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#67 | |
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"Mark"
Apr 2003
Between here and the
24×397 Posts |
Quote:
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#68 |
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Aug 2005
Seattle, WA
33408 Posts |
Fair enough. I can't claim any expertise on (or even passing knowledge of) how these things work in Windows. Is there really no way to do the equivalent of sending a signal to just the ecmclient process? My reading of the code, even for Windows, is that ecmclient behaves exactly the same way as I described. It's just a question of what the ecm process will do.
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#69 | |
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"Mark"
Apr 2003
Between here and the
24·397 Posts |
Quote:
To me the important thing is that the software behaves in a simple, predictable fashion and that a user has some ability to control the software's behavior without understanding the code behind it. I won't preclude anyone from using SIGTERM, but I doubt that it would be the preferred method for users to shutdown the client. FYI, out of habit I never rely on software to handle SIGTERM cleanly. Maybe I'm paranoid, but that is me. I do rely on software to handle SIGINT correctly. |
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#70 |
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"Mark"
Apr 2003
Between here and the
24×397 Posts |
I was merrily testing today when I realized that I hadn't written a piece of code that is needed: the recursive factoring of composites co-factors. I wrote the code, but then I wondered if I designed the tables optimally. I pose a question to you, the users of the ECMNet server to get you opinions.
Should I treat the new database similar to the current ini file, where connection between composite co-factor and original composite is lost (if you don't consider that the prefix of the composite co-factor name is the same as the original composite name) or should I continue to track the original composite and treat each factor as a child to that composite? This is the first option would look like in the database: Code:
composite a factor a-1 factor a-2 composite a-1 factor a-1-1 factor a-1-2 composite a-1-2 factor a-1-2-1 factor a-1-2-2 ... Code:
composite a factor a-1 factor a-2 factor a-3 ... factor a-n I'm personally leaning toward the second option because it makes more logical sense. Opinions? |
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#71 |
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"William"
May 2003
New Haven
2·7·132 Posts |
I seldom use automatic recursive factorization, so my opinion should be given low weight. I prefer option 2.
William |
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#72 | |
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Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
47×229 Posts |
Quote:
Paul |
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#73 |
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"Mark"
Apr 2003
Between here and the
24·397 Posts |
Okay, that is what I will do. It will cost me some time and delay the release.
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#74 |
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"Mark"
Apr 2003
Between here and the
24·397 Posts |
Does anyone care about "difficulty"? The difficulty is computed as the total work done * (decimal length^2). You can set up a strategy to order work by difficulty, with less difficult numbers to be factored before more difficult numbers.
Note that there is already a means to order work selection by total work and one to order work selected by decimal length. This would be a carry over from 2.x. There will be no means to order work selection by b1, as it is presumed that total work should be sufficient. Total work is computed by sum(b1 * ECM curves for b1) for all b1. Opinions? |
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#75 |
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"William"
May 2003
New Haven
2·7·132 Posts |
I use difficulty a lot - usually 60-90% in the configuration. I like the resulting spread of much more work for smaller numbers.
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#76 | |
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Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
47×229 Posts |
Quote:
Code:
// strategy0 - random // strategy1 - by lowest B1 that needs curves done and total work done // strategy2 - by total work done // strategy3 - by difficulty // strategy4 - by length and total work done //strategy0=20:20:0:0:0 strategy0=00:20:0:0:0 //strategy1=80:20:0:0:0 strategy1=100:20:0:0:0 strategy2=0:20:0:0:0 strategy3=0:20:0:0:0 strategy4=0:20:0:0:0 To be honest, I've never used any complex strategies during my entire experience of running your code. The last three have always had 0:20:0:0:0 and the last three figures on every line have never been anything other than 0:0:0. I'm a bear of very little brain and those things confuse me. Paul Paul |
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#77 | |
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Bamboozled!
"πΊππ·π·π"
May 2003
Down not across
47·229 Posts |
Quote:
Paul |
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