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#408 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2·13·113 Posts |
Quote:
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#409 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
B7A16 Posts |
1M < (CK for S66) <= 21314443
1M < (CK for S120) <= 374876369 1M < (CK for R66) <= 101954772 1M < (CK for R120) <= 166616308 |
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#410 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2×13×113 Posts |
Quote:
(20*88^q-1) * ((20*88^q+1)/3) Since n>=1, thus we have q>=1, and 20*88^q-1 >= 20*88^1-1 = 1759 > 1 (20*88^q+1)/3 >= (20*88^1+1)/3 = 587 > 1 Thus, this factorization is not trivial, and hence (400*88^n-1)/3 is composite for all even n. (Xayah) If n is odd, then n is congruent to either 1, 3, or 5 mod 6, however: If n = 1 mod 6, then (400*88^n-1)/3 is divisible by 3, and since n>=1, we have (400*88^n-1)/3 >= (400*88^1-1)/3 = 11733 > 3, thus (400*88^n-1)/3 is composite for all n = 1 mod 6. If n = 3 mod 6, then (400*88^n-1)/3 is divisible by 7 and greater than 7, thus (400*88^n-1)/3 is composite for all n = 3 mod 6. If n = 5 mod 6, then (400*88^n-1)/3 is divisible by 13 and greater than 13, thus (400*88^n-1)/3 is composite for all n = 5 mod 6. Thus, (400*88^n-1)/3 is composite for all odd n. (Rakan) By (Xayah) and (Rakan), (400*88^n-1)/3 is composite for all n>=1. |
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#411 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
1011011110102 Posts |
Quote:
S2: 3 (1) 7 (2) 12 (3) 19 (6) 31 (8) 47 (583) 383 (6393) 2897 (9715) 3061 (33288) 4847 (3321063) 5359 (5054502) 10223 (31172165) 21181 (>31600000) S3: 2 (1) 5 (2) 16 (3) 17 (6) 21 (8) 41 (4892) 621 (>10000) S4: 2 (1) 6 (2) 19 (3) 30 (4) 51 (46) 86 (108) 89 (167) 94 (291) 186 (10458) (next record k is > 794) S5: 2 (1) 3 (2) 18 (3) 19 (4) 34 (8) 40 (1036) 61 (6208) 181 (>12000) S6: 2 (1) 8 (4) 20 (5) 53 (7) 67 (8) 97 (9) 117 (23) 136 (24) 160 (3143) 1814 (>12000) S7: 2 (1) 5 (2) 9 (6) 21 (124) 101 (216) 121 (252) 141 (1044) (next record k is > 209) S8: 3 (2) 13 (4) 31 (20) 68 (115) 94 (194) 118 (820) 173 (7771) 259 (27626) 370? (>10000) S9: 2 (1) 6 (2) 17 (3) 21 (4) 26 (6) 40 (9) 41 (2446) 311? (>2000) S10: 2 (1) 8 (2) 9 (3) 22 (6) 34 (26) 269 (>24800) S11: 2 (1) 4 (2) 10 (10) 20 (35) 45 (40) 47 (545) 194 (>2000) S12: 2 (3) 17 (78) 30 (144) 37 (199) 261 (644) 378 (2388) 404 (714558) 563? (>5000) |
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#412 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
1011011110102 Posts |
Quote:
S136: CK=29180 S150: CK=49074 S192: CK=7879 S196: CK=16457 R136: CK=22195 R150: CK=49074 R192: CK=13897 R196: CK=1267 I still cannot find the CK for SR66 and SR120 :( |
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#413 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
1011011110102 Posts |
Quote:
S228: CK=1146 S232: CK=2564 S238: CK=34571 R228: CK=16718 R232: CK=27760 R238: CK=17926 Now, all CK for Sierpinski/Riesel bases b<=256 with b = 1, 3, 4, 5 (mod 6) were found, except SR190, I am now looking for the CK for SR190. Last fiddled with by sweety439 on 2017-08-26 at 15:23 |
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#414 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2×13×113 Posts |
Now, all CK for bases b<=256 are found except (in both two sides) b = 66, 120, 156, 180, 190, 210, 222, 240.
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#415 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
293810 Posts |
Quote:
S190: CK=2157728 S222: CK=333163 R190: CK=626861 R222: CK=88530 I have not tested other bases (b = 156, 180, 210, 240). Last fiddled with by sweety439 on 2017-08-26 at 17:19 |
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#416 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
293810 Posts |
My computer is now searching for generalized repunit primes (b^n-1)/(b-1) (see http://mersenneforum.org/showthread.php?t=21808), I will reserve this project (extended SR problems) after these searched were done.
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#417 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2·13·113 Posts |
In Riesel conjectures, if k=m^2 or k*b=m^2 and m and b satisfy at least one of these conditions, then this k should be excluded from the Riesel base b problem, since it has algebraic factors for even n (for the k=m^2 case) or odd n (for k*b=m^2 case) and it has a single prime factor for odd n (for the k=m^2 case) or even n (for the k*b=m^2 case).
Code:
m b = 2 or 3 mod 5 = 4 mod 5 = 5 or 8 mod 13 = 12 mod 13 = 3 or 5 mod 8 = 9 mod 16 = 4 or 13 mod 17 = 16 mod 17 = 12 or 17 mod 29 = 28 mod 29 = 7 or 9 mod 16 = 17 mod 32 = 6 or 31 mod 37 = 36 mod 37 = 9 or 32 mod 41 = 40 mod 41 = 23 or 30 mod 53 = 52 mod 53 = 11 or 50 mod 61 = 60 mod 61 = 15 or 17 mod 32 = 33 mod 64 = 27 or 46 mod 73 = 72 mod 73 = 34 or 55 mod 89 = 88 mod 89 = 22 or 75 mod 97 = 96 mod 97 = 10 or 91 mod 101 = 100 mod 101 = 33 or 76 mod 109 = 108 mod 109 = 15 or 98 mod 113 = 112 mod 113 = 31 or 33 mod 64 = 65 mod 128 = 37 or 100 mod 137 = 136 mod 137 = 44 or 105 mod 149 = 148 mod 149 = 28 or 129 mod 157 = 156 mod 157 = 80 or 93 mod 173 = 172 mod 173 = 19 or 162 mod 181 = 180 mod 181 = 81 or 112 mod 193 = 192 mod 193 = 14 or 183 mod 197 = 196 mod 197 = 107 or 122 mod 229 = 228 mod 229 = 89 or 144 mod 233 = 232 mod 233 = 64 or 177 mod 241 = 240 mod 241 = 63 or 65 mod 128 = 129 mod 256 = 16 or 241 mod 257 = 256 mod 257 etc. Last fiddled with by sweety439 on 2018-05-17 at 21:26 |
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#418 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
B7A16 Posts |
Quote:
Since these k's proven composite by full algebraic factors. Last fiddled with by sweety439 on 2020-08-07 at 16:02 |
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