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#353 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2×13×113 Posts |
Conjecture 1 (the strong Sierpinski conjecture): For b>=2, k>=1, if there is an n such that:
(1) k*b^n is neither a perfect odd power (i.e. k*b^n is not of the form m^r with odd r>1) nor of the form 4*m^4. (2) gcd((k*b^n+1)/gcd(k+1,b-1),(b^(9*2^s)-1)/(b-1)) = 1 for all s, i.e. for all s, every prime factor of (k*b^n+1)/gcd(k+1,b-1) does not divide (b^(9*2^s)-1)/(b-1). (i.e. ord_p(b) is not of the form 2^r (r>=0 if p = 2 or p = 3, r>=1 if p>=5), 3*2^r (r>=0) or 9*2^r (r>=0) for every prime factor p of (k*b^n+1)/gcd(k+1,b-1)). (3) this k is not excluded from this Sierpinski base b by the post #265. (the first 6 Sierpinski bases with k's excluded by the post #265 are 128, 2187, 16384, 32768, 78125 and 131072) Then there are infinitely many primes of the form (k*b^n+1)/gcd(k+1,b-1). Conjecture 2 (the strong Riesel conjecture): For b>=2, k>=1, if there is an n such that: (1) k*b^n is not a perfect power (i.e. k*b^n is not of the form m^r with r>1). (2) gcd((k*b^n-1)/gcd(k-1,b-1),(b^(9*2^s)-1)/(b-1)) = 1 for all s, i.e. for all s, every prime factor of (k*b^n-1)/gcd(k-1,b-1) does not divide (b^(9*2^s)-1)/(b-1). (i.e. ord_p(b) is not of the form 2^r (r>=0 if p = 2 or p = 3, r>=1 if p>=5), 3*2^r (r>=0) or 9*2^r (r>=0) for every prime factor p of (k*b^n-1)/gcd(k-1,b-1)). Then there are infinitely many primes of the form (k*b^n-1)/gcd(k-1,b-1). Last fiddled with by sweety439 on 2017-06-23 at 15:05 |
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#354 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2×13×113 Posts |
Quote:
Since if there is no such n, then this k must have covering set, be proven composite by full algebra factors, or be proven composite by partial algebra factors, thus, this k is excluded from this Sierpinski/Riesel base. Last fiddled with by sweety439 on 2017-06-23 at 15:10 |
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#355 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2×13×113 Posts |
Quote:
Thus, you can think that CRUS only includes the k's such that gcd(k+-1,b-1) = 1 (+ for Sierpinski, - for Riesel), since if gcd(k+-1,b-1) = 1 (+ for Sierpinski, - for Riesel), then this form is completely the same as the form for this k and this Sierpinski/Riesel base in CRUS. Last fiddled with by sweety439 on 2017-06-23 at 14:54 |
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#356 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2×13×113 Posts |
Quote:
For the n's such that (k*b^n+-1)/gcd(k+-1,b-1) is prime: (excluding MOB, since if k is multiple of the base (b), then k and k / b are from the same family, if k = k' * b^r, then the exponent n for this k is (the first number > r for k') - r, and the correspond prime for this k is the correspond prime for n = (the first number > r for k') for k') S2: k = 1: 1, 2, 4, 8, 16, ... (sequence is not in OEIS) k = 3: A002253 k = 5: A002254 k = 7: A032353 k = 9: A002256 k = 11: A002261 k = 13: A032356 k = 15: A002258 k = 17: A002259 k = 19: A032359 k = 21: A032360 k = 23: A032361 k = 25: A032362 k = 27: A032363 k = 29: A032364 k = 31: A032365 k = 33: A032366 k = 35: A032367 k = 37: A032368 k = 39: A002269 k = 41: A032370 k = 43: A032371 k = 45: A032372 k = 47: A032373 k = 49: A032374 k = 51: A032375 k = 53: A032376 k = 55: A032377 k = 57: A002274 k = 59: A032379 k = 61: A032380 k = 63: A032381 S3: k = 1: A171381 k = 2: A003306 k = 4: A005537 k = 5: 2, 6, 12, 18, 26, 48, 198, 456, ... (sequence