PARI's commands

[science_man_88]

Originally Posted by CRGreathouse

I can't quite follow you, but

n=0;
while(1,
  print1(n++);
  if(n>9, break);
  print1(", ")
);

does the trick.

Wonder how fast we could finish off the list? You know most of them by the sounds of it. I'm still a little stumped on how to fix my rle script but I know ( and ) shouldn't be used to code something with. By the looks of it and I need ways to check for control characters,spaces and numbers that appear out of nowhere
in the strings but aren't part of the count of characters) maybe a Vec, and a scan of type will do but maybe not. I'm so stupid maybe tab in between would help lol.

[science_man_88]

if something can be done to files in the file system root:

http://rosettacode.org/wiki/File_size the hard part to this one that must have landed it in the too hard category must be how to read the original given file size to compare something with.

[science_man_88]

http://rosettacode.org/wiki/Pascal's_triangle/Puzzle

Doesn't sound hard in one sense.

solve:

[ 151]
[ ][ ]
[40][ ][ ]
[ ][ ][ ][ ]
[ X][11][ Y][ 4][ Z]

first piece I can gather is x+y+22 = 40;so x+y=18 this is a fact to check for; also once a pair of x and y =18; also x+2y+z+30 = 151; so x+2y+z = 121; another fact to check for when going through z values.

[science_man_88]

for(x=0,18,for(y=0,18,if(x+y=18,for(z=1,103,if((x+2*y+z)==121,print(x","y","z);break(3))))))

First one it found was 0,18,85 . It never says the program has to use only the data given, I used what I could gather.

[science_man_88]

Originally Posted by science_man_88

for(x=0,18,for(y=0,18,if(x+y=18,for(z=1,103,if((x+2*y+z)==121,print(x","y","z);break(3))))))

First one it found was 0,18,85 . It never says the program has to use only the data given, I used what I could gather.

oops forgot y=x+z but that doesn't work I've messed up

[science_man_88]

I've determined y=13 by:


[ 6y+x+z+4a[2]+4a[4]= 7y +4a[2]+4a[4]]
[3y+x+37 ][3y+z+23]
[40=x+y+22][ 2y+15][ y+z+8 ]
[ x+11 ][y+11 ][y+4 ][z+4 ]
[ X][11][ Y][ 4][ Z]

if a = [] bottom row


for this sized triangle we see in this case 151-(44+16) = 91 ; 91/7 =13 y=13
40-13-22 =x = 5; 13-5=z=8;

however I now know how to solve it in this case.

[science_man_88]

 Pascals_triangle_puzzle(topvalue=151,leftsidevalue=40,bottomvalue1=11,bottomvalue2=4) = {
y=(topvalue-(4*(bottomvalue1+bottomvalue2)))/7;
x=leftsidevalue-(y+2*bottomvalue1);
z=y-x;
print(x","y","z); }

This easy enough ? I might try to make one for any size. just have to figure out the patterns lol.

[3.14159]

I figured out how to falsify factoring a large number (somewhat);

[866876601688257388041953428681474799611455578456879011971315052706094788178469895182220494116473202297231530219967803566778120639 528365543601153323389150907773258262552994601295053933845142213535320241754514748728875053183803012869853716977772216817067444377]

[361704130063529693429159107448019863732305480622816041454555619831169499041663864963068219490947259594777674878198147873998732309 326729818580681541350657067987755793696856969106820654842683490163988042729198926945304899046855890448333533668661395285070725039]

Which is..

866876601688257388041953428681474799611455578456879011971315052706094788178469895182220494116473202297231530219967803566778120639528365543601153323389150907773258262552994601295053933845142213535320241754514748728875053183803012869853716977772216817067444377 * 361704130063529693429159107448019863732305480622816041454555619831169499041663864963068219490947259594777674878198147873998732309326729818580681541350657067987755793696856969106820654842683490163988042729198926945304899046855890448333533668661395285070725039

[science_man_88]

Originally Posted by 3.14159

I figured out how to falsify factoring a large number (somewhat);

[866876601688257388041953428681474799611455578456879011971315052706094788178469895182220494116473202297231530219967803566778120639 528365543601153323389150907773258262552994601295053933845142213535320241754514748728875053183803012869853716977772216817067444377]

[361704130063529693429159107448019863732305480622816041454555619831169499041663864963068219490947259594777674878198147873998732309 326729818580681541350657067987755793696856969106820654842683490163988042729198926945304899046855890448333533668661395285070725039]

Which is..

866876601688257388041953428681474799611455578456879011971315052706094788178469895182220494116473202297231530219967803566778120639528365543601153323389150907773258262552994601295053933845142213535320241754514748728875053183803012869853716977772216817067444377 * 361704130063529693429159107448019863732305480622816041454555619831169499041663864963068219490947259594777674878198147873998732309326729818580681541350657067987755793696856969106820654842683490163988042729198926945304899046855890448333533668661395285070725039

finally Pi is back lol.

[3.14159]

Originally Posted by science_man_88

finally Pi is back lol.

Thanks. I get + 1 years added to my current age today.

[CRGreathouse]

Originally Posted by science_man_88

so in other words if(string==type(0) ||string==type(1/2), print("this string is numerical")) would work ?

No.

if(type(string) == "t_STR", print("It's a string."))

Originally Posted by science_man_88

Though I haven't covered floating point types.

t_REAL and t_COMPLEX.