mersenneforum.org  

Go Back   mersenneforum.org > Great Internet Mersenne Prime Search > Math

Reply
 
Thread Tools
Old 2014-04-23, 21:58   #56
science_man_88
 
science_man_88's Avatar
 
"Forget I exist"
Jul 2009
Dumbassville

26×131 Posts
Default

Quote:
Originally Posted by Batalov View Post
"q I believe" is the new form of Q.E.D.?
I just wanted to make sure I wasn't forgetting any other possibility like a mod operation solution to the problem.
science_man_88 is offline   Reply With Quote
Old 2014-04-23, 22:17   #57
Batalov
 
Batalov's Avatar
 
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2

36·13 Posts
Default

Your post makes about as much sense as this test from Being John Malkovich, or closer to this forum these scribbles. Well, not much can be done about "Kathy", but can you before posting first shape your thoughts in some coherent form? hmm?
Batalov is offline   Reply With Quote
Old 2014-04-23, 22:37   #58
science_man_88
 
science_man_88's Avatar
 
"Forget I exist"
Jul 2009
Dumbassville

26×131 Posts
Default

Quote:
Originally Posted by Batalov View Post
Your post makes about as much sense as this test from Being John Malkovich, or closer to this forum these scribbles. Well, not much can be done about "Kathy", but can you before posting first shape your thoughts in some coherent form? hmm?
okay let me put it this way:
1) Is there anything special above what is special about the k values in factors of normal mersenne factors, hidden within the k values of double mersenne factors ?
science_man_88 is offline   Reply With Quote
Old 2014-04-27, 15:00   #59
pdazzl
 
Apr 2014

7·17 Posts
Default

This is somewhat but not directly related to the topic; something I've noticed(checking mersenne.ca) is that it appears no mersenne prime (or primes that show up as factors in the Lucas Lehmer chain) are factors for any mersenne candidates. Is there a reason/property anyone can see for why this might be?


14
--- Factors
2
7

194
--- Factors
2
97


194^2-2
--- Factors
2
31
607


(194^2-2)^2-2
--- Factors
2
708158977


((194^2-2)^2-2)^2-2
--- Factors
2
127
7897466719774591


(((194^2-2)^2-2)^2-2)^2-2)
--- Factors
2
22783
265471
592897
2543310079
220600496383


((((194^2-2)^2-2)^2-2)^2-2)^2-2
--- Factors
2
113210499946729046527
71510428488234435849323250891975205208728978040847871


(((((194^2-2)^2-2)^2-2)^2-2)^2-2)^2-2
--- Factors
2
3867637345756894712411491994657791
4141173562324283362391211134773751434933274141271057666869711137355139870107549772907161419207982079



((((((194^2-2)^2-2)^2-2)^2-2)^2-2)^2-2)^2-2
--- Factors
2
1049179854847
27293256153178849431531258375109421840383
pdazzl is offline   Reply With Quote
Old 2014-04-27, 17:31   #60
science_man_88
 
science_man_88's Avatar
 
"Forget I exist"
Jul 2009
Dumbassville

26·131 Posts
Default

Quote:
Originally Posted by pdazzl View Post
This is somewhat but not directly related to the topic; something I've noticed(checking mersenne.ca) is that it appears no mersenne prime (or primes that show up as factors in the Lucas Lehmer chain) are factors for any mersenne candidates. Is there a reason/property anyone can see for why this might be?


14
--- Factors
2
7

194
--- Factors
2
97


194^2-2
--- Factors
2
31
607


(194^2-2)^2-2
--- Factors
2
708158977


((194^2-2)^2-2)^2-2
--- Factors
2
127
7897466719774591


(((194^2-2)^2-2)^2-2)^2-2)
--- Factors
2
22783
265471
592897
2543310079
220600496383


((((194^2-2)^2-2)^2-2)^2-2)^2-2
--- Factors
2
113210499946729046527
71510428488234435849323250891975205208728978040847871


(((((194^2-2)^2-2)^2-2)^2-2)^2-2)^2-2
--- Factors
2
3867637345756894712411491994657791
4141173562324283362391211134773751434933274141271057666869711137355139870107549772907161419207982079



