Standard crank division by zero thread - Page 57

jasonp · 2012-12-17, 18:58

Agree. Locked (for now)

Edit: now reopened (my early Christmas gift)

Don Blazys · 2013-01-03, 07:27

Welcome back to my very popular "online classroom".
I hope you all had a wonderful Christmas and a great New Year!

Quoting "NBtarheel_33":

Quote:

Don, you may have already mentioned this somewhere up the thread,
but what are the domains of c and T? All reals? Integers?
Nonnegative integers? This question needs to be settled before we can
really consider the question that you have set here.

We are considering positive integer variables whose implied domains
are as follows:

c is an element of {1,2,3...},
T is an element of {2,3,4...}.

And the question that we are considering is...

Given the identity:

$<br /> \left(\frac{T}{T}\right)*c^{3}=T*\left(\frac{c}{T}\right)^{\frac{\frac{3*\ln(c)}{\ln(T)}-1}{\frac{\ln(c)}{\ln(T)}-1}} <br />$

can we substitute

$\left(\frac{c}{c}\right)$ for $\left(\frac{T}{T}\right)$ ?

"LaurV" says:

Quote:

Yes.

"Rajula" says:

Quote:

Yes or no.

Paul Leyland says:

Quote:

No.

Mark Rodenkirch says:

Quote:

No...

Don Blazys says:

Quote:

No.

"Dubslow" says:

Quote:

No...

So... what do you say?
Please just answer either yes or no without any commentary whatsoever.

axn · 2013-01-03, 07:55

Quote:

Originally Posted by jasonp

Agree. Locked (for now)

Edit: now reopened (my early Christmas gift)

http://www.imdb.com/title/tt0063442/quotes?qt=qt0482675

Don Blazys · 2013-01-03, 08:12

Bunny rabbit "axn" was clearly unable to answer either yes or no.

akruppa · 2013-01-03, 11:35

This, too has been discussed ad nauseam in this thread. The identity holds only on the condition c!=T, and under this condition you can make the substitution, so the red herring on the RHS simplifies to the LHS again.

So, question for you, Blazys:

Given a rational a/b and integer c, under which conditions does

a/b = (ac)/(bc)

hold?

a) Under the condition c != 0
b) With no further conditions

Don't post unless you answer this.

pinhodecarlos · 2013-01-03, 23:38

What we've got here is (a) failure to communicate

ewmayer · 2013-01-04, 01:38

Quote:

Originally Posted by pinhodecarlos

What we've got here is (a) failure to communicate

Couple of weeks ago got to see the late Strother Martin in that Saturday night's creature feature, the low-budget snakefest with the vowel-challenged title Sssssss. His daughter in that was played by Heather Menzies (who later married Robert Urich and added that name via hyphenation concatenation), who played one of the Von Trapp children in the decidedly snake-less^* The Sound of Music. Good stuff.

Which gives me an idea: How 'bout we ~~per~~convert this "endless flaming over trivial identities disguised as needlessly obfuscated formulae" thread into a more socially useful "In memory of Strother Martin" thread?

--------------

^* (unless you count Herr Captain V.T. and Maria eventually hooking up, but hey, this is a family-friendly venue, so keep it clean, you troglodytes.)

akruppa · 2013-01-04, 13:04

You failed to respond to my question. Please try again.

Don Blazys · 2013-01-04, 13:09

What happened to my last post?

akruppa · 2013-01-04, 13:13

I removed it. As I said, don't post unless you answer my question, which you have failed to do.

LaurV · 2013-01-04, 13:15

Quote:

Originally Posted by Don Blazys

What happened to my last post?

Someone substituted c/c to T/T into it and it magically disappeared due to division by zero...

2012-12-17, 18:58	#617
jasonp Tribal Bullet Oct 2004 6727₈ Posts	Agree. Locked (for now) Edit: now reopened (my early Christmas gift) Last fiddled with by jasonp on 2012-12-21 at 14:28

2013-01-03, 11:35	#621
akruppa "Nancy" Aug 2002 Alexandria 2,467 Posts	This, too has been discussed ad nauseam in this thread. The identity holds only on the condition c!=T, and under this condition you can make the substitution, so the red herring on the RHS simplifies to the LHS again. So, question for you, Blazys: Given a rational a/b and integer c, under which conditions does a/b = (ac)/(bc) hold? a) Under the condition c != 0 b) With no further conditions Don't post unless you answer this. Last fiddled with by akruppa on 2013-01-03 at 19:42 Reason: Typos

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2013-01-03, 08:12	#620
Don Blazys Feb 2011 163 Posts	Bunny rabbit "axn" was clearly unable to answer either yes or no.

2013-01-03, 23:38	#622
pinhodecarlos "Carlos Pinho" Oct 2011 Milton Keynes, UK 3×17×97 Posts	What we've got here is (a) failure to communicate

2013-01-04, 13:04	#624
akruppa "Nancy" Aug 2002 Alexandria 2467₁₀ Posts	You failed to respond to my question. Please try again.

2013-01-04, 13:09	#625
Don Blazys Feb 2011 243₈ Posts	What happened to my last post?

2013-01-04, 13:13	#626
akruppa "Nancy" Aug 2002 Alexandria 4643₈ Posts	I removed it. As I said, don't post unless you answer my question, which you have failed to do.