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#78 |
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Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
10AB16 Posts |
Prime95 (as of 28.9) refuses to test 66066061 because it is composite. I don't know if Ruicar managed to bypass this check, or told us a false number (in order to safeguard "his prime", perhaps?).
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#79 |
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Nov 2016
43 Posts |
If is prime is the biggest prime no mersene know in the world ????
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#80 |
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"Forget I exist"
Jul 2009
Dumbassville
20C016 Posts |
it can't be prime with a composite exponent proof take for example 2*x for some value x as our exponent then 2^(2*x)-1 = (2^x+1)*(2^x-1) via the fact that 2^(x+1)-1 = 2*(2^x-1)+1 for any value x and the fact that you apply this repeated to get to the exponent 2*x leading to (2^x)*(2^x-1)+(2^x-1) = (2^x+1)*(2^x-1)=2^(2*x)-1
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#81 |
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Nov 2016
43 Posts |
you apply this repeated to get to the exponent 2*x leading to (2^x)*(2^x-1)+(2^x-1) = (2^x+1)*(2^x-1)=2^(2*x)-1 you say his repeat but when ou do this 2399 on side and 27539 other every time you reach one you take off this same value and the other side you need more rotation
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#82 | |
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"Forget I exist"
Jul 2009
Dumbassville
26×131 Posts |
Quote:
3=2*1+1 7=2*3+1 = 4*1+3 15= 2*7+1 =4*3+3 = 8*1+7 ... 3 is 2^2-1 15 is 2^4-1 is 2^(2*2)-1 = (2^2+1)*(2^2-1) = 5*3 and you can extend this to show that any multiple of a value other than 1 in the exponent is composite. Last fiddled with by science_man_88 on 2016-11-07 at 16:01 |
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#83 |
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Sep 2002
Database er0rr
2·32·11·19 Posts |
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#84 | |
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Romulan Interpreter
Jun 2011
Thailand
32×29×37 Posts |
m=266066061-1 can not be prime. Because 66066061 is not prime, but divisible by 2399, then one of the factors of m is q=22399-1, a number with 723 digits, given below:
Code:
1482380173949890670604068470529445983185715497388166624080411572684455306652894803587288151010577306536857015172975854678622446465125379386752523387893232484675234292972398578 691727336824282590717812815966030512353670037778064570481035526345892444454738716506466488254192210763638800232587234151479510015990161293030567920517649516101698365403033974455710 986201525920711228356829515454478449218686187559060428491668508532808899121503126638023632300652137917300176371029047879288166729514951883585323852279196293865857552535495660550140 388640801333982797227042111169900048227440172345667021193745731789629877001548800408128936695120888318680815929028755827082417845686877221292316100658499826339936380486714646474596 94706687 Quote:
(Where is RDS to send them to the books?) Last fiddled with by LaurV on 2016-11-08 at 07:19 |
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#85 | |
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Dec 2016
116 Posts |
Quote:
I'm Rui's friend, and we are working on a very interesting mathematics project. We are looking for people passionate about mathematics to look at what we have found. Can you please tell me if you have time to work with us ? For information, Rui doesn't have anymore access to this forum. Thanks a lot fo your response ! |
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#86 |
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Romulan Interpreter
Jun 2011
Thailand
32×29×37 Posts |
You should accept. Charge them $20 per hour. If you do not have a paypal account, PM me and I gave you mine...
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