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#144 |
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Jun 2009
22·32·19 Posts |
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#145 |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
2·7·677 Posts |
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#146 |
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"William"
May 2003
New Haven
93E16 Posts |
PRP list had 10^338*4+10^169*6+3
It's obviously 4x^2+6x+3, and P-1 factors as (2x+1)*(x+1) I see other large PRPs from forms like this, but there are cofactors after removing small divisors, so the algebra doesn't work. Last fiddled with by wblipp on 2013-10-16 at 17:02 Reason: grammerr |
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#147 |
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"William"
May 2003
New Haven
1001001111102 Posts |
Spotted (311^898+1)/96722 in the PRP list today. The denominator is 311^2, so P-1 is (311^896-1). Helping factordb find the algebraic factors enabled the proof.
Last fiddled with by wblipp on 2013-10-16 at 17:06 Reason: algebra |
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#148 |
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"William"
May 2003
New Haven
93E16 Posts |
Found (2^9053+7)/39 in the PRP list. Adding the algebraic factors of (2^9048-1) enabled the N-1 proof.
Also (2^9066*67-1)/267, which needed algebraic factors from 2^9064-1 to enable the N-1 proof. And (10^2731*7-67)/3 And (828^937-1)/827 And (2^9099+7)/15 10^2739+10^297-1 already had all the N+1 factors. All I did was press the proof button. (2^9109*7+1)/15 Last fiddled with by wblipp on 2013-10-18 at 05:47 Reason: Add additonal factorizations |
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#149 |
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Sep 2010
Scandinavia
3×5×41 Posts |
I factored (5189^303+1)/(5189^101+1).
That enabled the N-1 proof of (5189^607-1)/5188. |
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#150 |
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Feb 2012
Paris, France
7·23 Posts |
2^13645-511<4108> was waiting for someone to click on the "Proof" button (N-1), I did it.
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#151 |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
100101000001102 Posts |
(10^6439*8-791)/9 also waited for a click (by N-1).
(I've found it in M.Kamada's primesize.txt list; and after that checked that Phi6437(10) has had a certificate since 2008. Factordb also had it on record.) |
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#152 |
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Sep 2010
Scandinavia
11478 Posts |
I factored 252^473-1.
That enabled the N-1 proof of (252^947-1)/251. I'm doing a lot of these. |
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#153 |
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"William"
May 2003
New Haven
2×7×132 Posts |
(2^27721*57-1)/113 and (2^27721*55-1)/109 needed the known factors (2^27720-1) added to the N-1. Fortunately doing the first automatically spilled over into the second.
Last fiddled with by wblipp on 2013-11-10 at 05:13 |
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#154 |
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Feb 2012
Paris, France
7·23 Posts |
Factoring the remaining C109 in 2097^63-1 enabled the N-1 proof of (2097^757-1)/2096
The proofs of the following ones were enabled by adding algebraic factors to N-1 or N+1 2^8451-9 => N+1 (2^8461*91-1)/181 => N-1 (2^8465+3)/35 => N-1 |
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