(u, v)=u² + 2uv -v² : 1. Make a primesieve concerning the function f(u, u-1) = 2u²-1 from u=2 to u_max (there is a detailled description under http://devalco.de/quadr_Sieb_2x%5E2-1.php Safe all sieved out primes p with p < u_max, these primes appear in all quadratic functions with f(u, v) where u goes from 2 to u_max. (This should be the amount Q) 2. Make a sieving (vertikal) for f(u, 1)= u²+2u-1 by using the presieved primes Q 3. Make a sieving (vertikal) for f(u, 2)= u²+4u-4 by using the presieved primes Q 4. Make a sieving (vertikal) for f(u, 3)= u²+6u-9 by using the presieved primes Q .... u-2. Make a sieving (vertikal) for f(u, u-2)= u²+2(u-1)-(u-2)² by using the presieved primes Q The sieving is made by dividing the function f(u,v) by the primes Q. Do you have any idea why this prime sieve could be better than the prime generator for the function f(n)=2n²-1 ? @Batalov It looks like Misc. Math is a cold, dark and windy place, do you have a more decent place for the thread ? Or please give a mathematical reason. |
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