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#12 | ||
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Jun 2003
7·167 Posts |
Quote:
The proof is fixable, by defining y differently: suppose C is composite and that i < (all proper factors of C) < C < i^2. Let A be a proper factor of C. Then so is C/A. Let A=i+x and C/A=i+y for +ve x and y. But then C = A*C/A = (i + x)(I + y) = i^2 + i(x+y) + xy > i^2. Contradiction. Quote:
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#13 |
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Jun 2003
5,087 Posts |
Looks to me like a simple typo where "smallest factor of 'C'" was intended. Wouldn't that "fix" the proof?
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#14 | |
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Jun 2003
100100100012 Posts |
Quote:
So yeah, you can fix the proof by including everything he omitted. Also there's no reason for F to be the smallest factor of C. The proof works just as well if you say "let F be any factor of C". It's not a good idea to introduce redundant hypothesis into a proof. It may not make the proof technically "wrong", but it can obfuscate what is going on. |
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#15 |
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"Nathan"
Jul 2008
Maryland, USA
5·223 Posts |
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#16 |
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Jun 2003
5,087 Posts |
Hmmm... But your "nonsense" is unjustified. Could you tone it down a little? Another RDS, we don't need.
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#17 |
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Jun 2003
7·167 Posts |
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#18 |
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Jun 2003
13DF16 Posts |
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