is not in OEIS) k = 7: 1, 9, 33, 65, 337, ... (sequence is not in OEIS) k = 8: A005538 k = 10: A005539 k = 11: 1, 3, 21, 39, 651, ... (sequence is not in OEIS) k = 13: 2, 14, 32, 40, 112, ... (sequence is not in OEIS) k = 14: A216890 k = 16: 3, 4, 5, 12, 24, 36, 77, 195, 296, 297, 533, 545, 644, 884, 932, ... (sequence is not in OEIS) S4: k = 1: 1, 2, 4, 8, ... (sequence is not in OEIS) k = 2: A127936 k = 3: 1, 3, 4, 6, 9, 15, 18, 33, 138, 204, 219, 267, ... (sequence is not in OEIS) k = 5: 1, 3, 6, 12, 15, 18, 36, 72, 81, 84, 117, 522, 1023, 1083, 1206, ... (sequence is not in OEIS) k = 6: 2, 20, 94, 100, 104, 176, 1594, ... (sequence is not in OEIS) k = 7: A002255 S5: k = 1: 1, 2, 4, ... (sequence is not in OEIS) k = 2: A058934 k = 3: 2, 6, 8, 62, 120, 186, 414, 764, ... (sequence is not in OEIS) k = 4: A204322 k = 6: A143279 k = 7: (covering set {2, 3}) k = 8: 1, 1037, ... (sequence is not in OEIS) S6: k = 1: 1, 2, 4, ... (sequence is not in OEIS) k = 2: A120023 k = 3: A186112 k = 4: A248613 k = 5: A247260 k = 7: 1, 6, 17, 38, 50, 80, 207, 236, 264, 309, 555 ... (sequence is not in OEIS) k = 8: 4, 10, 16, 32, 40, 70, 254, ... (sequence is not in OEIS) S10: k = 1: 1, 2, ... (sequence is not in OEIS) k = 2: A096507 k = 3: A056807 k = 4: A056806 k = 5: A102940 k = 6: A056805 k = 7: A056804 k = 8: A096508 k = 9: A056797 k = 11: A102975 k = 12: 2, 38, 80, 9230, 25598, 39500, ... (sequence is not in OEIS) k = 13: A289051 k = 14: A099017 k = 15: 1, 4, 7, 8, 18, 19, 73, 143, 192, 408, 533, 792, 3179, 7709, 9554, 52919, 56021, 61604, ... (sequence is not in OEIS) k = 16: A273002 R2: k = 1: A000043 k = 3: A002235 k = 5: A001770 k = 7: A001771 k = 9: A002236 k = 11: A001772 k = 13: A001773 k = 15: A002237 k = 17: A001774 k = 19: A001775 k = 21: A002238 k = 23: A050537 k = 25: A050538 k = 27: A050539 k = 29: A050540 k = 31: A050541 k = 33: A002240 k = 35: A050543 k = 37: A050544 k = 39: A050545 k = 41: A050546 k = 43: A050547 k = 45: A002242 k = 47: A050549 k = 49: A050550 k = 51: A050551 k = 53: A050552 k = 55: A050553 k = 57: A050554 k = 59: A050555 k = 61: A050556 k = 63: A050557 R3: k = 1: A028491 k = 2: A003307 k = 4: A005540 k = 5: 1, 3, 5, 9, 15, 23, 45, 71, 99, 125, 183, 1143, ... (sequence is not in OEIS) k = 7: 2, 4, 6, 8, 16, 18, 28, 36, 52, 106, 114, 204, 270, 292, 472, 728, 974, ... (sequence is not in OEIS) k = 8: A005541 k = 10: A005542 k = 11: 22, 30, 46, 162, ... (sequence is not in OEIS) k = 13: 1, 5, 25, 41, 293, 337, 569, 1085, ... (sequence is not in OEIS) k = 14: 1, 11, 16, 80, 83, 88, 136, 187, 328, 397, 776, 992, 1195, ... (sequence is not in OEIS) k = 16: 1, 3, 9, 13, 31, 43, 81, 121, 235, 1135, 1245, ... (sequence is not in OEIS) R4: k = 1: (proven composite by full algebra factors) k = 2: A146768 k = 3: A272057 k = 5: 1, 2, 4, 5, 6, 7, 9, 16, 24, 27, 36, 74, 92, 124, 135, 137, 210, 670, 719, 761, 819, 877, 942, 1007, 1085, ... (sequence is not in OEIS) k = 6: 1, 3, 5, 21, 27, 51, 71, 195, 413, ... (sequence is not in OEIS) k = 7: 2, 3, 5, 12, 14, 41, 57, 66, 284, 296, 338, 786, 894, ... (sequence is not in OEIS) R5: k = 1: A004061 k = 2: A120375 k = 3: 1, 2, 4, 9, 16, 17, 54, 64, 112, 119, 132, 245, 557, 774, 814, 1020, 1110, ... (sequence is not in OEIS) k = 4: A046865 k = 6: A257790 k = 7: 1, 5, 11, 13, 15, 41, 61, 77, 103, 123, 199, 243, 279, 1033, 1145, ... (sequence is not in OEIS) k = 8: 2, 4, 8, 10, 28, 262, 356, 704, ... (sequence is not in OEIS) R6: k = 1: A004062 k = 2: A057472 k = 3: A186106 k = 4: 1, 3, 25, 31, 43, 97, 171, 213, 273, 449, 575, 