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#1 |
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"Matthew Anderson"
Dec 2010
Oregon, USA
25×52 Posts |
Hi MersenneForum,
I was doodling with a spreadsheet program. Can anyone find the missing number in this sequence? 1,4,32,224,1600,?,81152,578048, ... Also, what is the general form that will produce more numbers in the sequence? Best of luck. Regards, Matt There are two arbitrary initial values |
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#2 | |
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"Forget I exist"
Jul 2009
Dumbassville
26·131 Posts |
Quote:
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#3 |
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Aug 2006
135338 Posts |
The missing number is 11392 and the formula is a(n) = 6a(n-1) + 8a(n-2). That also explains why the number of factors of 2 tends to increase.
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#4 |
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"Matthew Anderson"
Dec 2010
Oregon, USA
25·52 Posts |
Hi MersenneForum,
Thanks to all the readers and participants. Also, thanks to the Maple command 'rsolve' the expression F(r)=2*F(r-1)+4*F(r-2) can be expressed as shown in the second attachment. Let me know if a .png file is no good for you. Regards, Matt |
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#5 |
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"Matthew Anderson"
Dec 2010
Oregon, USA
25×52 Posts |
Hi Mersenneforum,
Some of you may be familiar with the radical expression that goes with the Fibonacci sequence. https://en.wikipedia.org/wiki/Fibona...e_golden_ratio This should be similar. Regards, Matt |
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#6 |
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Aug 2006
135338 Posts |
Yes. The bases of the exponential expression are the roots of the characteristic equation of the recurrence, x^2 - 6x - 8.
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#7 |
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Just call me Henry
"David"
Sep 2007
Cambridge (GMT/BST)
23×3×5×72 Posts |
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#8 |
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"Harry Willam"
May 2017
USA
22·5 Posts |
Option :-
A) 9 B) 8 C) 6 D) 0 ![]() ![]() Tell Me
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#9 |
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"Matthew Anderson"
Dec 2010
Oregon, USA
14408 Posts |
Hi Mersenneforum,
Many thanks to the responses so far. As a learning exercise it would be nice to know the steps between a 'recurrence relation of the first kind' and its 'characteristic equation'. From the Wikipedia article on Lucas Sequence, we see this - Explicit expressions, The characteristic equation of the recurrence relation for Lucas sequences x^2 - Px + Q = 0 Must go. Matt |
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#10 |
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Aug 2006
3·1,993 Posts |
The characteristic equation of a recurrence of the form
a(n) = A*a(n-1) + B*a(n-1) + C*a(n-2) + D*a(n-3) is x^4 - Ax^3 - Bx^2 - Cx - D and you extend this to lower or higher degree in the obvious way. |
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#11 | |
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Sep 2002
Database er0rr
3,739 Posts |
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