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#144 | |
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"Forget I exist"
Jul 2009
Dumbassville
26·131 Posts |
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#145 | |
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"Forget I exist"
Jul 2009
Dumbassville
26×131 Posts |
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2) basically your stating that x!~x 3) the full list would them come to: son is a sibling of daughter, daughter is a sibling of son. 4) because you have defined x!~x this relation can't be reflexive in my mind. from that it can't have all 3 properties needed to be an equivalence relation |
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#146 |
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Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
3×5×719 Posts |
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#147 |
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"Forget I exist"
Jul 2009
Dumbassville
100000110000002 Posts |
Sorry Paul I didn't see an easy way forward ( I know not all paths are easily proven, so I must stop doing this).
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#148 | ||
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Jun 2003
7×167 Posts |
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Ordinary sets are unordered. The set {Mother, Father} is the same as the set {Father, Mother}. Pairs are ordered. (Mother, Father) is different from (Father, Mother). |
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#149 | |
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Nov 2003
22·5·373 Posts |
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some fairly deep combinatorics, (i.e. Polya's Counting Theorem). [i.e. consider duplicates induced by symmetries, rotations, and reflections] |
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#150 |
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"Forget I exist"
Jul 2009
Dumbassville
100000110000002 Posts |
Well I've come across something similar in number freak but it talks about Burnside's lemma. I just haven't wrapped my brain around many questions like this.
Last fiddled with by science_man_88 on 2011-01-21 at 13:53 |
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#151 | |||||||
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Jun 2003
116910 Posts |
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Last fiddled with by Mr. P-1 on 2011-01-21 at 14:12 |
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#152 | |
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Jun 2003
7·167 Posts |
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In fact, my question is just a disguised version of the question asked by CRGreathouse earlier in the thread: if S = {1, 2, 3, 4, 5,}, how many different binary relations are there on S? |
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#153 | ||
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Jun 2003
7×167 Posts |
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#154 | |
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"Forget I exist"
Jul 2009
Dumbassville
26·131 Posts |
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