701, 893, ... (sequence is not in OEIS) k = 5: A079906 k = 7: 1, 2, 3, 13, 21, 28, 30, 32, 36, 48, 52, 76, 734, ... (sequence is not in OEIS) k = 8: 1, 5, 35, 65, 79, 215, 397, 845, ... (sequence is not in OEIS) R10: k = 1: A004023 k = 2: A002957 k = 3: A056703 k = 4: A056698 k = 5: A056712 k = 6: A056716 k = 7: A056701 k = 8: A056721 k = 9: A056725 k = 11: A111391 k = 12: 5, 3191, 3785, 5513, 14717, ... (sequence is not in OEIS) k = 13: A056707 k = 14: 1, 2, 3, 4, 5, 16, 21, 23, 62, 175, 195, 206, 261, 347, 448, 494, 689, 987, 1361, 8299, 13225, 21513, 23275, ... (sequence is not in OEIS) k = 15: 1, 2, 15, 22, 27, 33, 38, 473, 519, 591, 699, 2273, 2476, 2985, 6281, 6947, 11990, 16828, 17096, 26236, 33459, 34963, ... (sequence is not in OEIS) k = 16: A056714 Last fiddled with by sweety439 on 2017-06-25 at 17:18 |
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#357 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2·13·113 Posts |
Pseudoprimes only exist when gcd(k+-1,b-1) (+ for Sierpinski, - for Riesel) is not 1, since the N-1 method (for Sierpinski when gcd(k+1,b-1) = 1) and N+1 method (for Riesel when gcd(k-1,b-1) = 1) can prove the primality, all of the primes with gcd(k+-1,b-1) (+ for Sierpinski, - for Riesel) = 1 are proven primes.
Last fiddled with by sweety439 on 2017-06-30 at 16:54 |
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#358 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
293810 Posts |
The records for the n are: (excluding the k's with covering set and the k's proven composite by full/partial algebra factors)
S2: 1 (1) 4 (2) 12 (3) 16 (4) 19 (6) 31 (8) 47 (583) 383 (6393) 2897 (9715) 3061 (33288) 4847 (3321063) 5359 (5054502) 10223 (31172165) 21181 (>31600000) S3: 1 (1) 5 (2) 16 (3) 17 (6) 21 (8) 41 (4892) 621 (>10000) S4: 1 (1) 6 (2) 19 (3) 30 (4) 51 (46) 86 (108) 89 (167) 94 (291) 186 (10458) (next record k is > 794) S5: 1 (1) 3 (2) 18 (3) 19 (4) 34 (8) 40 (1036) 61 (6208) 181 (>12000) S6: 1 (1) 8 (4) 20 (5) 53 (7) 67 (8) 97 (9) 117 (23) 136 (24) 160 (3143) 1296 (>=268435454) S7: 1 (4) 9 (6) 21 (124) 101 (216) 121 (252) 141 (1044) (next record k is > 209) S8: 2 (1) 3 (2) 13 (4) 31 (20) 68 (115) 94 (194) 118 (820) 173 (7771) 256 (>=2863311528) S9: 1 (1) 6 (2) 17 (3) 21 (4) 26 (6) 40 (9) 41 (2446) 311? (>2000) S10: 1 (1) 8 (2) 9 (3) 22 (6) 34 (26) 100 (>=33554430) S11: 1 (2) 10 (10) 20 (35) 45 (40) 47 (545) 194 (>2000) S12: 1 (1) 2 (3) 12 (>=33554431) R2: 1 (2) 13 (3) 14 (4) 43 (7) 44 (24) 74 (2552) 659 (800516) 2293 (>8300000) R3: 1 (3) 11 (22) 71 (46) 97 (3131) 119 (8972) 313 (24761) 1613 (>50000) R4: 2 (1) 7 (2) 39 (12) 74 (1276) 106 (4553) 659 (400258) (next record k is > 1114) R5: 1 (3) 2 (4) 31 (5) 32 (8) 34 (163) 86 (2058) 428 (9704) 638? (>2000) R6: 1 (2) 37 (4) 54 (6) 69 (10) 92 (49) 251 (3008) 1597 (>5000000) R7: 1 (5) 31 (18) 59 (32) 73 (127) 79 (424) 139 (468) 159 (4896) 197 (181761) (next record k is > 457) R8: 2 (2) 5 (4) 11 (18) 37 (851) 74 (2632) 236 (5258) 239? (>2000) R9: 2 (1) 11 (11) 53 (536) 119 (4486) 386 (>5000) R10: 1 (2) 12 (5) 32 (28) 89 (33) 98 (90) 109 (136) 121 (483) 406 (772) 450 (11958) 505 (18470) 1231 (37398) 1803 (45882) 1935 (51836) 2452 (>554789) R11: 1 (17) 32 (18) 39 (22) 62 (26202) 201? (>2000) R12: 1 (2) 23 (3) 24 (4) 46 (194) 157 (285) 298 (1676) 1037 (>5000) Last fiddled with by sweety439 on 2017-06-28 at 13:05 |
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#359 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2×13×113 Posts |
Reserve S80 k=947 (the only remain k not in CRUS for S80).
