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Old 2013-06-06, 05:36   #144
Puzzle-Peter
 
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Quote:
Originally Posted by firejuggler View Post
(and sorry Puzzle-Peter, i snatched this one from you)
That's fine. They're only a few minutes of work each. But I must admit I was wondering about some of my certificates not being needed when I uploaded them.
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Old 2013-06-09, 00:36   #145
Batalov
 
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38502*529^38502-1 ;-)

My first tiny GW prime. (Outside of FactorDB, it is proven of course.)
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Old 2013-09-08, 13:39   #146
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PRP list had 10^338*4+10^169*6+3

It's obviously 4x^2+6x+3, and P-1 factors as (2x+1)*(x+1)

I see other large PRPs from forms like this, but there are cofactors after removing small divisors, so the algebra doesn't work.

Last fiddled with by wblipp on 2013-10-16 at 17:02 Reason: grammerr
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Old 2013-10-16, 17:05   #147
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Spotted (311^898+1)/96722 in the PRP list today. The denominator is 311^2, so P-1 is (311^896-1). Helping factordb find the algebraic factors enabled the proof.

Last fiddled with by wblipp on 2013-10-16 at 17:06 Reason: algebra
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Old 2013-10-18, 04:11   #148
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Found (2^9053+7)/39 in the PRP list. Adding the algebraic factors of (2^9048-1) enabled the N-1 proof.

Also (2^9066*67-1)/267, which needed algebraic factors from 2^9064-1 to enable the N-1 proof.

And (10^2731*7-67)/3

And (828^937-1)/827

And (2^9099+7)/15

10^2739+10^297-1 already had all the N+1 factors. All I did was press the proof button.

(2^9109*7+1)/15

Last fiddled with by wblipp on 2013-10-18 at 05:47 Reason: Add additonal factorizations
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Old 2013-11-02, 21:21   #149
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I factored (5189^303+1)/(5189^101+1).
That enabled the N-1 proof of (5189^607-1)/5188.
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Old 2013-11-06, 18:14   #150
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2^13645-511<4108> was waiting for someone to click on the "Proof" button (N-1), I did it.
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Old 2013-11-06, 18:40   #151
Batalov
 
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(10^6439*8-791)/9 also waited for a click (by N-1).

(I've found it in M.Kamada's primesize.txt list; and after that checked that Phi6437(10) has had a certificate since 2008. Factordb also had it on record.)
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Old 2013-11-06, 20:23   #152
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I factored 252^473-1.
That enabled the N-1 proof of (252^947-1)/251.

I'm doing a lot of these.
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Old 2013-11-10, 05:11   #153
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(2^27721*57-1)/113 and (2^27721*55-1)/109 needed the known factors (2^27720-1) added to the N-1. Fortunately doing the first automatically spilled over into the second.

Last fiddled with by wblipp on 2013-11-10 at 05:13
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Old 2013-11-10, 16:37   #154
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Factoring the remaining C109 in 2097^63-1 enabled the N-1 proof of (2097^757-1)/2096
The proofs of the following ones were enabled by adding algebraic factors to N-1 or N+1
2^8451-9 => N+1
(2^8461*91-1)/181 => N-1
(2^8465+3)/35 => N-1
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