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#265 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
1011011110102 Posts |
In this case, although (k*b^n+1)/gcd(k+1,b-1) has neither covering set nor algebra factors, but this form still cannot have a prime, thus this case is also excluded in the conjectures. (this situation only exists in the Sierpinski side)
b = q^m, k = q^r, where q is not of the form t^s with odd s>1, and m and r have no common odd prime factor, and the exponent of highest power of 2 dividing r >= the exponent of highest power of 2 dividing m, and the equation 2^x = r (mod m) has no solution. Examples: b = q^7, k = q^r, where r = 3, 5, 6 (mod 7). b = q^14, k = q^r, where r = 6, 10, 12 (mod 14). b = q^15, k = q^r, where r = 7, 11, 13, 14 (mod 15). b = q^17, k = q^r, where r = 3, 5, 6, 7, 10, 11, 12, 14 (mod 17). b = q^21, k = q^r, where r = 5, 10, 13, 17, 19, 20 (mod 21) b = q^23, k = q^r, where r = 5, 7, 10, 11, 14, 15, 17, 19, 20, 21, 22 (mod 23) b = q^28, k = q^r, where r = 12, 20, 24 (mod 28) b = q^30, k = q^r, where r = 14, 22, 26, 28 (mod 30) b = q^31, k = q^r, where r = 3, 5, 6, 7, 9, 10, 11, 12, 13, 14, 15, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30 (mod 31) b = q^33, k = q^r, where r = 5, 7, 10, 13, 14, 19, 20, 23, 26, 28 (mod 33) etc. (these are all examples for m<=33) Last fiddled with by sweety439 on 2017-06-09 at 00:27 |
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#266 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2×13×113 Posts |
In the Sierpinski side, if k is a rational power of b, then this number is a generalized Fermat number in base q (q is the largest number such that both b and k are integer powers of q) (if gcd(k+1,b-1) = 1) or a half generalized Fermat number in base q (q is the largest number such that both b and k are integer powers of q) (if gcd(k+1,b-1) = 2) or a generalized repunit in base -q (q is the largest number such that both b and k are integer powers of q) (if gcd(k+1,b-1) is neither 1 nor 2). Besides, in the Riesel side, if k is a rational power of b, then this number is a generalized repunit in base q (q is the largest number such that both b and k are integer powers of q), if b is not a perfect power, then if k is a rational power of b, then k is always a integer power of b, thus this number is a base b repunit (all such k's are in the same family), if b is a perfect power and this number has no algebra factors, then this number is a base q repunit, where q is the largest number such that both b and k are integer powers of q.
In the Riesel side (we only consider such k's < b, since all k's > b is a multiple of b, which are in the same family with smaller k), the correspond primes for non-perfect power b (in the case, k must be 1) are already listed in http://oeis.org/A084740, and the correspond primes for perfect powers b<=144 are: (exclude the forms with algebra factors, i.e. if b = q^m and k = q^r, then gcd(m,r) = 1) (some cases are k's > CK for the base) Code:
b k prime 4 2 (2*4^1-1)/1 8 2 (2*8^2-1)/1 8 4 (4*8^1-1)/1 9 3 (3*9^1-1)/2 16 2 (2*16^1-1)/1 16 8 (8*16^1-1)/1 25 5 (5*25^1-1)/4 27 3 (3*27^2-1)/2 27 9 (9*27^23-1)/2 32 2 (2*32^6-1)/1 32 4 (4*32^1-1)/1 32 8 (8*32^2-1)/1 32 16 (16*32^3-1)/1 36 6 (6*36^1-1)/5 49 7 (7*49^2-1)/6 64 2 (2*64^1-1)/1 64 32 (32*64^2-1)/1 81 3 (3*81^3-1)/2 81 27 (27*81^1-1)/2 100 10 (10*100^9-1)/9 121 11 (11*121^8-1)/10 125 5 (5*125^2-1)/4 125 25 (25*125^3-1)/4 128 2 (2*128^18-1)/1 128 4 (4*128^15-1)/1 128 8 (8*128^2-1)/1 128 16 (16*128^459-1)/1 128 32 (32*128^2-1)/1 128 64 (64*128^1-1)/1 144 12 (12*144^1-1)/11 Last fiddled with by sweety439 on 2017-05-23 at 18:25 |
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#267 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
B7A16 Posts |
I tested some bases b>64.
