Answer in 5 . 4 . 3 . 2 . 1 ..... - Page 2

MattcAnderson · 2016-10-18, 05:20

Quote:

Originally Posted by Uncwilly

The following is borrowed from here.
Let's try to keep it with out powers or bases. Also, let's try to get variants for each number
Color any additions that you make.

Code:

 1 = 5 - 4 + 3 - 2 - 1
 2 = (5 - 4 + 3 - 2) x 1
3 = (5 + 4) - (3 x 2 x 1)
 4 = -5 + 4 + (3 x 2) - 1
 5 = -5 + (4 x 3) - 2 x 1

Hi Math People Everywhere

This is my take on the puzzle.

5 - ( 4 + 3 ) 2 1
5-7-2+1
One

yeah
Best of luck on yours.

Pass
M C

VBCurtis · 2016-10-18, 07:07

23 = (5 * 4) + 3 * (2-1)

Uncwilly · 2016-10-18, 07:16

Current list

Code:

 1 = 5 - 4 + 3 - 2 - 1
 2 = (5 - 4 + 3 - 2) x 1
 3 = (5 + 4) - (3 x 2 x 1)
 4 = -5 + 4 + (3 x 2) - 1
 5 = -5 + (4 x 3) - 2 x 1
 6 = (5 - 4) * (3 * 2 * 1)
 7 = 5 - 4 + 3 + 2 + 1
 8 = 5 + 4 - 3 + 2 * 1
 9 = (5 + 4) * (3 - 2 * 1)
10 = (5 + 4) + (3 - (2 * 1))
11 = 5 + 4 + 3 - 2 + 1
12 = 5 + 4 + 3 * (2 - 1)
13 = 5 + 4 + 3 + 2 - 1
14 = 5 + 4 + 3 + 2 * 1
15 = 5 + 4 + 3 + 2 + 1
16 = 5 + 4 + 3 * 2 + 1
17 = (5 + 4 * 3) * (2-1)
18 = 5 + 4 * 3 + 2 - 1
19 = (5 * 4) - (3 / (2 + 1))
20 = (5 * 4) + (3 - (2 + 1)) or (5 * 4 * 3) / (2 + 1)  or 5 * 4 * (3 / (2 + 1))
21 = (5 * 4) + ( 3 / (2 + 1))
22 = (5 * 4) + 3 - 2 + 1
23 = (5 * 4) + 3 * (2 - 1)
24 = (5 * 4) + 3 + (2 - 1)
25 = 5 * (4 + (3 / (2 - 1)))

axn · 2016-10-18, 07:38

26 = 5 * 4 + 3 * 2 * 1
27 = 5 * 4 + 3 * 2 + 1
28 = 5 + 4 * 3 * 2 - 1
29 = 5 + 4 * 3 * 2 * 1
30 = 5 + 4 * 3 * 2 + 1

KangJ · 2016-10-18, 07:45

1=5/(4*3/2-1), 1=(5-4+3)/2-1
2=5+4-3*2-1, 2=5/(4-3/2*1), 2=5*4+3-21
3=(5-4+3)/2+1, 3=-(54/3)+21
4=5*4/(3+2/1), 4=-5*4+3+21
5=5*4/(3+2-1), 5=5-4*(3-2-1)
6=5+4/(3+2-1)
7=5*(4-3)+2*1
8=5-4+3*2+1, 8=54/3/2-1
9=-5+4*3+2/1, 9=-54+3*21
10=5*4*(3/2-1), 10=5+4+3-2*1, 10=54/3/2+1
11=-5*(4-3*2)+1, 11=-5*4+32-1
12=5+4*3/2+1
13=5*4-3*2-1
14=5*4-3*2/1
15=5*4-3*2+1, 15=-5-4+3+21
16=5+4*3-2+1, 16=54/3-2*1
17=(5*4-3)*(2-1), 17=-5+43-21
18=5*4-3+2-1, 18=-(5-43)/2-1
19=5*4-3+2*1, 19=54/3+2-1
20=5*4-3+2+1
21=5*4+3-2*1
22=5*4+3-2+1
23=(5+4+3)*2-1
24=(5+4+3)*2/1
25=5*4+3*2-1
26=5*4+3*2*1
27=5*4+3*2+1
28=5+4*3*2-1
29=5+4*3*2*1
30=5*4*3/2*1
31=(5*4*3)/2+1
32=5*(4+3)-2-1
33=(5+4*3)*2-1
34=(5+4*3)*2*1
35=(5*4-3)*2+1
36=5*(4+3)+2-1
37=5*(4+3)+2*1
38=5*(4+3)+2+1
39=54/3+21
40=5*(4+3+2-1)
45=5*(4+3*2-1)
46=(5*4+3)*2*1
47=(5*4+3)*2+1
49=5*(4*3-2*1)