((((((194^2-2)^2-2)^2-2)^2-2)^2-2)^2-2)^2-2
--- Factors
2
1049179854847
27293256153178849431531258375109421840383
Yes, simply put, since s at that point has remainder of 0 when divided by these factors the next s will have 0^2-2 = factor-2 remainder from this factor, the next s after that has (-2)^2-2 which gets you to 2, 2^2-2 = 2 so you never move from 2 like the mersenne primes themselves so only sequences that hit 2 remainder a mersenne can possibly be have that mersenne divide by it but the only scenario I know that causes this is when the mersenne is prime and hence has no prime factors other than itself. it would have to divide the lower mersennes if that.
science_man_88 is offline   Reply With Quote
Old 2014-04-27, 20:49   #61
science_man_88
 
science_man_88's Avatar
 
"Forget I exist"
Jul 2009
Dumbassville

838410 Posts
Default practically impossible

I know if we could factor any residue mod Mp we probably wouldn't need the LL test but is this feasible for low p values:

a = LL residue mod Mp

factor a and then eliminate k values based on k*p = (prime factors -1)/2 mod prime factors so if p is x mod prime factors k is y or z mod the prime factors ?

edit: I'm just realizing this again probably

Last fiddled with by science_man_88 on 2014-04-27 at 20:52
science_man_88 is offline   Reply With Quote
Old 2014-04-28, 02:51   #62
pdazzl
 
Apr 2014

7·17 Posts
Default

Something I was trying out today was running an LL just on the factors without the embedded 2, was doing some compares against the original LL
(Doing this via ^2, *2, -1 instead of ^2-2), seems to result in smaller residues to calculate overall but unfortunately an extra operation.


2*(2^2)-1=7

2*(7^2)-1=97

2*(97^2)-1=18817
pdazzl is offline   Reply With Quote
Old 2014-04-28, 03:07   #63
TheMawn
 
TheMawn's Avatar
 
May 2013
East. Always East.

6BF16 Posts
Default

Quote:
Originally Posted by science_man_88 View Post
I know if we could factor any residue mod Mp we probably wouldn't need the LL test but is this feasible for low p values:
I believe the residue is already mod MP
TheMawn is offline   Reply With Quote
Old 2014-04-28, 03:59   #64
LaurV
Romulan Interpreter
 
LaurV's Avatar
 
Jun 2011
Thailand

7×1,373 Posts
Default

Channeling my inner RDS, why is this stuff in the math forum?
LaurV is offline   Reply With Quote
Old 2014-04-28, 11:22   #65
science_man_88
 
science_man_88's Avatar
 
"Forget I exist"
Jul 2009
Dumbassville

26×131 Posts
Default

Quote:
Originally Posted by TheMawn View Post
I believe the residue is already mod MP
I know , I did however end up writing it with an assumption I don't know why I made and that was a= 0 mod 2kp+1.
science_man_88 is offline   Reply With Quote
Old 2014-05-05, 12:10   #66
Qubit
 
Qubit's Avatar
 
Jan 2014

2·19 Posts
Default

Quote:
Originally Posted by pdazzl View Post
This is somewhat but not directly related to the topic; something I've noticed(checking mersenne.ca) is that it appears no mersenne prime (or primes that show up as factors in the Lucas Lehmer chain) are factors for any mersenne candidates. Is there a reason/property anyone can see for why this might be?
Other ways to see this are:
1. Recall that every two prime-exponent Mersenne numbers are coprime (that is, they share no common factor greater than 1). What you noticed follows.
or 2. Recall that if M(p) divides M(q) (p, q are odd primes) then M(p)\equiv 1 (mod q), which is a contradiction since q cannot divide an even number.

(Also, unrelated, notice that p never divides 2^p-1.)
Qubit is offline   Reply With Quote
Reply



Similar Threads
Thread Thread Starter Forum Replies Last Post
Distribution of Mersenne Factors tapion64 Miscellaneous Math 21 2014-04-18 21:02
Known Mersenne factors CRGreathouse Math 5 2013-06-14 11:44
A strange new (?) fact about Mersenne factors ChriS Math 14 2006-04-12 17:36
Factors of Mersenne Numbers asdf Math 17 2004-07-24 14:00
Factors of Mersenne numbers ? Fusion_power Math 13 2003-10-28 20:52

All times are UTC. The time now is 17:55.


Fri Jul 16 17:55:46 UTC 2021 up 49 days, 15:43, 1 user, load averages: 1.46, 1.54, 1.52

Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2021, Jelsoft Enterprises Ltd.

This forum has received and complied with 0 (zero) government requests for information.

Permission is granted to copy, distribute and/or modify this document under the terms of the GNU Free Documentation License, Version 1.2 or any later version published by the Free Software Foundation.
A copy of the license is included in the FAQ.