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#360 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2×13×113 Posts |
Quote:
S4: k = 419: covering set {3, 5, 7, 13} k = 659: covering set {3, 5, 13, 17, 241} k = 794: covering set {3, 5, 7, 13} S5: All k = 7, 11 (mod 24): covering set {2, 3} S7: k = 209: covering set {2, 3, 5, 13, 43}. S8: All k = 47, 79, 83, 181 (mod 195): covering set {3, 5, 13} All k = m^3: for all n; factors to: (m*2^n + 1) * (m^2*4^n - m*2^n + 1) S9: All k = 31, 39 (mod 80): covering set {2, 5} S10: k = 989: covering set {3, 7, 11, 13} k = 1121: covering set {7, 11, 13, 37} k = 3653: covering set {3, 7, 11, 37} S11: All k = 5, 7 (mod 12): covering set {2, 3} S12: k = 521: covering set {5, 13, 29} k = 597: covering set {5, 13, 29} k = 1143: covering set {5, 13, 29} R4: k = 361: covering set {3, 5, 7, 13} k = 919: covering set {3, 5, 7, 13} k = 1114: covering set {3, 5, 7, 13} All k = m^2 for all n; factors to: (m*2^n - 1) * (m*2^n + 1) R5: All k = 13, 17 (mod 24): covering set {2, 3} R7: k = 457: covering set {2, 3, 5, 13, 19} R8: All k = 14, 112, 116, 148 (mod 195): covering set {3, 5, 13} k = 658: covering set {3, 5, 19, 37, 73} All k = m^3: for all n; factors to: (m*2^n - 1) * (m^2*4^n + m*2^n + 1) R9: All k = 41, 49 (mod 80): covering set {2, 5} k = 74: covering set {5, 7, 13, 73} All k = m^2: for all n; factors to: (m*3^n - 1) * (m*3^n + 1) R10: k = 334: covering set {3, 7, 13, 37} k = 343: n = 1 (mod 3): factor of 3; n = 2 (mod 3): factor of 37; n = 0 mod 3: let n=3q; factors to: (7*10^q - 1) * [49*10^(2q) + 7*10^q + 1] k = 1585: covering set {3, 7, 11, 13} k = 1882: covering set {3, 7, 11, 13} R11: All k = 5, 7 (mod 12): covering set {2, 3} R12: k = 376: covering set {5, 13, 29} k = 742: covering set {5, 13, 29} k = 1288: covering set {5, 13, 29} All k where k = m^2 and m = 5, 8 (mod 13): for even n let k = m^2 and let n = 2*q; factors to: (m*12^q - 1) * (m*12^q + 1); odd n: factor of 13 All k where k = 3*m^2 and m = 3, 10 (mod 13): even n: factor of 13; for odd n let k = 3*m^2 and let n = 2*q - 1; factors to: [m*2^n*3^q - 1] * [m*2^n*3^q + 1] Last fiddled with by sweety439 on 2017-09-28 at 22:35 |
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#361 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2×13×113 Posts |
Quote:
R12 has only 2 k's remain: 1037 and 1132, but S12 has many k's remain. (thus, I did not search S12 very far) |
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#362 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
293810 Posts |
Quote:
Next possible record k for S11 is 195, tested to n=10000 with no (probable) prime found. Beside, I also found that 638*5^6974-1 is prime. (next possible record k for R5 is 662) Also, R8 k=239 and R11 k=201 are tested to n=10000 with no (probable) prime found. Note: 302*9^2849-1 is prime, but 302 is not a record k for R9, since the first (probable) prime for R9 k=119 is (119*9^4486-1)/2, this (probable) prime is converted by R3 k=119. Last fiddled with by sweety439 on 2017-06-29 at 18:26 |
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#363 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
55728 Posts |
Conjecture: If k is not Sierpinski/Riesel in base b, then k*b is also not Sierpinski/Riesel in base b, i.e. if (k*b+-1)/gcd(k+-1,b-1) is prime, then there is an n>=1 such that ((k*b)*b^n+-1)/gcd(k*b+-1,b-1) is prime. (if this k is not excluded from the Sierpinski/Riesel problem base b)
