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#221 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
55728 Posts |
Quote:
Last fiddled with by sweety439 on 2017-05-09 at 14:51 |
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#222 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2·13·113 Posts |
Quote:
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#223 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2·13·113 Posts |
Quote:
12, 18, 32, 37*, 38, 50, 55, 62. * In these bases some of the primes found are probable primes that have not been certified. The non-certified probable primes for these bases are: S37: (19*37^5310+1)/4 |
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#224 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
55728 Posts |
Certificates of the proven primes for the proven extended Sierpinski/Riesel conjectures: (>=300 digits and not belong to the original Sierpinski/Riesel conjectures, i.e. gcd(k+-1, b-1) is not 1)
S7, k=141, (141*7^1044+1)/2: http://factordb.com/cert.php?id=1100000000887911448 S13, k=11, (11*13^564+1)/12: (proven to be prime by N-1-method) S16, k=23, (23*16^1074+1)/3: http://factordb.com/cert.php?id=1100000000001707231 S43, k=13, (13*43^580+1)/14: (proven to be prime by N-1-method) S43, k=9, (9*43^498+1)/2: http://factordb.com/cert.php?id=1100000000899429028 S61, k=23, (23*61^1659+1)/12: http://factordb.com/cert.php?id=1100000000922387835 R4, k=106, (106*4^4553-1)/3: http://factordb.com/cert.php?id=1100000000350048535 R10, k=121, (121*10^483-1)/3: http://factordb.com/cert.php?id=1100000000291649394 R12, k=298, (298*12^1676-1)/11: http://factordb.com/cert.php?id=1100000000800797310 R17, k=13, (13*17^1123-1)/4: http://factordb.com/cert.php?id=1100000000033706286 R26, k=121, (121*26^1509-1)/5: http://factordb.com/cert.php?id=1100000000894500022 R35, k=1, (1*35^313-1)/34: (proven to be prime by N-1-method) R37, k=5, (5*37^900-1)/4: (proven to be prime by N-1-method) R39, k=1, (1*39^349-1)/38: (proven to be prime by N-1-method) R45, k=53, (53*45^582-1)/4: http://factordb.com/cert.php?id=1100000000920998225 R49, k=79, (79*49^212-1)/6: http://factordb.com/cert.php?id=1100000000854476434 R57, k=87, (87*57^242-1)/2: (proven to be prime by N-1-method) Last fiddled with by sweety439 on 2017-05-09 at 18:16 |
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#225 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2·13·113 Posts |
Corrected the "k's that make a full covering set with all or partial algebraic factors" column: If there are no k's proven composite by this condition, then delete this condition.
Also, the test limit for R61 is not 5K, it is just 4K, I have corrected it. This is the right word file. Last fiddled with by sweety439 on 2017-05-09 at 19:00 |
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#226 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2×13×113 Posts |
This is the text file for the conjectured k and the covering set for all bases b<=64.
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#227 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
1011011110102 Posts |
Quote:
Can you give all primes for R28 (original conjecture, but only for the k's < the CK for extended conjecture)? Or I cannot complete the top 10 primes for this base (extended conjecture). Also, can you also give all primes for SR22, SR46, SR58 and SR63 (original conjecture, but only for the k's < the CK for extended conjecture)? I only tested these bases to n=1000, but in CRUS, there are primes with n>1000 for these bases, but many of them are not top 10 primes in the original conjecture, so I cannot copy the CRUS primes to this project, see the word files. (Since for SR22, SR46, SR58 and SR63, there are too many k's remain at n=1000, thus I only tested to n=1000) Last fiddled with by sweety439 on 2017-05-09 at 19:13 |
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#228 | |
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May 2007
Kansas; USA
32×13×89 Posts |
Quote:
I need possibly two sets of examples: 1. An example of the divisor for several consecutive k's on a single base. 2. If I'm not understanding it and the divisor is the same for all k's on a single base, I need an example of the divisor for several consecutive bases. Last fiddled with by gd_barnes on 2017-05-09 at 20:11 |
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#229 | |
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May 2007
Kansas; USA
32×13×89 Posts |
Quote:
Regardless base 63 has a huge conjecture on both sides. The entire primes file would be multiple gigabytes. I will still consider sending base 63 if you will do the above. Last fiddled with by gd_barnes on 2017-05-09 at 20:14 |
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#230 | |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
2·13·113 Posts |
Quote:
Thus, for example, for R13, the divisor of k = 1, 2, 3, ... are {12, 1, 2, 3, 4, 1, 6, 1, 4, 3, 2, 1, 12, 1, 2, 3, 4, 1, ...}, and for S11, the divisor of k = 1, 2, 3, ... are {2, 1, 2, 5, 2, 1, 2, 1, 10, 1, 2, 1, 2, 5, 2, 1, 2, 1, ...}. In fact, this divisor is the largest number that divides k*b^n+-1 (+ for Sierpinski, - for Riesel) for all n. Thus, this divisor is the largest "trivial factor" of k*b^n+-1 (+ for Sierpinski, - for Riesel). Last fiddled with by sweety439 on 2017-05-24 at 18:49 |
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#231 |
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"99(4^34019)99 palind"
Nov 2016
(P^81993)SZ base 36
55728 Posts |
See page 12 of https://cs.uwaterloo.ca/~cbright/reports/mepn.pdf, you can use srsieve to sieve (a*b^n+c)/d for all fixed integers a, b, c, d.
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