User TJAOI - Page 45

ixfd64 · 2019-08-24, 01:06

Quote:

Originally Posted by Madpoo

I don't know who that user is, but if I ever meet him/her, I'll buy 'em a drink of their choice.

Someone said his forum name was "error." However, he has neither confirmed nor denied this.

mathwiz · 2019-08-24, 01:33

Quote:

Originally Posted by Madpoo

I don't know who that user is, but if I ever meet him/her, I'll buy 'em a drink of their choice.

How many GHz days must one accumulate in order for you to buy them a nice glass of Macallan 25?

kriesel · 2019-08-24, 14:15

Quote:

Originally Posted by mathwiz

How many GHz days must one accumulate in order for you to buy them a nice glass of Macallan 25?

Apparently not more than 663000/year. See #17 at https://www.mersenne.org/report_top_500/
But madpoo did not state his requirements, which could be identifying and implementing and running a novel approach at scale.

a1call · 2019-08-24, 20:15

As an alternative for getting a free drink, I have no doubt that Madpoo as well as many others (some might insist for the drink to be nonalcoholic) will be glad to pay for a drink if you can find a factor for M1277.

Even, TJAOI hasn't given a factor for that yet, AFAIK.

lycorn · 2019-08-24, 22:31

Quote:

Originally Posted by a1call

Even, TJAOI hasn't given a factor for that yet, AFAIK.

Not even Ryan Propper...

Madpoo · 2019-08-25, 05:32

Quote:

Originally Posted by kriesel

Apparently not more than 663000/year. See #17 at https://www.mersenne.org/report_top_500/
But madpoo did not state his requirements, which could be identifying and implementing and running a novel approach at scale.

I also didn't specify drink size... hmm... I hadn't thought through some of the pricier drinks out there, but my "out" is that by "drink" I could be referring to as little as a teaspoon-full.

Would they serve such a tiny amount?

LaurV · 2019-08-31, 10:31

Quote:

Originally Posted by a1call

As an alternative for getting a free drink, I have no doubt that Madpoo as well as many others (some might insist for the drink to be nonalcoholic) will be glad to pay for a drink if you can find a factor for M1277.

I will buy a drink for whoever gets a factor of M1279. You won't argue for plus or minus two, would you?

retina · 2019-08-31, 10:47

Quote:

Originally Posted by LaurV

I will buy a drink for whoever gets a factor of M1279.

M1279 = (2^1279-1) * 1

There you go, both factors.

a1call · 2019-08-31, 12:55

Giving a factor for M1277 is easy as long as you don't ask for the decimal expansion

$<br /> GCD\left( \left( \sqrt {M1277}\backslash 1\right) !,M1277\right)<br />$

alpertron · 2019-09-01, 12:51

Quote:

Originally Posted by a1call

Giving a factor for M1277 is easy as long as you don't ask for the decimal expansion

$GCD\left( \left( \sqrt {M1277}\backslash 1\right) !,M1277\right)$

I think that if all prime factors of M1277 are less than its square root, the GCD will give you M1277.

a1call · 2019-09-01, 13:58

Quote:

Originally Posted by alpertron

I think that if all prime factors of M1277 are less than its square root, the GCD will give you M1277.

Looks like I was too quick at going and having a glass of orange juice.

Since it seems impossible to parse # in LaTeX how about:

GCD((sqrt(M1277)\1)#,M1277)

Would that fair any better?
Now only one of the factors can be in common if any are powers.

And since M1277 is not a primorial something must be uncommon.

ETA I realize that I was wrong and the primorial does not fair any better. Thanks for pointing that out.

2019-08-24, 20:15	#488
a1call "Rashid Naimi" Oct 2015 Remote to Here/There 100000010000₂ Posts	As an alternative for getting a free drink, I have no doubt that Madpoo as well as many others (some might insist for the drink to be nonalcoholic) will be glad to pay for a drink if you can find a factor for M1277. Even, TJAOI hasn't given a factor for that yet, AFAIK. Last fiddled with by a1call on 2019-08-24 at 20:16

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2019-08-31, 12:55	#493
a1call "Rashid Naimi" Oct 2015 Remote to Here/There 2⁴×3×43 Posts	Giving a factor for M1277 is easy as long as you don't ask for the decimal expansion $<br /> GCD\left( \left( \sqrt {M1277}\backslash 1\right) !,M1277\right)<br />$