S65 has CK=10 (proven) Covering set: {3, 11} k,n 1,2 2,1 3,2 4,2 5,1 6,5 7,2 8,1 9,1 S67 has CK=26 (3 k's remain: 1, 17 and 21) Covering set: {3, 7, 31} k,n 1,??? 2,6 3,1 4,1 5,6 6,4532 (given by CRUS) 7,135 8,1 9,2 10,1 11,209 12,135 13,2 14,1 15,1 16,3 17,??? 18,2 19,21 20,2 21,??? 22,3 23,1 24,1 25,2 S68 has CK=22 (2 k's remain: 1 and 17) Covering set: {3, 23} k,n 1,??? (at n=2^24-1, see GFN stats) 2,1 3,2 4,6 5,29 6,1 7,2 8,319 9,1 10,6 11,3947 (given by CRUS) 12,656921 (given by CRUS) 13,26 14,1 15,1 16,36 17,??? (at n=1M, see CRUS) 18,2 19,6 20,1 21,1 S69 has CK=6 (proven) Covering set: {5, 7} k,n 1,2 2,1 3,2 4,1 5,1 S71 has CK=5 (proven) Covering set: {2, 3} k,n 1,2 2,3 3,1 4,22 S73 has CK=47 (2 k's remain: 14 and 21) Covering set: {2, 5, 13} k,n 1,1 2,4 3,4 4,1 5,1 6,1 7,2 8,28 9,2 10,3 11,1 12,1 13,23 14,??? 15,1 16,40 17,9 18,2 19,1 20,1 21,??? 22,1 23,2 24,1 25,10 26,1 27,4 28,2 29,1 30,2 31,1 32,2 33,6 34,3 35,1 36,7 37,6 38,6 39,350 40,3 41,1 42,1 43,2 44,2 45,4 46,1 S74 has CK=4 (proven) Covering set: {3, 5} k,n 1,2 2,1 3,1 S75 has CK=37 (1 k remain: 11) Covering set: {2, 19} k,n 1,32 2,1 3,1 4,2 5,48 6,2 7,1 8,1 9,6 10,1 11,??? 12,57 13,2 14,1 15,1 16,1 17,128 18,57 19,3 20,2 21,2 22,4 23,1 24,1 25,2 26,1 27,1 28,129 29,2 30,1 31,1 32,2 33,18 34,1 35,11 36,1 Last fiddled with by sweety439 on 2017-05-23 at 19:14 |
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#268 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
B7A16 Posts |
R65 has CK=10 (proven)
Covering set: {3, 11} k,n 1,19 2,4 3,1 4,9 5,2 6,1 7,1 8,10 9,1 R67 has CK=33 (1 k remain: 25) Covering set: {2, 17} k,n 1,19 2,768 (given by CRUS) 3,2 4,1 5,1 6,1 7,2 8,2 9,3 10,1 11,6 12,1 13,7 14,1 15,4 16,(proven composite by partial algebra factors) 17,1 18,7 19,8 20,2 21,27 22,1 23,42 24,1 25,??? 26,1 27,2 28,2 29,1 30,2 31,10 32,1 R68 has CK=22 (proven) Covering set: {3, 23} k,n 1,5 2,4 3,10 4,1 5,13574 (given by CRUS) 6,2 7,25395 (given by CRUS) 8,62 9,3 10,53 11,198 12,2 13,1 14,4 15,1 16,1 17,2 18,1 19,1 20,2 21,1 R69 has CK=6 (proven) Covering set: {5, 7} k,n 1,3 2,1 3,1 4,(proven composite by partial algebra factors) 5,4 R71 has CK=5 (proven) Covering set: {2, 3} k,n 1,3 2,52 3,2 4,1 R73 has CK=112 (2 k's remain: 79 and 101) Covering set: {5, 13, 37} k,n 1,5 2,2 3,1 4,1 5,2 6,2 7,2 8,8 9,(proven composite by partial algebra factors) 10,3 11,1 12,11 13,1 14,1 15,1 16,1 17,15 18,4 19,3 20,1 21,1 22,2 23,1 24,3 25,(proven composite by partial algebra factors) 26,50 27,2 28,1 29,3 30,2 31,3 32,24 33,5 34,1 35,1 36,(proven composite by partial algebra factors) 37,2 38,9 39,1 40,5 41,6 42,50 43,1 44,12 45,1 46,1 47,2 48,73 49,1 50,2 51,1 52,2 53,1 54,63 55,1 56,6 57,4 58,25 59,1 60,9 61,39 62,8 63,2 64,5 65,1 66,1 67,3 68,2 69,1 70,2 71,1 72,8 73,4 74,3 75,5 76,18 77,8 78,1 79,??? 80,1 81,1 82,4 83,26 84,1 85,2 86,1 87,3 88,1 89,32 90,1 91,3 92,2 93,1 94,1 95,1 96,2 97,47 98,4 99,1 100,1 101,??? 102,10 103,5 104,1 105,102 106,1 107,2 108,1 109,4 110,2 111,1 R74 has CK=4 (proven) Covering set: {3, 5} k,n 1,5 2,132 3,2 R75 has CK=37 (1 k remain: 35) Covering set: {2, 19} k,n 1,3 2,1 3,16 4,5 5,9 6,1 7,2 8,1 9,1 10,2 11,2 12,2 13,1 14,1 15,2 16,119 17,5 18,54 19,2 20,1 21,1 22,15 23,4 24,2 25,1 26,1 27,2 28,1 29,1 30,41 31,2 32,1 33,1 34,1 35,??? 36,1 Last fiddled with by sweety439 on 2017-05-23 at 19:15 |
