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#551 | |
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Feb 2012
34·5 Posts |
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#552 |
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Aug 2010
Kansas
54710 Posts |
Composite exponent + composite divisor= ?
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#553 | ||
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Jun 2003
2×3×7×112 Posts |
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Last fiddled with by axn on 2012-10-06 at 04:03 |
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#554 |
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Sep 2002
17·47 Posts |
P-1 found a factor in stage #2, B1=530000, B2=9805000.
UID: Jwb52z/Clay, M58188989 has a factor: 55849484816777970918764473 85.530 bits. |
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#555 |
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Sep 2006
Odenton, MD, USA
22·41 Posts |
Two factors found with Brent-Suyama:
P-1 found a factor in stage #2, B1=260000, B2=6305000, E=12. M4037023 has a factor: 46132411290706485444839 k = 5713667136737453 = 17 × 31 × 53 × 1327 × 154,154,969 P-1 found a factor in stage #2, B1=290000, B2=7395000, E=12. M4438789 has a factor: 1402524780745530895151 k = 157985069885675 = 5^2 × 73883 × 85,532,569 |
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#556 |
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"Åke Tilander"
Apr 2011
Sandviken, Sweden
2·283 Posts |
ANONYMOUS Manual testing 1019 F-ECM Oct 13 2012 2:05AM 0.0 0.0000 1140356877758679056056869944845540826402854641895928218298013381554156431441
249.334 bits Quote from http://www.mersenne.org/report_recent_cleared/ There are now 4 known factors of M1019 with a total size of 452.3 bits Factor was not found by me. It would be interesting to know who was the "Anonymous" this time? 13th biggest known factor of any Mp (not counting the biggest factors of fully factored Mps). Does anyone know wether the remaining 567-bit factor is composite or not? OK Now I have found this post. Adding a question: Does "prp" in frmky:s log mean that the factors are probable primes, not proven to be primes? Last fiddled with by aketilander on 2012-10-13 at 10:39 |
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#557 |
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Apr 2012
993438: i1090
2·73 Posts |
Found by NFS@home
http://escatter11.fullerton.edu/nfs/...ead.php?id=386 The remaining 567-bit factor is prime Last fiddled with by Jatheski on 2012-10-13 at 10:16 |
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#558 | |
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Basketry That Evening!
"Bunslow the Bold"
Jun 2011
40<A<43 -89<O<-88
3×29×83 Posts |
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#559 | |
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"Åke Tilander"
Apr 2011
Sandviken, Sweden
2×283 Posts |
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#560 | ||
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May 2007
Kansas; USA
22×19×137 Posts |
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For what it's worth: M268435456 = 3 * 5 * 17 * 257 * 641 * 65537 * 6700417 * ?? Or more interestingly M(2^28) = (2^1+1) * (2^2+1) * (2^4+1) * (2^8+1) * (2^16+1) * (2^32+1) * ?? Note that 2^32+1 = 641 * 6700417. Edit: The question is: How long does this sequence continue? In other words are 2^64+1 and 2^128+1 factors also? Last fiddled with by gd_barnes on 2012-10-14 at 09:36 Reason: edit |
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#561 |
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May 2007
Kansas; USA
22×19×137 Posts |
After some analysis, I just answered my own question above. I'm sure many on here recognize this but I did not. I'll state it for others like me who did not know the following:
For any 2^(2^q)-1 where q is sufficiently large, algebraic factors are: Code:
[2^(2^0)+1] * [2^(2^1)+1] * [2^(2^2)+1] * [2^(2^3)+1] * [2^(2^4)+1] * ..... * [2^(2^(q-1))+1] Code:
[2^(2^0)+1] * [2^(2^1)+1] * [2^(2^2)+1] * [2^(2^3)+1] * [2^(2^4)+1] * ..... * [2^(2^27)+1] Last fiddled with by gd_barnes on 2012-10-15 at 00:21 |
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