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#67 |
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If I May
"Chris Halsall"
Sep 2002
Barbados
2×67×73 Posts |
Not a dumb question at all. Yes -- I could do that, but I've decided instead to use the equations which are already known rather than spider and parse yet another PrimeNet page.
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#68 | |
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If I May
"Chris Halsall"
Sep 2002
Barbados
2×67×73 Posts |
Quote:
So far, 20 P-1 tests have been run by six workers, with one factor found as a result. (Congrats monst!!!) And thanks again to James for making the PHP code for GHz Days credit calculation so readily available. I just wish he worked in Perl....
Last fiddled with by chalsall on 2011-11-12 at 18:42 Reason: s/and automatically/and will automatically/ |
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#69 | |
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"Lucan"
Dec 2006
England
2×3×13×83 Posts |
Quote:
Long may it continue! David Last fiddled with by davieddy on 2011-11-12 at 23:05 |
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#70 |
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If I May
"Chris Halsall"
Sep 2002
Barbados
2·67·73 Posts |
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#71 | ||
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"Richard B. Woods"
Aug 2002
Wisconsin USA
22×3×641 Posts |
Quote:
The algorithm uses the Dickman function (http://en.wikipedia.org/wiki/Dickman_function , http://mathworld.wolfram.com/DickmanFunction.html) to calculate the probability of finding a smooth factor up to a given limit. The way that the TF limit enters is that there is zero probability of finding a factor below the limit of TF already done. (If TF already found a factor, why are you here?) So, the probability of finding a smooth factor, for the purposes of the P-1 bounds-choosing algorithm, below a given limit L (with L > TFed limit) is: Probability of a smooth factor below L, using the Dickman function minus Probability of a smooth factor below (the TFed limit), also using the Dickman function Quote:
If TF is deeper (TF limit is higher), then the probability of P-1 finding a not-found-by-TF factor under a chosen limit L, (L > TFed limit), is lower. So, in order to have the same chance of finding a not-found-by-TF factor, the P-1 bounds have to be higher. But this increases the "cost" of the P-1, so that decreases the desirability of P-1 when balanced against the "cost" of further LL, which leads to choosing lower P-1 bounds. Last fiddled with by cheesehead on 2011-11-13 at 02:41 |
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#72 |
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Basketry That Evening!
"Bunslow the Bold"
Jun 2011
40<A<43 -89<O<-88
3×29×83 Posts |
I meant that P-1 has to do less work for an overall equal percentage, meaning if each exponent has a 5% factor limit and TF does 3% instead of 2, then P-1 only has to do 2% instead of three. (Of course those numbers are completely made up crap and you're post is still much more correct than anything I've posted.)
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#73 | |
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Jun 2003
100100100012 Posts |
Quote:
But this is not what the P-1 bounds calculation is trying to determine. Rather, the algorithm seeks to maximise the expected time LL time saved, (i,e. the probability of success times the time to do the LL(s)) less the time of the P-1 computation itself. As the bounds (and consequently the computation time) increases, so does the probability. But the law of diminishing returns applies. P95 chooses limits at the point where the expected benefit of doing one more iteration of either stage 1 and stage 2 falls to equal the cost of doing that iteration. If more TF has been done, then the benefit of doing P-1 is reduced, and this crossover point is reached sooner, hence more TF implies less P-1. This has nothing to do with equalising the overall probability of success. |
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#74 |
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"Lucan"
Dec 2006
England
2·3·13·83 Posts |
Two points:
1) Near optimum, a tadge off makes little difference. A good example is that no-one around here questions the "bitlevel" as a sensible granularity for TF 2) Finding a factor is obviously better than proving a number composite. David Last fiddled with by davieddy on 2011-11-13 at 12:04 |
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#75 | ||
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Jun 2003
100100100012 Posts |
Quote:
Quote:
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#76 | |
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"Lucan"
Dec 2006
England
194A16 Posts |
Quote:
While we all have faith in the validity of LL (Some of us even understand why it works) there seems to be a number who get an erection every time they find a factor. David Last fiddled with by davieddy on 2011-11-13 at 13:22 |
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#77 |
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May 2011
Orange Park, FL
3·5·59 Posts |
Last night it gave me 2,533.628 GHz days credit for exponent 48276133 and indicates I found a factor. Gimps says
Manual testing 48276133 NF 2011-11-13 00:06no factor for M48276133 from 2^70 to 2^71 4.9533 Manual testing 48276133 NF 2011-11-13 00:06no factor for M48276133 from 2^69 to 2^70 2.4767 Chuck |
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