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#269 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2·13·113 Posts |
Some extended Sierpinski/Riesel bases are "proven", but with some probable primes that have not been certified, these bases <=64 and probable primes are shown below:
Code:
base k probable prime S61 43 (43*61^2788+1)/4 S61 62 (62*61^3698+1)/3 S64 11 (11*64^3222+1)/3 R7 159 (159*7^4896-1)/2 R7 197 (197*7^181761-1)/2 R7 313 (313*7^5907-1)/6 R7 367 (367*7^15118-1)/6 R17 29 (29*17^4904-1)/4 R51 1 (1*51^4229-1)/50 Last fiddled with by sweety439 on 2017-05-24 at 16:25 |
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#270 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2×13×113 Posts |
These files are the status of S5, S9 and S11 for all k<=1024. (tested up to n=2000) (0 if there are no (probable) primes for n<=2000)
These k's with covering set, thus excluded in the files: S5: k = 7, 11 (mod 24), covering set {2, 3} S9: k = 31, 39 (mod 80), covering set {2, 5} S11: k = 5, 7 (mod 12), covering set {2, 3} Last fiddled with by sweety439 on 2017-05-25 at 19:21 |
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#271 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2×13×113 Posts |
These files are the status of R5, R9 and R11 for all k<=1024. (tested up to n=2000) (0 if there are no (probable) primes for n<=2000)
These k's with covering set, thus excluded in the files: R5: k = 13, 17 (mod 24), covering set {2, 3} R9: k = 41, 49 (mod 80), covering set {2, 5}, also square k's with full algebra factors R11: k = 5, 7 (mod 12), covering set {2, 3} Last fiddled with by sweety439 on 2017-05-25 at 19:21 |
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#272 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2·13·113 Posts |
Quote:
Can you reserve S10 k=269 and S25 k=71? |
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#273 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2·13·113 Posts |
Quote:
Sierpinski and Riesel bases 5, 8, 9, 11, 13, 14, 16 would be interesting bases to attack to prove the 2nd/3rd/etc. conjectured k's since their 1st one is so low and was already easily proven. Also, the 2nd/3rd/etc. conjecture for R10 has been worked in http://www.worldofnumbers.com/Append...s%20to%20n.txt (k mod 9 = 1) and https://www.rose-hulman.edu/~rickert...siteseq/#b10d3 (k mod 9 = 4 or 7), R10 has conjectured k at k = 334, 1585, 1882, 3340, 3664, 7327, 8425, 9208, 10176, ... (k = 343 and 3430 proven composite by partial algebraic factors), and this base has 3 k's remain for k < 10176: 2452, 4421 and 5428. (test limit: k = 2452 at n=554K, k = 4421 at n=1.76M, k = 5428 at n=300K) Last fiddled with by sweety439 on 2017-06-01 at 19:20 |
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#274 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2·13·113 Posts |
Update the primes for SR22, R28, SR46, SR58 and SR63 for the k's such that gcd(k+-1,b-1) = 1 (+ for Sierpinski, - for Riesel), compare with CRUS.
See http://www.mersennewiki.org/index.ph..._definition%29 (Sierpinski) and http://www.mersennewiki.org/index.ph..._definition%29 (Riesel). Last fiddled with by sweety439 on 2017-06-01 at 12:50 |
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#275 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2·13·113 Posts |
Reserve SR42, SR48 and SR60 (only for the k's not in CRUS, i.e. gcd(k+-1,b-1) > 1),
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