I think 39 is only the impossible number without cheating

Batalov · 2016-10-18, 07:51

41 = 5 + 4 * 3 * (2 + 1)

LaurV · 2016-10-18, 09:37

Quote:

Originally Posted by Uncwilly

Code:

 2 = (5 - 4 + 3 - 2) x 1

Why do you need the parenthesis there?

unconnected · 2016-10-18, 09:59

42 = 5+4+32+1

unconnected · 2016-10-18, 10:01

43=-5*4+(3*21)

petrw1 · 2016-10-18, 15:11

Quote:

Originally Posted by KangJ

39=54/3+21

I think 39 is only the impossible number without cheating

Another way to get 39 with bending another rule:

39 = 5 X ( (3 X 2) + 1) + 4

bsquared · 2016-10-18, 15:56

Another cheat

:

39 = (5 * (4 + 3) + 2 + 1)++

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2016-10-18, 07:07	#13
VBCurtis "Curtis" Feb 2005 Riverside, CA 11375₈ Posts	23 = (5 * 4) + 3 * (2-1)

2016-10-18, 07:38	#15
axn Jun 2003 2²·3·421 Posts	26 = 5 * 4 + 3 * 2 * 1 27 = 5 * 4 + 3 * 2 + 1 28 = 5 + 4 * 3 * 2 - 1 29 = 5 + 4 * 3 * 2 * 1 30 = 5 + 4 * 3 * 2 + 1

2016-10-18, 07:45	#16
KangJ Jul 2015 11₈ Posts	1=5/(43/2-1), 1=(5-4+3)/2-1 2=5+4-32-1, 2=5/(4-3/21), 2=54+3-21 3=(5-4+3)/2+1, 3=-(54/3)+21 4=54/(3+2/1), 4=-54+3+21 5=54/(3+2-1), 5=5-4(3-2-1) 6=5+4/(3+2-1) 7=5(4-3)+21 8=5-4+32+1, 8=54/3/2-1 9=-5+43+2/1, 9=-54+321 10=54(3/2-1), 10=5+4+3-21, 10=54/3/2+1 11=-5(4-32)+1, 11=-54+32-1 12=5+43/2+1 13=54-32-1 14=54-32/1 15=54-32+1, 15=-5-4+3+21 16=5+43-2+1, 16=54/3-21 17=(54-3)(2-1), 17=-5+43-21 18=54-3+2-1, 18=-(5-43)/2-1 19=54-3+21, 19=54/3+2-1 20=54-3+2+1 21=54+3-21 22=54+3-2+1 23=(5+4+3)2-1 24=(5+4+3)2/1 25=54+32-1 26=54+321 27=54+32+1 28=5+432-1 29=5+4321 30=543/21 31=(543)/2+1 32=5(4+3)-2-1 33=(5+43)2-1 34=(5+43)21 35=(54-3)2+1 36=5(4+3)+2-1 37=5(4+3)+21 38=5(4+3)+2+1 39=54/3+21 40=5(4+3+2-1) 45=5(4+32-1) 46=(54+3)21 47=(54+3)2+1 49=5(43-2*1) I think 39 is only the impossible number without cheating

2016-10-18, 07:51	#17
Batalov "Serge" Mar 2008 Phi(4,2^7658614+1)/2 3⁶×13 Posts	41 = 5 + 4 * 3 * (2 + 1)

2016-10-18, 09:59	#19
unconnected May 2009 Russia, Moscow 13·199 Posts	42 = 5+4+32+1

2016-10-18, 10:01	#20
unconnected May 2009 Russia, Moscow 5033₈ Posts	43=-54+(321)

2016-10-18, 15:56	#22
bsquared "Ben" Feb 2007 110110111001₂ Posts	Another cheat : 39 = (5 * (4 + 3) + 2 + 1)++