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#1 |
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Jun 2005
11000102 Posts |
Something to befuddle your minds with
(however, do not believe everything I say) One can very easily set up the following trigenomical identity: (1+Tan^2 A)(1+Cos 2A) = 2 … (1) (one plus tan squared A)... and its conjugate (1+Cot^2 B)(1-Cos 2B)=2 …(2) when A->pi/2 (90 degrees) or B->0 then (1+Tan^2 A) approaches infinity and (1+Cos 2A) approaches zero ( Cos pi = -1) but (1) is true hence infinity times zero equals two Try it yourself, identities (1) and (2) are true Now you have the fools-proof that: Infinity times Zero equals Two.
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#2 |
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Undefined
"The unspeakable one"
Jun 2006
My evil lair
6,793 Posts |
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#3 | |
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"Forget I exist"
Jul 2009
Dartmouth NS
8,461 Posts |
Quote:
1/2*PI + 1/24*PI^3 + 1/240*PI^5 + 17/40320*PI^7 + 31/725760*PI^9 + 691/159667200*PI^11 + 5461/12454041600*PI^13 + 929569/20922789888000*PI^15 + O(PI^17) |
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#4 |
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Nov 2008
2×33×43 Posts |
It should be Pi not PI. But even then I get -3.961408125 E28, and this number tends to -infinity as realprecision in Pari tends to +infinity. The same thing happens with tan(Pi) (except the number is very small, tending to 0 as realprecision tends to infinity). What's going on here?
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#5 | |
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"Forget I exist"
Jul 2009
Dartmouth NS
8,461 Posts |
Quote:
Code:
(11:13) gp > tan(Pi/2) *** tan: can't compute tan(Pi/2 + kPi). |
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