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Old 2015-03-19, 01:14   #12
science_man_88
 
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Quote:
Originally Posted by primus View Post
\begin{cases}<br />
		k\equiv 3 \pmod{30}\text{~ with ~} b \equiv 2 \pmod{10}\text{~ and ~ }n \equiv 0,3 \pmod{4} \\<br />
		k\equiv 3 \pmod{30}\text{~ with ~} b \equiv 4 \pmod{10}\text{~ and ~ } n \equiv 0,2 \pmod{4} \\<br />
		k\equiv 3 \pmod{30}\text{~ with ~}b \equiv 6 \pmod{10}\text{~ and ~ }n \equiv 0,1,2,3 \pmod{4} \\<br />
		k\equiv 3 \pmod{30}\text{~ with ~}b \equiv 8 \pmod{10}\text{~ and ~ }n \equiv 0,1 \pmod{4}<br />
		\end{cases}

potentially unable to be mocked as much:

\begin{cases}<br />
		k\equiv 3 \pmod{30}\text{~ with ~} n \equiv 0 \pmod{4}\text{~ and ~ }b \equiv 2,4,6,8 \pmod{10} \\<br />
		k\equiv 3 \pmod{30}\text{~ with ~} n \equiv 1 \pmod{4}\text{~ and ~ } b \equiv 6,8 \pmod{10} \\<br />
		k\equiv 3 \pmod{30}\text{~ with ~}n \equiv 2 \pmod{4}\text{~ and ~ }b \equiv 4,6 \pmod{10} \\<br />
		k\equiv 3 \pmod{30}\text{~ with ~}n \equiv 3 \pmod{4}\text{~ and ~ }b \equiv 2,6 \pmod{10}<br />
		\end{cases}
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Old 2015-03-20, 14:20   #13
primus
 
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Thanks Darth Vader for changing a title .
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Old 2015-07-04, 12:44   #14
primus
 
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http://arxiv.org/pdf/1506.03444.pdf
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Old 2015-07-04, 15:42   #15
danaj
 
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From a practical point of view, does this offer any advantage vs. Proth's theorem for +1 or LLR for -1 (using the Rödseth (1994) method for finding a start value)? The latter seems much simpler than all the tables of mod conditions.
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