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#12 |
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"/X\(‘-‘)/X\"
Jan 2013
B7416 Posts |
That's if you submit a residue for the same exponent. But if someone is seeking credit, the smart thing to do would be to spread the fake residues out across many exponents. Eventually a match will be found.
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#13 |
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Jun 2015
Vallejo, CA/.
2·7·71 Posts |
Along with more than 100 incorrect results (maybe even more than 200) for one user, a match would be found eventually.
![]() Someone once said that it 10,000,000 monkeys banged 10 million pianos for 200,000,000 centuries one would eventually play the 4th movement of Beethoven 9th Symphony. |
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#14 |
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Romulan Interpreter
Jun 2011
Thailand
7×1,373 Posts |
This is false, and the proof is the invention of internet. Two billion monkeys in front of the keyboards for almost a century, and nobody wrote a Shakespeare yet...
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#15 | |
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Romulan Interpreter
Jun 2011
Thailand
258B16 Posts |
Quote:
![]() And if you are after lots of DC credit, just submit lots of TCs for exponents already legally DCed (different users, etc). You still get the DC credit, this is for sure, and for free, and without a lot of trial/fail stuff...
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#16 |
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Einyen
Dec 2003
Denmark
35×13 Posts |
You cannot see the full residue until a match is found:
http://mersenne.org/M58930367 Unverified 2013-07-21 CJCorley 27E5644101AE86__ Unverified 2017-05-12 endless_mike FE321A206ADB61__ |
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#17 | |
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Jun 2015
Vallejo, CA/.
2·7·71 Posts |
Quote:
Last fiddled with by rudy235 on 2017-05-16 at 06:22 Reason: a missing comma. |
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#18 |
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Undefined
"The unspeakable one"
Jun 2006
My evil lair
22·1,549 Posts |
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#19 |
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Undefined
"The unspeakable one"
Jun 2006
My evil lair
22×1,549 Posts |
And the first monkey was Beethoven, with many subsequent monkeys afterwards. And it took a lot less than 200,000,000 centuries.
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#20 |
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"Forget I exist"
Jul 2009
Dumbassville
26·131 Posts |
not necessarily the odds of each one not matching is 255/256 so the odds of n independent guesses not matching is (255/256)^n which falls under 50% at about 178 guesses but is never 0% until n is infinite. the pigeonhole principle assuming all 2 digit endings are equally likely would suggest a 1 in 256 chance of matching for any given residue ending.
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#21 | |
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Sep 2003
5·11·47 Posts |
Quote:
Probably having only the last two hex digits masked is a legacy from the days when we were still verifying old pre-GIMPS results that had only four or five hex digit residues rather than the current sixteen. But all of those have long since been double checked to the full sixteen hex digits. |
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#22 |
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"Mike"
Aug 2002
25·257 Posts |
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