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#122 | |
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Nov 2003
22·5·373 Posts |
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thread have been repeatedly ignored and since my comments are obviously not valued, I withdraw from future comments and also place alpertron and pdazzl on my 'ignore; they do not listen and are unteachable' list. BTW, in response to the strong urge that the moderators seem to have to practice censorship, I point to Voltaire: http://www.brainyquote.com/quotes/qu...ire109645.html The moderators, it seems, do not defend people's right to "say it". |
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#123 | |
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Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
22·5·72·11 Posts |
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OK, enough from me on this particular spat. We can continue in the Soapbox if you would like a larger audience than PM allows. It's clear that this is no longer about mathematics and does not belong here. Paul |
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#124 | |
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Apr 2014
11101112 Posts |
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#125 |
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Aug 2002
Buenos Aires, Argentina
101010101102 Posts |
I concur with the previous poster.
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#126 |
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Aug 2002
Buenos Aires, Argentina
136610 Posts |
I was reading some proofs of Erdos-Kac theorem. It appears that it does not work "as expected" in our case because the product of all known prime factors have less than 500 digits, which is less than 0.01% of the size of the number.
In this case, the extremely small primes (when compared to the Mersenne number) are essentially independent. Thus the presence of a new prime factor does not depend on the presence of other prime factors. So wblipp's numbers appear to be OK. |
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#127 | |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
2×47×101 Posts |
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The fairly arbitrarily picked "candidates" were disproportionately sieved, and the distribution is skewed again. Try M3396244391. Does it have 2 prime factors... or >8? It does have more than eight. Try it. |
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#128 | ||
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May 2013
East. Always East.
11·157 Posts |
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In fact, I would normally not admit to "laughing" at the ignorance in this statement. The reason I do is just to show that I see that it's obviously wrong, but that there is a better way of dealing with it. Just because an event occurs, this does not mean that the event is necessarily likely to occur. Grab a coin, and flip it twenty times, logging the result, in order. I will do that myself, right now: H T H T H T H H H T T H H H H T T T T H Now, consider that the odds of getting that exact sequence of heads and tails is 220, one power of two per toss. 1 chance in 1048576, specifically. It happened, even though the odds are 1 in a million. In the same way, the odds of finding an eleventh factor (and proving the existence of thirteen) weren't very high, but that in no way prevents this event from occurring. However, this COULD be the first of a number of events which bring into question the integrity of the prediction. One time, not likely, but possible. If we randomly pick another exponent with 9 factors and find two or three more, that is VERY not likely, but possible. If we pick a third, and AGAIN find factors despite the prediction that we won't, we can start to ask ourselves if the prediction is actually any good. I don't really understand how we can "prove" anything about the behaviour of such random things as prime numbers and the distribution of factors in a number, but I'll take it for granted that the conjectures are "close enough" for now. Last fiddled with by TheMawn on 2014-08-25 at 20:08 |
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#129 | |
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Aug 2002
Buenos Aires, Argentina
2×683 Posts |
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According to Bob, if a Mersenne number already has several known prime factors, the probability of having more factors is extremely remote, and more remote as we know more factors. So I do not see how we know 11 prime factors of some Mersenne number if that is true, and several Mersenne numbers with 8, 9 and 10 prime factors. That's why I said that something was wrong with respect to probabilities. Last fiddled with by alpertron on 2014-08-25 at 21:17 Reason: Corrected Web site |
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#130 | |
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Aug 2002
Buenos Aires, Argentina
2×683 Posts |
Quote:
Then, in order to find the 7th factor we would have 1 chance in 100. That would be possible, because we have lots of Mersenne numbers to check. But then we find the 8th, 9th, 10th and now the 11th. That's 1 chance in 10,000,000,000. We can start to have some doubts about the statistics, but we can also have good luck. But then you can find other Mersenne numbers with 10 prime factors. That's one chance in 100,000,000 and several Mersenne numbers with 9 prime factors. That's 1 chance in 1,000,000 for each hit. It is clear that far from good luck, something wrong occurs with the probabilities. Last fiddled with by alpertron on 2014-08-25 at 20:52 Reason: Changed probabilities |
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#131 | |
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Apr 2014
7×17 Posts |
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#132 |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
100101000101102 Posts |
M3273488573 has 9 (and >=1 invisible one). It is rather easy to find them.
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