PARI's commands

[CRGreathouse]

Originally Posted by science_man_88

Yeah same with comment(s) like they say no passwords in plain text you may get lost trying to read uncommented code, But some random other person could have just as hard of a time until they figure it out.

"No passwords in plain text" has nothing to do with comments in source code.

[science_man_88]

My encode of rle isn't perfect for example:

RLE(hello world) = 1H1e2l1o1w1o1r1l1d

RLE("Hello world") = 1H1e2l1o101w1o1r1l1d

so they don't code out the same and so my decode will likely have to compensate unless my encode is redone.

[science_man_88]

(12:54) gp > checkstring(string) = eval(vector(Vec(Str(string))))
%90 = (string)->eval(vector(Vec(Str(string))))
(12:56) gp > checkstring(string)
  *** vector: gtos expected an integer, got '["s", "t", "r", "i", "n", "g"]'.

catch the error and you complete http://rosettacode.org/wiki/Determin...ing_is_numeric no ?

actually maybe not you'd have to check if it's not a number list, Oh well my mistake again...

[CRGreathouse]

Originally Posted by science_man_88

My encode of rle isn't perfect for example:

RLE(hello world) = 1H1e2l1o1w1o1r1l1d

RLE("Hello world") = 1H1e2l1o101w1o1r1l1d

so they don't code out the same and so my decode will likely have to compensate unless my encode is redone.

Solution: Don't ever, ever, ever pass strings without quoting them. If you do, you're going to end up with nonsense like this where your first example omits the space.

Passing strings without quotes causes serious issues and does not work in all cases. Don't do it. (When you do this, what's actually happening is you're sending monomials which are evaluated to their own names (!), but if a values becomes associated you'll see that instead of what you wanted.)

Your improper use of eval() caused the space to be read as 0 rather than as a space.

[CRGreathouse]

Originally Posted by science_man_88

(12:54) gp > checkstring(string) = eval(vector(Vec(Str(string))))
%90 = (string)->eval(vector(Vec(Str(string))))
(12:56) gp > checkstring(string)
  *** vector: gtos expected an integer, got '["s", "t", "r", "i", "n", "g"]'.

To check the type of a variable, look at type(variable). If it's a string the type will be "t_STR".

type(0) is t_INT
type(1/2) is t_FRAC
type(x^3 + 1) is t_POL
type(x) is t_POL
type(hello) is t_POL
type("hello") is t_STR
and so forth.

[science_man_88]

(13:18) gp > for(x=1,10,print1(x);if(x!=10,print1(",")))
1,2,3,4,5,6,7,8,9,10
(13:18) gp > for(x=1,10,print1(x);if(x==10,break());print1(","))
1,2,3,4,5,6,7,8,9,10
(13:19) gp > for(x=1,9,print1(x);print1(","));print(10)
1,2,3,4,5,6,7,8,9,10
(13:20) gp > for(x=1,9,print1(x","));print(10)
1,2,3,4,5,6,7,8,9,10

not sure which implementation is best for http://rosettacode.org/wiki/Loops/N_plus_one_half lol

[science_man_88]

http://rosettacode.org/wiki/Pattern_matching

right up my alley just not sure what i want to do for it.

[CRGreathouse]

Originally Posted by science_man_88

(13:18) gp > for(x=1,10,print1(x);if(x!=10,print1(",")))
1,2,3,4,5,6,7,8,9,10
(13:18) gp > for(x=1,10,print1(x);if(x==10,break());print1(","))
1,2,3,4,5,6,7,8,9,10
(13:19) gp > for(x=1,9,print1(x);print1(","));print(10)
1,2,3,4,5,6,7,8,9,10
(13:20) gp > for(x=1,9,print1(x","));print(10)
1,2,3,4,5,6,7,8,9,10

not sure which implementation is best for http://rosettacode.org/wiki/Loops/N_plus_one_half lol

I've given some thought to that myself. I think to go with the spirit of the problem a while(1, ...) loop might be best.

[science_man_88]

Originally Posted by CRGreathouse

I've given some thought to that myself. I think to go with the spirit of the problem a while(1, ...) loop might be best.

unless a while has a otherwise do this part it wouldn't all be in the loop and:

Quite often one needs loops which, in the last iteration, execute only part of the loop body. The goal of this task is to demonstrate the best way to do this.
Write a loop which writes the comma-separated list

suggest it should be part of the loop which knocks out all but the first 2 in my group, as well as possibly a while, or do until.

never mind dah if statements lol.

[CRGreathouse]

I can't quite follow you, but

n=0;
while(1,
  print1(n++);
  if(n>9, break);
  print1(", ")
);

does the trick.

[science_man_88]

Originally Posted by CRGreathouse

To check the type of a variable, look at type(variable). If it's a string the type will be "t_STR".

type(0) is t_INT
type(1/2) is t_FRAC
type(x^3 + 1) is t_POL
type(x) is t_POL
type(hello) is t_POL
type("hello") is t_STR
and so forth.

so in other words if(string==type(0) ||string==type(1/2), print("this string is numerical")) would work ? Though I haven't covered floating point types.