Some classic quasi-counterexamples: S2 k=6977 has a prime at n=3, but for k = 55816 = 6977*2^3, this prime k=6977, n=3 would be k=55816, n=0 but n must be > 0 hence it is not allowed so k=55816 must continue to be searched, and k=55816 has a prime at n=14536. S3 k=23 has a prime at n=3, but for k = 621 = 23*3^3, this prime k=23, n=3 would be k=621, n=0 but n must be > 0 hence it is not allowed so k=621 must continue to be searched, and k=621 has no (probable) prime for n<=10000. S4 k=11 has a prime at n=2, but for k = 176 = 11*4^2, this prime k=11, n=2 would be k=176, n=0 but n must be > 0 hence it is not allowed so k=176 must continue to be searched, and k=176 has a prime at n=228. S5 k=8 has a prime at n=1, but for k = 40 = 8*5^1, this prime k=8, n=1 would be k=40, n=0 but n must be > 0 hence it is not allowed so k=40 must continue to be searched, and k=40 has a prime at n=1036. S7 k=3 has a prime at n=1, but for k = 21 = 3*7^1, this prime k=3, n=1 would be k=21, n=0 but n must be > 0 hence it is not allowed so k=21 must continue to be searched, and k=21 has a prime at n=124. S22 k=1 has a prime at n=1, but for k = 22 = 1*22^2, this prime k=1, n=1 would be k=22, n=0 but n must be > 0 hence it is not allowed so k=22 must continue to be searched, and k=22 has no prime for n<2^24-1. R2 k=37 has a prime at n=1, but for k = 74 = 37*2^1, this prime k=37, n=1 would be k=74, n=0 but n must be > 0 hence it is not allowed so k=74 must continue to be searched, and k=74 has a prime at n=2552. R2 k=337 has a prime at n=1, but for k = 674 = 337*2^1, this prime k=337, n=1 would be k=674, n=0 but n must be > 0 hence it is not allowed so k=674 must continue to be searched, and k=674 has a prime at n=11676. R6 k=491 has a prime at n=3, but for k = 106056 = 491*6^3, this prime k=491, n=3 would be k=106056, n=0 but n must be > 0 hence it is not allowed so k=106056 must continue to be searched, and k=106056 has a (probable) prime at n=3038. R10 k=45 has a prime at n=1, but for k = 450 = 45*10^1, this prime k=45, n=1 would be k=450, n=0 but n must be > 0 hence it is not allowed so k=450 must continue to be searched, and k=450 has a prime at n=11958. R15 k=196 has a prime at n=1, but for k = 2940 = 196*15^1, this prime k=196, n=1 would be k=2940, n=0 but n must be > 0 hence it is not allowed so k=2940 must continue to be searched, and k=2940 has a prime at n=13254. R18 k=1 has a prime at n=2, but for k = 324 = 1*18^2, this prime k=1, n=2 would be k=324, n=0 but n must be > 0 hence it is not allowed so k=324 must continue to be searched, and k=324 has a (probable) prime at n=25665. R23 k=10 has a prime at n=1, but for k = 230 = 10*23^1, this prime k=10, n=1 would be k=230, n=0 but n must be > 0 hence it is not allowed so k=230 must continue to be searched, and k=230 has a prime at n=6228. R27 k=22 has a prime at n=1, but for k = 594 = 22*27^1, this prime k=22, n=1 would be k=594, n=0 but n must be > 0 hence it is not allowed so k=594 must continue to be searched, and k=594 has a prime at n=36624. R31 k=4 has a prime at n=1, but for k = 124 = 4*31^1, this prime k=4, n=1 would be k=124, n=0 but n must be > 0 hence it is not allowed so k=124 must continue to be searched, and k=124 has a prime at n=1116. R48 k=8 has a prime at n=1, but for k = 384 = 8*48^1, this prime k=8, n=1 would be k=384, n=0 but n must be > 0 hence it is not allowed so k=384 must continue to be searched, and k=384 has no prime for n<=200000. Last fiddled with by sweety439 on 2017-06-30 at 16:52 |
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